Title | Formula sheet |
---|---|
Author | Alexa Lie |
Course | Quantitative Methods 1 |
Institution | University of Melbourne |
Pages | 3 |
File Size | 145 KB |
File Type | |
Total Downloads | 102 |
Total Views | 152 |
Formula...
THE UNIVERSITY OF MELBOURNE Department of Economics ECON10005 QUANTITATIVE METHODS 1
FINAL EXAM FORMULA SHEET
Data Analysis x¯ =
Coefficient of variation
SAMPLE VARIANCE
sample Mean n
n
1 X xi n
s2 =
1 1 X (xi − x¯)2 = n−1 n−1 i=1
i=1
n
cov(X, Y ) = sxy COVariance
1X |xi − x¯| MAD = n i=1 Population: 1/n
i=1
n X
1 1 X (xi − x¯)(yi − y¯) = = n−1 n−1 i=1 n
n X
i=1
X pˆ = n
xi2 − n x¯2
!
cv = !
xi yi − n x¯ y¯
p Lp = (n + 1) 100
Proportion
r=
s x¯
sxy sx sy
Sample coefficient of correlation
percentile
Probability Theory Conditional probability
P [A|B] = Mean
Multiplication rule
P [A ∩ B] P [B]
E(X) = µ =
k X i=1
xi ·p(xi )
COV (X, Y ) = σxy =
n X m X i=1 j=1
If Y = a + b X, If X ∼ b(n, p): If Y = a + b X, If X ∼ N (µ, σ 2 ),
addition rule
P [A∩B] = P [A|B]·P [B]
2
V AR(X) = σ =
P [A∪B] = P [A]+P [B]−P [A∩B] k X i=1
(xi − µ)2 ·p(xi ) =
(xi − µx ) (yj −µy ) p(xi , yj ) =
E(Y ) = a + b E(X)
and
n X m X i=1 j=1
k X i=1
x2i ·p(xi ) − µ2
xi ·yj ·p(xi , yj ) −µx · µy
V AR(Y ) = b2 V AR(X )
binomial probability n! x n−x
P (X = x) = p(x) = E(Y ) = a + b E(X)
x!(n − x)!
and
p (1 − p)
n = number of trials; x = number of successes
V AR(Y ) = b2 V AR(X )
Z = (X − µ)/σ ∼ N (0, 1)
Continuous Distribution Densities Uniform: f (x) =
1 for a ≤ x ≤ b b−a
−(x−µ)2 1 Normal: f (x) = √ e 2σ2 −∞ < x < ∞ σ 2π
1
Sampling Distributions
For samples of size n:
¯ −µ X √ ∼ tn−1 s/ n
(n − 1)s2 2 ∼ χn−1 σ2
p q pˆ ≃ N p, n
sampling distribution of proportion
Interval Estimators - Single Populations Estimator of mean when variance is known
¯ ± zα/2 √σ X n
¯ ± tα/2,n−1 √s X n
(n − 1)s2 (n − 1)s2 , 2 2 χα/2 χ1−α/2
!
n=
Tests - Single Populations ¯ −µ X √ σ/ n
t=
Estimating mean when variance is known
z
α/2
B
pˆ ± zα/2
r
n=
σ 2
sample size required to estimate mean with variance known
CI for chi squared
z=
Estimator of mean when variance is unknown
X¯ − µ √ s/ n
Estimator of proportion
√ 2 zα/2 pˆ qˆ B sample size required to estimate p
pˆ − p z=p pq/n
Estimating mean when variance is unknown
pˆ qˆ n
χ2 =
(n − 1)s2 σ2
Chi squared distribution
standardizing sample proportion
Interval Estimators - Two Populations mean for match pair
X¯D ±tα/2,nD −1
sD √ nD
ci for match pair
nD nD 1 X 1 X ¯ xDi (x1i −x2i ) = XD = nD nD i=1
i=1
¯ 1 − X¯2 ± zα/2 X
s
sD =
σ12 σ22 + n2 n1
sP
nD i=1 (xDi
¯ D )2 −X nD − 1
sd for match pair
pˆ1 − pˆ2 ± zα/2
r
pˆ1qˆ1 pˆ2qˆ2 + n2 n1
ci for independent when variance is known
Tests - Two Populations match pair if variance unknown
t=
¯D − µD X √ sD / nD
z=
¯ 2 ) − (µ1 − µ2 ) (X¯1 − X independent if q 2 σ22 σ1 variance known +n n1 and unequal 2
z= p1-p2 = D
(ˆ p1 − pˆ2 ) − (p1 − p2 ) q pˆ1 qˆ1 + pˆ2nqˆ22 n1 pˆ1 =
x1 n1
pˆ2 =
z=
x2 n2
2
(ˆ p1 − pˆ2 ) − (p1 − p2 ) r p1-p2 pˆ qˆ n11 + n12
pˆ =
x1 + x2 n1 + n2
= 0
Simple Regression
βˆ0 = y¯ − βˆ1 x¯ s ˆβ0 = sε
sP
n i=1
Pn ¯)(yi − y¯) sxy i=1 (xi − x Pn = 2 βˆ1 = ¯)2 sx i=1 (xi − x
xi2/n (n − 1)sx2
s βˆ1 = p
sε
(n −
1)sx2
sε =
r
SSE n−2
test statistic
βˆj ± tα/2,n−2 · sβˆj
t=
βˆj − βj s βˆj
R2 =
2 sxy SSR SSE = 2 2 = 1− SST sx sy SST
n-2 d. f.
n X (yi −¯ y )2 SST = i=1
SSR =
n X i=1
(ˆ yi −¯ y)
2
n n 2 X X sxy 2 2 2 e i = (n−1) sy − 2 (yi −ˆ yi ) = SSE = sx i=1 i=1
3...