Mechanics of Deformable Bodies - Part1 PDF

Title Mechanics of Deformable Bodies - Part1
Author Alberto Bautista
Course Deformable Bodies
Institution Izmir Kâtip Celebi University
Pages 60
File Size 3.7 MB
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MECHANICS OF DEFORMABLE BODIES « Summary of Notes »

MECHANICS OF DEFORMABLE BODIES « CHAPTER 1: STRESS, STRAIN AND MECHANICAL PROP. OF MATERIALS »

MECHANICS OF DEFORMABLE BODIES

MECHANICS OF DEFORMABLE BODIES

MECHANICS OF DEFORMABLE BODIES 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11.

Stress, Strain and Mechanical Prop. of Materials, Axial Load, Torsion, Bending, Transverse Shear, Combined Loadings, Stress and Strain Transformation Design of Beams and Shafts Deflection of Beams and Shafts Buckling of Columns Energy Methods

WHAT IS MECHANICS OF DEFORMABLE BODIES?

• Mechanics of materials is a study of the relationship between the external loads applied to a body and the stress and strain caused by the internal loads within the body.

EQUILIBRIUM OF A DEFORMABLE BODY (REMINDER) • External Loads: – – – –

• Support Reactions:

INTERNAL RESULTANT LOADINGS (REMINDER)

• It will be shown in later that point O is most often chosen at the centroid of the sectioned area, and so we will always choose this location for O, unless otherwise stated. • Also, if a member is long and slender, as in the case of a rod or beam, the section to be considered is generally taken perpendicular to the longitudinal axis of the member. • This section is referred to as the cross section

INTERNAL RESULTANT LOADINGS (REMINDER) • The method of sections is used to determine the internal resultant loadings acting on the surface of the sectioned body. • In general, these resultants consist of a normal force, shear force, torsional moment, and bending moment.

Right-hand rule

COPLANAR LOADINGS (REMINDER)

• General Procedure: • Support Reactions:

N, V, T and M Diagrams

– Determine the reactions acting on the chosen segment

• Free-Body Diagram: – Draw a free-body diagram of one of the “cut” segments. N, V, M &T. – These resultants are normally placed at the point representing the geometric center or centroid of the sectioned area. – Coplanar system of forces, only N, V & M act at the centroid .

• Equations of Equilibrium: – If the solution of the equilibrium equations yields a negative value for a resultant, the directional sense of the resultant is opposite to that shown on the free-body diagram.

STRESS • Stress in structural members

STRESS

• Stress describes the intensity of the internal force acting on a specific plane (area) passing through a point.

STRESS • NORMAL STRESS: The intensity of the force acting normal to ∆A is defined as Normal Stress σ (sigma). – If normal force pulls the area  Tensile Stress – If normal force push the area  Compressive Stress

• SHEAR STRESS: The intensity of the force acting tangent to ∆A is defined as Shear Stress τ (tau). – Note that in this subscript notation z specifies the orientation of the area. x and y indicate the axes along which each shear stress acts.

STRESS • General State of Stress:

• Units: Since stress represents a force per unit area, the magnitudes of both normal and shear stress are specified in basic units as N/m2. • Also; Pascal: 1Pa= 1 N/m2, Megapascal: 1MPa= 1 N/mm2= 1 MN/m2.

AVERAGE NORMAL STRESS IN AN AXIALLY LOADED BAR • Average stress distribution acting on the cross-sectional area of an axially loaded bar is focused. • This bar is prismatic, all cross sections are the same throughout its length. • P is applied to the bar through the centroid of its cross-sectional area, then the bar will deform uniformly throughout the central region of its length, provided the material of the bar is both homogeneous and isotropic.

 Homogeneous material has the same physical and mechanical properties throughout its volume  Isotropic material has these same properties in all directions.

AVERAGE NORMAL STRESS IN AN AXIALLY LOADED BAR

• Due to the uniform deformation of the material, it is necessary that the cross section be subjected to a constant normal stress distribution.

AVERAGE NORMAL STRESS IN AN AXIALLY LOADED BAR • Two normal stress components on the element must be equal in magnitude but opposite in direction. • This is referred to as uniaxial stress.

