Title | Calculus 2 Cheat Sheet |
---|---|
Author | Sam Haines |
Course | Engineering Analysis Ii |
Institution | University of Louisville |
Pages | 12 |
File Size | 1.3 MB |
File Type | |
Total Downloads | 49 |
Total Views | 160 |
Good study tool to use in trying to study for calculus two....
Calculus 2 Cheat Sheet Unit One To get equation for a plane you need: a vector normal (perpendicular) to the plane and a point on the plane, for example if ´ ( A , B , C ) and a point P(x 0 , y 0 , z 0) the equation for the plane is: you have N
A ( x − x 0) +B ( y− y 0 ) +C ( z − z 0 ) =0 To get the parametric equations for a line you need: a vector parallel to the line and a point on the line, for example if you
V ¿∨¿ (a , b , c) and a point ´¿
have
x = x 0 +at , y= y 0 +bt ,
P(x 0 , y 0 , z 0) the equations for the line will be:
z=z 0 +ct
To find the distance between points, lines, and planes: Between points and lines or two parallel lines you use the cross product ( sin θ ) Between points and planes, two parallel planes, lines and planes, or skew lines you use the dot product ( cos θ ), ( A´
compB´ ) Unit Two For a spring/rubber band:
F=kx , where k is the spring constant and x is the displacement b
W =∫ kxdx , where x is a variable and k is the spring constant, you can also solve for k if you have W a
For a gas/piston cylinder: k
PV =C
P2 V 2 − P1 V 1 1−k For leaking bucket/sand: b
∫ f ( x ) dx
, where f(x) is the function of the leaking bucket/sand
a
For conical pile/hemisphere pumping out water: b
b
b
a
a
a
∫ hdF=∫ hwdV =∫ hwAdy , where h is the height (in terms of y), w is the weight-density, and A is the area Using work-kinetic energy relationship:
1 2 2 W =∆ KE= m(v 2 −v 1 ) , make sure the m in the equation is in SLUGS for U.S. units 2 Example for if mass is given in ounces: go from ounces to pounds, divide by 32 (U.S. gravitational constant) and plug into the equation Hydrostatic Force:
HF = pA ,
dF = pdA ,
p= wh ⟹ dF =whdA , where h is depth and w is weight-density, if the object is not at b
an angle it is dF = whLdh ⇒F=∫ whLdh , if it is at an angle it becomes
dF = whLds , and you have to find dh in
a
terms of ds
F=w h´ A , where w is weight-density, ´h is the centroid (which is 1/3h for a triangle), and A is the area
Unit Three To find the inverse of a function, find x in terms of y and then switch the x and y
For example, the inverse of y = x 3
y=x Remember
would be
1 3
−1 −1 f ( f ( x ))=f ( f ( x ) )=x
Derivatives of the inverse trigonometric functions:
d 1 du sin−1 u= dx √ 1−u2 dx
……which is also equal to the negative
d cos−1 u dx 1 du d tan −1 u= ……..which is also equal to the negative dx 1+u2 dx d cot−1 u dx du d 1 −1 sec u= 2 dx |u|√ u −1 dx
……which is also equal to the negative
d csc−1 u dx
Integrals resulting from the derivatives:
∫
du =sin−1 u+C √1−u2
du
∫ 1+u2 =tan−1 u+C ¿ u∨¿ +C ∫ du2 =sec−1 ¿ u √u −1 DON’T FORGET ABSOLUTE VALUE FOR sec-1(x) AND csc-1(x)
Unit Four Derivative of the natural log (ln): Common natural logs:
Integral of the natural log (ln):
u
You can implicitly differentiate using ln is you take the natural log of both sides and solve for Derivative of the natural exponential (e x):
dy dx
Integral of the natural exponential (e x):
∫ eu du=eu + C NOTE:
ln x
e =x
…… and ….. loga u=
Derivative of other exponentials (au):
ln u ln a
Integral of other exponentials (au):
u(x)v(x):
Derivative of
Exponential Applications:
solve for ek and then solve for the needed value
For non-compound interest rates (example: 2%) the rate would equal k For compound interest rates:
where k is the number times compounded per year and t is the number of years
Newtons Law of Cooling: where T is the actual temperature, Ts is the temperature of the surroundings, and T0 is the initial temperature
Unit Five sinh x=
e x −e− x 2
cosh x =
e x + e−x 2
tanh x=
sinh x h
x
−x
e x −e− x = e +e
Hyperbolic identitiy to remember:
cosh2 x− sinh2 x=1
very similar to regular trigonemtric identites just remember that the derivative of cosh(x) is sinh(x)
Catenary (chain):
remember that,
1 =∞ 0
For integrals with one of the limits of integration being
∞ , turn it into a limit
10
Example:
10
∫ x2 dx
would turn into
−∞
lim a →−∞
∫a
x 2 dx
For integrals that violate FTC you use the same idea 5 −¿
a→0
a
5
Example:
∫ dx 2 −3 x
dx
∫ x2
would have a divide by zero so you split it up into
b
b→0
+¿
+ lim ¿ ∫ dx 2 ¿ x
−3
lim ¿ ¿
Unit Six Basic integration techniques:
Forms of substitutions using the unit circle with a and x:
Integration by parts:
Partial Fractions: Method One (equating coefficiants)
Method Two (heaviside method)
Unit Seven Geometric series:
Unit Eight
THESE ARE THE SAME AS FROM UNIT FIVE
For binomial series, use the form
(1 + x )m
Unit Nine...