Title | CHM 1210 Opotowsky Lecture Videos UNIT Dimensional Analysis |
---|---|
Author | Holly Marie Bernardino |
Course | General Chemistry |
Institution | California State Polytechnic University Pomona |
Pages | 1 |
File Size | 50.4 KB |
File Type | |
Total Downloads | 32 |
Total Views | 146 |
Taught by Joelle Opotowsky online through Blackboard...
CHM 1210 OPOTOWSKY LECTURE VIDEOS
UNIT DIMENSIONAL ANALYSIS Calculate the # of moles in 2.00g Aluminum Foil 1. Determine sig figs: 3 sig figs due to the trailing zeroes 2. Set up presentation line a. What do they want? What is the goal of the problem? b. Most important to set up a line in order to communicate the problem 3. Include number, units, substance or else NO POINTS WILL BE GIVEN >:c Givens: 2.00g Al, g, moles moles: 2. 00𝑔 𝐴𝑙 ×
1 𝑚𝑜𝑙𝑒 𝐴𝑙 = 26.98𝑔 𝐴𝑙
0.074178m → 0.0741 mole Al
Calculate the number of moles of H2O produced when 2.00g oxygen gas reacts with excess hydrogen gas. -Opotowsky assumes we know her diatomic molecules H2(g): Hydrogen gas, O2(g): Oxygen gas ● Allowed to use coefficient space to balance the equations. ● Ask yourself what are the units for the balanced equations? ● Understand the chemical equations as a recipe being done. _ H2(g) + _ O2(g) → _ H2O (l) Mole mole mole 2.00g ? moles ? moles H2O= 2. 00𝑔 𝑂2 ×
---> 2 H2(g) + 1 O2(g) → 2 H2O (l) (complete equation)
1 𝑚𝑜𝑙𝑒 𝑂2 32.00𝑔 𝑂2
×
2 𝑚𝑜𝑙𝑒 𝐻2𝑂 1 𝑚𝑜𝑙𝑒 𝑂2
= 0.125 mole → 0.125 mol H2O
Things that we knew in order to set up the equation: 1) 2.00 g O2 2) g→ moles (O2: 2 x 16= 3)
1 𝑚𝑜𝑙𝑒 𝑂2 2 𝑚𝑜𝑙𝑒 𝐻2𝑂
32.00𝑔 1 𝑚𝑜𝑙𝑒 𝑂2
)
(For everyone one mole of oxygen, this would produce 2 moles water)...