MAXIMUM AVERAGE NORMAL STRESS • In our analysis both the internal force P and the cross-sectional area A were constant along the longitudinal axis of the bar, and as a result the normal stress σ= P/A is also constant throughout the bar’s length. • Several external loads along its axis, or a change in its cross-sectional area may occur. As a result, the normal stress within the bar could be different from one section to the next, and, if the maximum average normal stress is to be determined, then it becomes important to find the location where the stress is maximum. • To do this; – Determine the internal force P at various sections along the bar. – It may be helpful to show this variation by drawing an axial or normal force diagram. – P will be positive if it causes tension in the member, and negative if it causes compression.

NUMERICAL EXAMPLE #1 (1/1): • Determine the maximum average normal stress in the bar when it is subjected to the loading shown. (Thickness: 10 mm.)

NUMERICAL EXAMPLE #2 (1/2): • Member AC is subjected to a vertical force of 3 kN. • Determine the position x of this force so that the average compressive stress at the smooth support C is equal to the average tensile stress in the tie rod AB. The rod has a cross-sectional area of 400 mm2 and the contact area at C is 650 mm2.

NUMERICAL EXAMPLE #2 (2/2):

AVERAGE SHEAR STRESS

• The loading discussed here is an example of simple or direct shear, since the shear is caused by the direct action of the applied load F. • This type of shear often occurs in various types of simple connections that use bolts, pins, welding material, etc.

AVERAGE SHEAR STRESS

• All four shear stresses must have equal magnitude and be directed either toward or away from each other at opposite edges of the element.

AVERAGE SHEAR STRESS

NUMERICAL EXAMPLE #1 (1/2): • The inclined member is subjected to a compressive force of 600 N. Determine the average compressive stress along the smooth areas of contact defined by AB and BC, and the average shear stress along the horizontal plane defined by DB.

NUMERICAL EXAMPLE #1 (2/2):

• Changing the orientation of the stress element produces different stress components for the same state of stress.

ALLOWABLE STRESS DESIGN • To ensure the safety of a structural member, it is necessary to restrict the applied load to one that is less than the load the member (or element) can fully support.

• In any of these equations, the factor of safety must be greater than 1 in order to avoid the potential for failure. • A design that is based on an allowable stress limit is called Allowable Stress Design (ASD).

LIMIT STATE DESIGN • This method of design is called Limit State Design (LSD), or more specifically, in the United States it is called Load and Resistance Factor Design (LRFD). • Load Factors: Various types of loads R can act on a structure or structural member, and each is multiplied by a load factor γ (gamma) that accounts for its variability. • Resistance Factors: Resistance factors Ø (phi) are determined from the probability of material failure as it relates to the material’s quality and the consistency of its strength.

STRAIN • This specimen exhibits noticeable strain before it fractured. • Measurement of this strain is necessary so that the stress in the material can be determined in cases of complicated loadings.

DEFORMATION • Deformation: • Whenever a force is applied to a body, it will tend to change the body’s shape and size. • These changes are referred to as deformation, and they may be either highly visible or practically unnoticeable.

NORMAL STRAIN • In order to describe the deformation of a body by changes in length of line segments and the changes in the angles between them, we will develop the concept of strain.

• NORMAL STRAIN: • Normal strain is the change in length of a line per unit length, then we will not have to specify the actual length of any particular line segment.

• Normal strain is a dimensionless quantity, since it is a ratio of two lengths.

SHEAR STRAIN • SHEAR STRAIN: • Deformations not only cause line segments to elongate or contract, but they also cause them to change direction. • If we select two line segments that are originally perpendicular to one another, then the change in angle that occurs between them is referred to as Shear Strain. • This angle is denoted by γ (gamma) and is always measured in radians (rad), which are dimensionless.

θ‘ < π/2 shear strain is positive. θ‘ > π/2 shear strain is negative.

CARTESIAN STRAIN COMPONENTS • Cartesian Strain Components: These components can be used to describe the deformation of the body.

• Approximate lengths of the three sides of the parallelepiped are; • The approximate angles between these sides are; • Notice that the normal strains cause a change in volume of the element, whereas the shear strains cause a change in its shape. • Both of these effects occur simultaneously during the deformation.

