Midterm 1 A solutions PDF

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Answer Key Testname: MIDTERM_1

1) No

Correct Answer Was Provided. 2) No Correct Answer Was Provided. 3) E 4) E 5) C 6) B 7) A 8) C 9) E 10) D 11) E 12) C 13) D 14) C 15) A 16) C 17) E

A-9

Some possibly useful formulas and constants: v = ∆x ∆t x = x0 + v0x t + 12 ax t2

v = dx dt vx = v0x + ax t

∆v a = ∆t x = 12 (v0x + vx )t

2 a = dv = d x dt dt2 2 = v2 vx 0x + 2ax (x − x0 )

y = y0 + vy0 t + 12 ay t2

vy = v0y + ay t

y = 12 (v0y + vy )t

2 + 2a (y − y ) vy2 = v0y y 0

~v = ~v0 + ~at

~r = ~r0 + ~v0 t + 21~at2

~v13 = ~v12 + ~v23

Σ~F = m~a

~ FG = m~g

2 ac = v R

R=

Ffr = µk FN

Ffr ≤ µs FN

2 aR = vR

atan = dv dt

C = 2πr

A = πr 2

A = 4πr 2

V = 34 πr 3

|~g | = 9.80 m/s2

1 mi = 5,280 ft

1 in = 2.54 cm

v02 sin 2θ g

T = 1 f

FD = −bv...