EGR 107 ME HW 3 Threaded Fastener solution PDF

Preview

Summary

Homework solution...

Description

EGR 107 Winter 2015 Mechanical Engineering Homework 3 Print this page, solve directly on this paper. 1. a) Determine how deep you would have to drill a hole if you needed to use a plug tap to form 15 complete threads for a .875 – 16 thread. Explain your decision. Solution: length of each thread=1/16 inch Length of 15 thread= 15* 1/16=15/16 inch Assume this plug tap has 4 threads of chamfer, then length of chamfer =1/16*4=1/4 inch One additional thread= 1/16 inch So the minimum depth of hole= 15/16 +1/4 +1/16= 1.25 inch b) How deep would the hole need to be for a bottoming tap? Explain your decision. Solution: length of each thread=1/16 inch Length of 15 thread= 15* 1/16=15/16 inch Assume this bottoming tap has 1 threads of chamfer, then length of chamfer =1/16*1=1/16 inch One additional thread= 1/16 inch So the minimum depth of hole= 15/16 +1/16 +1/16= 1.1.0625 inch 2. Describe the thread specification of ¾-16 UNF -3A X10 Solution: ¾ is major diameter 16 threads per inch UNF: Unified fine thread 3: Class 3 fit A: External thread 10: length of thread is 10 inch 3. Describe the thread specification of M25X3 X60 Solution: M: Metric system 25: major diameter is 25 mm 3: pitch is 3 mm 60: total length of thread is 60 mm Solution: length of each thread=1/16 inch Length of 15 thread= 15* 1/16=15/16 inch Assume this plug tap has 4 threads of chamfer, then length of chamfer =1/16*4=1/4 inch One additional thread= 1/16 inch So the minimum depth of hole= 15/16 +1/4 +1/16= 1.25 inch...