Title | Electrostatics and Magnetostatics Cheat Sheet Formulas |
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Author | Sanzhar Askaruly |
Pages | 5 |
File Size | 798.1 KB |
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EEC 130A : Formula Sheet Up to Midterm 2 Updated: Mar. 7th 2012 1 Electrostatics Z 0 1 ˆ 0 ρl dl E= R Force on a point charge q inside a static elec- 4π l0 R02 tric field Electric field produced by an infinite sheet F = qE of charge Gauss’s law ρs E = zˆ I 2 D · dS = Q or ∇·D=ρ S Electric field pr...
EEC 130A : Formula Sheet Up to Midterm 2 Updated: Mar. 7th 2012
1
Electrostatics
1 E= 4πǫ
Force on a point charge q inside a static electric field F = qE
Z
ˆ ′ ρl dl R R′2 l′
Electric field produced by an infinite sheet of charge
Gauss’s law E = zˆ I
S
D · dS = Q
or
∇·D=ρ
∇×E=0
or
C
E=
E · dl = 0
q (R − Ri ) E= 4πǫ0 |R − Ri |3
E = −∇V
Electric field produced by a volume charge distribution Z
ˆ ′ ρv dV R R′2 V′
1 E= 4πǫ
ˆ ′ ρs ds R R′2 S′
or
V2 − V1 = −
Z
P2 P1
E · dl
Electric potential due to a point charge (with infinity chosen as the reference)
′
V =
Electric field produced by a surface charge distribution Z
Dr ρl D = ˆr = ˆr ǫ ǫ 2πǫr
Electric field - scalar potential relationship
Electric field produced by a point charge q in free space
1 E= 4πǫ
ρs 2ǫ
Electric field produced by an infinite line of charge
Electrostatic fields are conservative I
′
q 4πǫ0 |R − Ri |
Poisson’s equation ∇2 V = −
′
ρ ǫ
Constitutive relationship in dielectric materials D = ǫ0 E + P
Electric field produced by a line charge distribution 1
where P is the polarization.
Gauss’s law for magnetism I B · dS = 0 ∇ · B = 0 or
P = ǫ0 χe E
S
Electrostatic energy density Ampere’s law
1 we = ǫE 2 2
∇×H=J
Boundary conditions E1t = E2t
or
C
H · dl = I
Magnetic flux density — magnetic vector potential relationship
ˆ × (E1 − E2 ) = 0 n
or
I
B=∇×A D1n − D2n = ρs
or
ˆ · (D1 − D2 ) = ρs n
Magnetic potential produced by a current distribution
Ohm’s law J = σE
µ A= 4π
Conductivity σ = ρv µ
Z
V′
J dV ′ R′
Vector Poisson’s Equation
where µ stands for charge mobility. ∇2 A = −µJ
Joule’s law P =
2
Z
Magnetic field intensity produced by an infinitesimally small current element (BiotSavart law)
E · J dv
Magnetostatics dH =
ˆ I dl × R 4π R2
Force on a moving charge q inside a magnetic field F = qu × B
Magnetic field produced by an infinitely long wire of current in the z-direction
Force on an infinitesimally small current element Idl inside a magnetic field
ˆ I H=φ 2πr
dFm = Idl × B
Magnetic field produced by a circular loop of current in the φ-direction
Torque on a N -turn loop carrying current I inside a uniform magnetic field
H = zˆ
T=m×B
Ia2 2(a2 + z 2 )3/2
Constitutive relationship in magnetic materials
ˆ N IA. where m = n 2
4
Constants
B = µ0 H + µ0 M Free space permittivity Magnetization ǫ0 = 8.85 × 10−12 M = χm H
Free space permeability
Boundary conditions
B1n = B2n
or
H1t − H2t = Js
or
µ0 = 4π × 10−7 ˆ · (B1 − B2 ) = 0 n
ˆ × (H1 − H2 ) = Js n
Magnetostatic energy density 1 wm = µH 2 2
3
Useful Integrals √ dx = ln(x + x2 + c2 ) x2 + c2 Z 1 x dx = tan−1 2 2 x +c c c
Z
√
Z
dx
= 2 3/2
F/m
1 x √ 2 c x2 + c2
x2 + c Z √ x dx √ = x2 + c2 x2 + c2 Z 1 x dx = ln (x2 + c2 ) x2 + c2 2 Z x dx 1 = −√ 2 2 3/2 2 (x + c ) x + c2 Z 1 dx =− 2 (a + bx) b(a + bx)
3
H/m...