Key Equations ch4and5 PDF

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Chapter 4

R =  F = F1 + F2 + F3 +

F =0  F = ma F

x

= max

F

y

= may

w = mg

(4.1)

(body in equilibrium)

(4.3)

(Newton’s second law of motion)

F

(4.6)

= maz (Newton’s second law of motion)

z

(4.7)

(magnitude of the weight of a body of mass m)

FA on B = − FB on A

(4.8)

(Newton’s third law of motion)

(4.10)

Chapter 5

F = 0  Fx = 0

(particle in equilibrium, vector form)

(5.1)

 Fy = 0 (particle in equilibrium, component form)

 F = ma  F = ma F x

x

y

f k =  kn

(Newton’s second law, vector form) = may (Newton's second law, component form)

(5.3)

(magnitude of kinetic friction force)

f s  ( f s) max =  sn

arad

(5.2)

=

2 R

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(magnitude of static friction force)

(uniform circular motion)

(5.4)

(5.13)

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arad =

4 2R (uniform circular motion) T2

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(5.15)

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