MECHANICAL PROPERTIES OF MATERIALS • The strength of a material depends on its ability to sustain a load without undue deformation or failure. • This property is inherent in the material itself and must be determined by experiment. • One of the most important tests to perform in this regard is the tension or compression test. • Although several important mechanical properties of a material can be determined from this test, it is used primarily to determine the relationship between the average normal stress and average normal strain in many engineering materials such as metals, ceramics, polymers, and composites.

MECHANICAL PROPERTIES OF MATERIALS

• Response of a material to applied forces depends on the type and nature of the bond and the structural arrangement of atoms, molecules or ions. • Basic deformation types for load carrying materials are: – 1. Elastic deformation (deformations are instantaneously recoverable) – 2. Plastic deformation (non-recoverable) – 3. Viscous deformation (time-dependent deformation)

MECHANICAL PROPERTIES OF MATERIALS • Elastic Behavior: • Return to the their original shape when the applied load is removed.

MECHANICAL PROPERTIES OF MATERIALS • Plastic Behavior: • No deformation is observed up to a certain limit. • Once the load passes this limit, permanent deformations are observed.

MECHANICAL PROPERTIES OF MATERIALS Elastoplastic Plastic Behavior:

MECHANICAL PROPERTIES OF MATERIALS • Viscoelastic (and Viscoplastic) Behavior: • Viscoelastic behavior  Return to the their original shape when the applied load is removed.

MECHANICAL PROPERTIES OF MATERIALS

a. Ideal Linear Elastic b. Ideal Elastoplastic

c. Ideal Linear Plastic d. Ideal Elastoplactic (with hardening)

THE STRESS–STRAIN DIAGRAM • A plot of the results produces a curve called the stress–strain diagram.

THE STRESS–STRAIN DIAGRAM • Conventional Stress–Strain Diagram: • We can determine the Nominal or Engineering Stress by dividing the applied load P by the specimen’s original cross-sectional area A0.

• Likewise, the Nominal or Engineering Strain is found directly from the strain gauge reading, or by dividing the change in the specimen’s gauge length δ, by the specimen’s original gauge length L0.

• σ and ε are plotted so that the vertical axis is the stress and the horizontal axis is the strain, the resulting curve is called a Conventional Stress– Strain Diagram.

THE STRESS–STRAIN DIAGRAM

Conventional Stress– Strain Diagram True Stress–Strain Diagram

THE STRESS–STRAIN DIAGRAM • Conventional stress–strain diagram for a mild steel specimen. 1ksi≈ 6.895 MPa

STRESS–STRAIN BEHAVIOR OF DUCTILE AND BRITTLE MATERIALS

• Stress–Strain Behavior of Ductile and Brittle Materials: • Materials can be classified as either being ductile or brittle, depending on their stress–strain characteristics. • Ductile Materials: • Any material that can be subjected to large strains before it fractures is called a ductile material. • Ductile materials for design because these materials are capable of absorbing shock or energy, and if they become overloaded, they will usually exhibit large deformation before failing.

• The percent reduction in area is another way to specify ductility. It is defined within the region of necking as follows:

STRESS–STRAIN BEHAVIOR OF DUCTILE AND BRITTLE MATERIALS

• Besides steel, other metals such as brass, molybdenum, and zinc may also exhibit ductile stress–strain characteristics similar to steel, whereby they undergo elastic stress–strain behavior, yielding at constant stress, strain hardening, and finally necking until fracture.

• In most metals, however, constant yielding will not occur beyond the elastic range. One metal for which this is the case is aluminum. • Actually, this metal often does not have a well-defined yield point , and consequently it is standard practice to define a yield strength using a graphical procedure called the offset method

STRESS–STRAIN BEHAVIOR OF DUCTILE AND BRITTLE MATERIALS

• Offset Method: • Normally for structural design a 0.2% strain is chosen, and from this point on the ε axis a line parallel to the initial straight-line portion of the stress–strain diagram is drawn. • The point where this line intersects the curve defines the yield strength.

1ksi≈ 6.895 MPa

BRITTLE MATERIALS • Materials that exhibit little or no yielding before failure are referred to as brittle materials. • Gray cast iron is an example, having a stress-strain diagram in tension as shown by portion AB of the curve Gray Cast Iron. 1ksi≈ 6.895 MPa

BRITTLE MATERIALS • It can generally be stated that most materials exhibit both ductile and brittle behavior. – For example, steel has brittle behavior when it contains a high carbon content, and it is ductile when the carbon content is reduced. – Also, at low temperatures materials become harder and more brittle, whereas when the temperature rises they become softer and more ductile. 1ksi≈ 6.895 MPa

HOOKE’S LAW • The stress–strain diagrams for most engineering materials exhibit a linear relationship between stress and strain within the elastic region. • An increase in stress causes a proportionate increase in strain. • Robert Hooke (1676) use springs and is known as Hooke’s law.

