Chemistry writing Ionic Formulas with Polyatomic Ions PDF

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Ionic Formulas with Polyatomic Ions

Step 1 Write the charges for both elements -

(If the charges are the same, they cancel out and you can write it normally)

Step 2 Rearrange The elements -

Transition Elements with Roman Numerals in Brackets Determine the number of Valence Electrons/Charge

Examples Aluminium Fluoride I Aluminium Sulfate

Al 3+

F1AlF3

I Al+3 I

I Strontium Phosphate I

SO₄²- I

Al2(SO4)3

I

Sr 2-

Tin (IV) Selenide

PO₄³⁻ I Sn4+

Sr3(PO4)2

Se 2-

I Sn2/2 Se4/2 SnSe2

Ammonium Sulfate NH₄⁺ SO₄²-

(NH4)2SO4 Naming Compounds with Polyatomic Ions To name compounds with Polyatomic Ions: Name of the metal Followed by the name of the polyatomic ion (In Lowercase) When finding the chemical formula from the compound name always balance for ionic compounds.

When given the chemical formula and asked to find the compound name Identify the metal and the polyatomic ion and write its name Examples What is the name of the formula: Li3PO4 – We can see the metal Lithium and the Polyatomic ion Phosphate (PO₄³⁻) What is the name of the formula: Ca(OH)2: Ca = Calcium and OH is Hydroxide so the compound name is Calcium Hydroxide What is the compound name of the formula: NH4N03 – Ammonium is NH4 and Nitrate is N03 So, the name of the compound is Ammonium Nitrate.

Naming/Writing Covalent Molecular Compounds -

Compounds formed of two nonmetals are called Covalent or Molecular Compounds. Compounds formed of a metal and a nonmetal are called Ionic Compounds

For the First Element, start with the element name. For the second element, start with the -ide name. Use prefixes to show how many atoms of each type there are. Do not use “Mono (1) “ on the first element. If you have “ao” or “oo”, turn it into “o”

N2O3 Di Nitrogen CF4

Tri Oxide

Carbon Tetra Fluoride

Cl2O7 Di Chlorine Heptoxide

I P4S10

Tetra Phosphorus Deca Sulfide

I PCL5 Phosphorus

Penta Chloride

I P4O6 Tetra Phosphorus

Hexoxide

CO Carbon Monoxide

Naming Binary Ionic Compounds with Transition Metals & Polyatomic Ions

FeCl2 -> Iron (II) Chloride

FeS  Iron(II) Sulfide Because Sulfide has a -2 charge Iron needs +2 to balance out the charges.

Oxidation state of Fe2S3

2Fe+3s=0 2Fe + 3(-2) = 0 2Fe – 6 = 0 +6 +6 2Fe = 6 2Fe/2 and 6/2 - Fe = +3 Iron (III) Sulfide) Naming Binary Ionic Compounds with Transition Metals & Polyatomic Ions

PbO2 = Pb + 2O = 0 Pb + 2(-2) = 0 Pb -4 = 0 +4 +4

Pb = +4

Sn3(PO4)4 = Tin (IV) Phosphate

Therefore the name of this ionic compound is Lead (IV) Oxide...