Title | 2017 VCAA Further Mathematics Exam 1 Solutions |
---|---|
Course | Discrete Mathematics |
Institution | University of Melbourne |
Pages | 2 |
File Size | 86 KB |
File Type | |
Total Downloads | 69 |
Total Views | 133 |
Practice paper...
http://www.learning-with-meaning.com/ 2017 VCAA Further Mathematics Exam 1 Solutions © itute 2017
SECTION A Data analysis 1
2
3
4
Core 5
6
7
8
9
10
11
12
D B D D B E E D A A D D Recursion and financial modelling 17 18 19 20 21 22 A D C D E A SECTION B Module 1: Matrices 1 2 3 4 5 6 B E C C A D Module 2: Networks and decision mathematics 1 2 3 4 5 6 B C A D C E Module 3: Geometry and measurement 1 2 3 4 5 6 D D B B C B Module 4: Graphs and relations 1 2 3 4 5 6 B C B E D C SECTION A Data analysis
13
14
15
16
B D D
A
23 D
24 B
7 A
8 A
7 D
8 B
7 E
8 A
actual , deseasonalised actual deseasonalised = = 0.625× actual = (1− 0.375)× actual 1.6
D
Q16 1.6 =
A
Recursion and financial modelling Q17
A
Q18
D
Q19
C
Q20
D
Q21
7 C
8 D
Core
680 − 125 ≈ $0.072 4 × 1920
E
Q22
A
28.42 ≈ 0.004 7105. 41 Interest = 7233. 83 × 0. 004 = 28. 94 Principal addition = 7500.00 − 7233.83 = 266.17 Payment = 266.17 − 28.94 = 237.23
D
Q23 Interest rate =
Q1
D
Q2
B
Q3
D
Q4 3 < log10 (area ) < 4 , 10 3 < area < 10 4
D
Q5 30 % of 300 = 90
B
Q6
E
Q7
E
Q8
D
Q9 17.7 − 18.4 = −0.7
A
Q10 z =
22 + 19 + 22 + 43 19 + 22 + 43 + 37 = 26.5 , = 30. 25 4 4 26.5 + 30.25 = 28.375 2
Q15
x − x − 0.3 − 0.02 = −0.8 = 0.4 sx
Q24 N = 120 , I % = 4. 35 , PV = 245 000 , PMT = −1800 , P/Y = 12 , C/Y = 12 , FV = −108 219. 1611 N = 60 , PV = 108 219. 1611, PMT = −2000 , FV = 0 , P/Y = 12, C/Y = 12 , I % ≈ 4.14
B
A
Q11
D
Q12
D
Q13
B
Q14
D
1 2017 Further Maths Trial Exam 1 Solutions
© itute 2017
http://www.learning-with-meaning.com/ SECTION B Module 1: Matrices
Module 3: Geometry and measurement
Q1 θ =
360 = 72 5
D
Q1
B
Q2
E
Q3 ∆ ≠ 0
C
Q4
C
Q5
A
Q4 V =
Q6 aij + bij = (2 i + j) + (i − j ) = 3i
D
Q5
C
Q7 Let Fn+ 1 = Fn = F0 .
Q6 r = 102 − 82 = 6
B
1 0 0 0
sin θ sin 26° = , θ ≈ 50 ° or 130 ° 7 4 The third angle: 180 − 50 − 26 = 104° or 180− 130 − 26 = 24°
E
Q2 XZ =
38.52 + 24.0 2 ≈ 45.4
D
Q3 139 ° E, 25 ° E, 3 °W, 58 ° W
0 0 0 0 0 0 0. 65 1 0 0 0 . 25 0 . 75 0 0 F + B F0 = 0 0 1 0 0. 20 0. 95 0 0 0 0 1 0. 10 0. 05 0. 05 1 1 0 0 0 0. 65 0 0 0 0 . 25 0 . 75 0 0 0 1 0 0 B= F − 0.20 0. 95 0 0 0 0 1 0 0 0 0 0 1 0.10 0. 05 0. 05 1 17 500 Y − 10 000 J .: B = − 1650 A − 5850 D
0.3 0.2 V 40 29 0.2 0.2 W 15 = 13 X Y Z 20 33 X = 1 − 0.3 − 0.2 = 0.5 Y = 1− 0.2 − 0.2 = 0.6 40 X + 15Y + 20Z = 33 , Z = 0.2 0.2 ×40 + 0.2 ×15 + 20W = 13 , W = 0.1
1 π × 52 × 1.8 + π × 52 × 16 ≈ 1304 3
B
Q7
Q8 Shaded area ≈
1 1 × 100 2 sin 60° − × π × 502 ≈ 403 2 2
A
Module 4: Graphs and relations
Q1
B
Q2
C
Q3 100 = k × 5 2 , k = 4
B
Q4 500 + 240 + 200 = 940
E
Q5
D
Q6 2a + 3c = 69.50 and a + 5c = 78.50 .: a =16 and c = 12.5 .: 3 a + 4 c = 98. 00
C
A
Q8
A
Module 2: Networks and decision mathematics
Q7 150 x + 50 ×
Q1
B
Q2
C
Q3
A
Q4 CGJ: 4 + 3 + 5 = 12
D
Q5 Critical path CFHM
C
Q6
E
Q7
D
Q8 The minimum cut is Cut B
B
2017 Further Maths Trial Exam 1 Solutions
B
x = 0.8× 200 + 250 , x = 2. 35 2
Q8
C D
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