AP Physics Momentum Inquiry Virtual Lab Newton\'s 2nd Law of Motion Answer Key PDF

Title AP Physics Momentum Inquiry Virtual Lab Newton\'s 2nd Law of Motion Answer Key
Course Integrated Software Applications I
Institution Del Mar College
Pages 5
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Summary

This is the answer key for the Momentum Inquiry VIrtual Lab. This includes the velocity vs time graph....


Description

AP Momentum Inquiry Virtual Lab

Name _________________________________ Per ____

Open the Virtual Lab: Open a search engine (ex: Google), and type in “physics classroom momentum lab,” then select the first search result. Then, click the top-left corner of the image to start the lab. Note: “Showing work” here means to just write out the red car’s momentum (pR) and the blue car’s momentum (pB) before writing out the total momentum. You don’t need to show how you calculate each car’s momentum.

Part 1: Explosions 1. Initial Conditions: mR = 1 kg

vR = 0 m/s

mB = 1 kg

vB = 0 m/s

Total momentum before explosion (show work):

Total momentum after explosion (show work):

Make a momentum vs time graph below that shows the momenta of each cart before and after the collision. Label each line to represent each cart. Make a velocity vs time graph next to this one.

2. Initial Conditions (both move at +1 m/s before): mR = 2 kg

vR = 1 m/s

Total momentum before explosion (show work):

Total momentum after explosion (show work):

mB = 1 kg

vB = 1 m/s

Make a momentum vs time graph below that shows the momenta of each cart before and after the collision. Label each line to represent each cart. Make a velocity vs time graph next to this one.

Part 2: Inelastic Collisions 1. Initial Conditions (only red car moves before): mR = 3 kg

vR = 4 m/s

mB = 1 kg

vB = 0 m/s

Total momentum before collision (show work):

Total momentum after collision (show work):

Make a momentum vs time graph below that shows the momenta of each cart before and after the collision. Label each line to represent each cart. Make a velocity vs time graph next to this one.

2. Initial Conditions (both move to the right before, red going faster): mR = 1 kg

vR = 10 m/s

mB = 2 kg

vB = 1 m/s

Total momentum before collision (show work):

Total momentum after collision (show work):

Make a momentum vs time graph below that shows the momenta of each cart before and after the collision. Label each line to represent each cart. Make a velocity vs time graph next to this one.

Part 3: Elastic Collisions 1. Initial Conditions (only blue moves before): mR = 2 kg

vR = 0 m/s

mB = 3 kg

vB = -10 m/s

Total momentum before collision (show work):

Total momentum after collision (show work):

Make a momentum vs time graph below that shows the momenta of each cart before and after the collision. Label each line to represent each cart. Make a velocity vs time graph next to this one.

2. Initial Conditions: mR = 2 kg

vR = 10 m/s

mB = 1 kg

vB = -8 m/s

Total momentum before collision (show work):

Total momentum after collision (show work):

Make a momentum vs time graph below that shows the momenta of each cart before and after the collision. Label each line to represent each cart. Make a velocity vs time graph next to this one.

Summary Questions 1. Okay, okay, see a pattern?? Alright, now PREDICT(calculate): What will be the speed of the both cars together after an inelastic collision, if the conditions before the collision are as follows: mR = 3 kg

vR = 6 m/s

mB = 1 kg

vB = 0 m/s

Check your work with the simulation after you make your prediction (with Physics…)

2. What actually was the pattern that you saw? This should have been the case with explosions and both types of collisions.

I noticed that as soon as the 2 cars came in contact or collides, one moves to the left and the other moves to the right... vice versa. 3a. What did you notice about the relative speed of each car (how their speeds compare) and their masses after an explosion? You may want to go back and run a few explosions to double check.

The higher the speed is, the lighter the mass, which results to a higher collision.

3b. How could you explain these relative speeds using Newton’s 2nd Law (ΣF = ma).

Using Newton's 2nd Law of Motion, we can determine the relative speeds by adding the acceleration.

4. Complete the graph by finishing the blue line assuming that both carts have the same mass....


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