Lab Report 9 Emily Travis PDF

Title Lab Report 9 Emily Travis
Author Emily Travis
Course Physics
Institution The University of Tennessee
Pages 1
File Size 66.9 KB
File Type PDF
Total Downloads 21
Total Views 115

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lab report 9 ...


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Name: Emily Travis E-mail address: [email protected] Laboratory 9 Report The purpose of this lab is to study diffraction patterns caused by slits and lasers and determine if the slit width or distance can be verified using various formulas. The diameter of a hair is also measured and determined using the same simulation. Part 1 Verify the slit width w. Explain which measurement you made, show your calculation and your result for the slit width. There are several measurements you can make. Pick one. To verify the slit width, I considered the formula w sinӨ=mλ but because m=1 because we are just trying to verify w, the formula becomes w=λ/sinӨ . We are given the wavelength and the angle between maxima is estimated to be 0.3165 radians which, when plugged in, verifies that w equals 20 µm. Determine the slit spacing d. Explain which measurement you made, show your calculation and your result for the slit spacing. There are several measurements you can make. Pick one. (Hint) To determine split spacing d using the 2 slit piece, the formula d sinӨ =m λ rearranges to be d =mλ/sinӨ because L=1m in this simulation. Substituting 633nm for wavelength and 0.716 for sinӨ, d=0.05m As you observe the pattern, does it differ from that of the double slit for the same slide to screen distance L? If yes, what is different? (Zoom in to get a better view.) Yes the pattern is different. The amount of spaces and dark areas seems to increase when looking through the 4 slit piece. Part 2 Observe the diffraction pattern on the screen. Determine the diameter w of the hair. Explain which measurement you made, show your calculation and your result for the diameter of the hair. To calculate the diameter of the hair, I used Diameter = λmd/sinӨ. To determine sin I measured from the central bright maxima to the 1st order maxima on the left. That value was 6.25. Plugging in values → diameter = (.633)(.00625)/sin(0.12499) so the diameter of the hair is 0.003mm...


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