• E represents the constant of proportionality, which is called the modulus of elasticity or Young’s modulus, named after Thomas Young (1807). • This equation represents the equation of the initial straight-lined portion of the stress-strain diagram up to the proportional limit. • Furthermore, the modulus of elasticity represents the slope of this line. • E= 200 GPa (Steel)

STRAIN HARDENING • If a specimen of ductile material, such as steel, is loaded into the plastic region and then unloaded, elastic strain is recovered as the material returns to its equilibrium state. • The plastic strain remains, however, and as a result the material is subjected to a permanent set. • When the load is removed; however, it will not fully return to its original position. • Since interatomic forces have to be overcome to elongate the specimen elastically, then these same forces pull the atoms back together when the load is removed.

STRAIN HARDENING • If the load is reapplied, the atoms in the material will again be displaced until yielding occurs at or near the stress A’, and the stress–strain diagram continues along the same path as before.

STRAIN ENERGY • Strain Energy: • As a material is deformed by an external load, the load will do external work, which in turn will be stored in the material as internal energy. • This energy is related to the strains in the material, and so it is referred to as strain energy.

MODULUS OF RESILIENCE • Modulus of Resilience: • In particular, when the stress σ reaches the proportional limit, the strain-energy density is referred to as the modulus of resilience.

• Physically the modulus of resilience represents the largest amount of internal strain energy per unit volume the material can absorb without causing any permanent damage to the material. • Certainly this becomes important when designing bumpers or shock absorbers.

MODULUS OF TOUGHNESS • Modulus of Toughness: • This quantity represents the entire area under the stress–strain diagram and therefore it indicates the maximum amount of strainenergy the material can absorb just before it fractures. • This property becomes important when designing members that may be accidentally overloaded.

POISSON’S RATIO • Poisson’s Ratio: • When a deformable body is subjected to an axial tensile force, not only does it elongate but it also contracts laterally.

• In the elastic range the ratio of these strains is a constant, since the deformations are proportional. • Constant is referred as Poisson’s ratio, υ(nu), and has a value that is unique for a particular material that is both homogeneous and isotropic. • The negative sign is included since longitudinal elongation (positive strain) causes lateral contraction (negative strain), and vice versa.

POISSON’S RATIO

THE SHEAR STRESS–STRAIN DIAGRAM • The Shear Stress–Strain Diagram: • If the material is homogeneous and isotropic, then this shear stress will distort the element uniformly.

• G is called the shear modulus of elasticity or the modulus of rigidity.

FAILURE OF MATERIALS DUE TO CREEP AND FATIGUE • The mechanical properties of a material have up to this point been discussed only for a static or slowly applied load at constant temperature. • In some cases, however, a member may have to be used in an environment for which loadings must be sustained over long periods of time at elevated temperatures, or in other cases, the loading may be repeated or cycled. • Creep: When a material has to support a load for a very long period of time, it may continue to deform until a sudden fracture occurs or its usefulness is impaired. This time-dependent permanent deformation is known as creep • Fatigue: When a metal is subjected to repeated cycles of stress or strain, it causes its structure to break down, ultimately leading to fracture. • This behavior is called fatigue, and it is usually responsible for a large percentage of failures in connecting rods and crankshafts of engines; steam or gas turbine blades; connections or supports for bridges, railroad wheels, and axles; and other parts subjected to cyclic loading. • In all these cases, fracture will occur at a stress that is less than material’s yield stress.

REFERENCES • REFERENCES: • Mechanics of Materials, 9th Ed., R.C. Hibbeler, Prentice Hall, 2014. • Mechanics of Materials, 7th Ed., F.P. Beer, E.R. Johnston, J.T. DeWolf, D.F. Mazurek, McGraw Hill, 2015. • Strength of Materials Part-1: Elementary Theory and Problems, 2nd Ed., S. Timoshenko, D. Van Nostrand Company, 1948....


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