Laboratory Exercise 3 - MATH PDF

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De La Salle University – Dasmariñas COLLEGE OF SCIENCE AND COMPUTER STUDIES MATHEMATICS AND STATISTICS DEPARTMENT City of Dasmariñas, Cavite LABORATORY ACTIVITY #3 Hypothesis Testing Score:

OBJECTIVES: 1. Compute and interpret the point and interval estimates of parameters. 2. Compute and interpret the length of the interval formed. 3. Solve each problem using Microsoft Excel. TASKS, RESULTS, INTERPRETATION The HR department of ABC Manufacturing Industry studied the Job Performance and Job satisfaction of 120 employees. The information such as gender and job status were collected. Given below are the hypotheses of the study 1. There is no significant difference among the level of job satisfaction of the employees when they are grouped according to 1.1 gender 1.2 job status 2. There is no significant difference among the level of job performance of the employees when they are grouped according to 2.1 educational attainment 2.2 length of service Task: 1. There is no significant difference among the level of job satisfaction of the employees when they are grouped according to 1.1 gender 1.2 job status Output: 1.

Hypothesis

Ho: Gender and Job Status variables are dependent. Ha: The variables Gender and Job Status are independent. 2. Significance Level and Test Statistic α = 0.05 The test corresponds to Test for equality of variances.

3. Computation and Solution

Results ANOVA ANOVA - Job Performance Sum of Squares df Mean Square

Cases Gender

1.060

1

1.060

Job Status

1.731

1

1.731

Gender ✻ Job Status Residuals

1.215

1

1.215

30.927

116

0.267

F

p

3.977 0.048 6.493 0.012 4.557 0.035

Descriptives Descriptives - Job Performance Gender Job Status Mean SD Female Outsourced Regular Male Outsourced Regular

N

3.905 0.425 26 3.945 0.529 34 3.513 0.570 34 3.958 0.509 26

Assumption Checks Test for Equality of

F

df1

df2

p

1.840

3.000

116.000

0.144

Variances (Levene's)

Post Hoc Tests Standard Post Hoc Comparisons - Gender ✻ Job Status p Mean Difference SE

t tukey

Female, Outsourced Male, Outsourced

0.393

Female, Regular

-0.039

Male, Regular

-0.053

Male, Outsourced Female, Regular

-0.432

Male, Regular

-0.445

Male, Regular

-0.013

Female, Regular

0.135 0.022 0.135 0.991 0.143 0.983 0.125 0.004 0.135 0.007 0.135 1.000

2.920 -0.292 -0.368 -3.450 -3.311 -0.099

Interpretation: 4. Decision and Conclusion Therefore, there is no sample evidence to reject the null hypothesis because the p-value of the test is 0.144, which is greater than the significant level of 0.05. In addition, the variables are said to be independent....