Lab 3-Density-Lab Report(2)-1 PDF

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REPORT SHEET

Density and Specific Gravity

LAB

3

A. Density of Liquids A.1 Density of Water 1. Volume (mL)

20.2 mL

2. Mass of beaker

150.802 g

3. Mass of beaker + liquid

171.223 g

4. Mass of liquid 171.223g – 150.802 g = Density D = 20.421g = 5. 20.2mL

*20.421g *1.01g/mL

A.2 Density of an Unknown Liquid 1. Type of liquid sample Volume of liquid

Salt water 20.3 mL

2. Mass of beaker

150.802 g

3. Mass of beaker + liquid

172.047 g

4. Mass of liquid 172.047g – 150.802 g = 5. Density D = 21.245g =

*21.245g *1.05g/mL

20.3 mL

B. Specific Gravity

1. Specific gravity of water

1.01

2. Specific gravity of liquid sample

1.05

3. Specific gravity of water using a hydrometer

1.00

4. Specific gravity of liquid using a hydrometer

1.04

How do the calculated specific gravity of water and the liquid sample (1, 2) compare to the hydrometer readings (3, 4) for water and the liquid sample? The calculated values were both 0.01 units higher than the hydrometer readings.

C. Density of Solids

1. Mass of the solid

24.641 g

2. Initial water level

19.9 mL

3. Final water level with solid

23.1 mL

4. Volume of solid (3  2)

*3.2mL

5. Density of the solid D=24.641g =

*7.7g/mL

3.2mL 6. Type of metal

*bronze

D. Graphing Mass and Volume

1. Initial volume of water

22.7 mL

2. Initial mass of cylinder + water

43.850 g

3. Type of metal

Brass

Total Mass of Cylinder, Water, and Metal Pieces

Total Volume of Water and Metal Pieces

4.

52.271

g

4.

23.7

mL

5.

63.363

g

5.

25.0

mL

6.

72.999

g

6.

25.9

mL

7.

89.951

g

7.

28.2

mL

Calculations

8. Mass of Metal Pieces

9. Volume of Metal Pieces 10. Density (8/9)

(4–2)

*8.4210

g

(4–1)

*1

mL

*8.421

g/mL

(5–2)

*19.513

g

(5–1)

*2.3

mL

*8.483

g/mL

(6–2)

*29.149

g

(6–1)

*3.2

mL

*9.109

g/mL

(7–2)

*46.101

g

(7–1)

*5.5

mL

*8.382

g/mL

11. Drawing the Graph

12.

*Calculate the slope of the line which is equal to the density of the metal:

Slope of line = (y2-y2) / (x2-x1) = (46.101 – 8.421) / (5.5 – 1) = (37.68) / (4.5) = 8.373 g/mL Questions and Problems Q1 A metal object has a mass of 8.37 g. When it was placed in a graduated cylinder containing 20.0 mL of water, the water level rose to 23.1 mL. What is the density and identity of the metal? (see Table 3.1) Volume of metal = 23.1mL – 20.0mL = 3.1mL Density of the metal D=M = 8.37g = 2.7g/mL V 3.1mL According to table 3.1 above, the metal is Aluminum Q2 What is the mass of a solution that has a density of 0.775 g/mL and a volume of 50.0 mL? Mass = Density x Volume M= 0.775 g/mL x 50.0mL M = 38.8 g The mass of the solution is 38.8g

Q4 A pump delivers the following volume of a solution over 4 h. Volume (mL)

Time (h)

0

0

50

1.0

100

2.0

125

2.5

150

3.0

200

4.0

Prepare a graph to represent the data....