Navdeep\'s Final Exam Part #1 - MATH 136-31D TR 9 30am, section 31D, Fall 2020 Web Assign PDF

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12/15/2020

Navdeep's Final Exam Part #1 - MATH 136-31D TR 9:30am, section 31D, Fall 2020 | WebAssign

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MATH 136-31D TR 9:30am, section 31D, Fall 2020 INSTRUCTOR

Victor Lasic

Navdeep's Final Exam Part #1 (Test)

Ivy Tech CC, IN

Current Score

QUESTION

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TOTAL SCORE

20/20

100.0%

Due Date https://www.webassign.net/web/Student/Assignment-Responses/submit?dep=25528391&tags=autosave#question1655743_17

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12/15/2020

Navdeep's Final Exam Part #1 - MATH 136-31D TR 9:30am, section 31D, Fall 2020 | WebAssign

TUE, DEC 15, 2020 3:10 PM EST

Assignment Submission & Scoring Assignment Submission For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer. Assignment Scoring Your last submission is used for your score.

1.

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 1.2.067.

MY NOTES

Simplify the expression, and rationalize the denominator if appropriate. 3x 2y3

√6xy2y2

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2.

Navdeep's Final Exam Part #1 - MATH 136-31D TR 9:30am, section 31D, Fall 2020 | WebAssign

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 1.4.046.

MY NOTES

SWOKATG13 2.1.059.

MY NOTES

Simplify the expression. 1 x+h

− 1 x

h −1x(x+h)

3.

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

Solve the formula for the specified variable. GK + N = D − UK for K K= $$D−NG+U

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4.

Navdeep's Final Exam Part #1 - MATH 136-31D TR 9:30am, section 31D, Fall 2020 | WebAssign

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 2.2.033.

MY NOTES

It takes a girl 36 minutes to deliver the newspapers on her route; however, if her brother helps, it takes them only 20 minutes. How long would it take her brother to deliver the newspapers by himself? min

45

5.

[2/2 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 2.3.014.

MY NOTES

Solve the equation by factoring. (If there is more than one solution, enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION. If there are infinitely many solutions, enter INFINITELY MANY.) −8 5x 1 + = 2 x−4 x+4 x − 16 x = -1/5 If there are infinitely many solutions, give the restrictions on x as a comma separated list. (If there are not infinitely many solutions or there are no restrictions on x, enter NONE.) −

6.

None

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 2.3.039.

MY NOTES

Solve by using the quadratic formula. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.) 2 9 − +7=0 w w2 w= 1,27

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7.

Navdeep's Final Exam Part #1 - MATH 136-31D TR 9:30am, section 31D, Fall 2020 | WebAssign

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 2.4.045.

MY NOTES

Find the solutions of the equation. (Enter your answers as a comma-separated list.) 6x2 + x + 2 = 0 −1−i√4712, −1+i√4712 x =

8.

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 2.5.004.

MY NOTES

Solve the equation. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.) 2|5x + 8| − 1 = 15 x= 0, −165

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Navdeep's Final Exam Part #1 - MATH 136-31D TR 9:30am, section 31D, Fall 2020 | WebAssign

[1/1 Points]

9.

DETAILS

PREVIOUS ANSWERS

SWOKATG13 2.5.024.

MY NOTES

Solve the equation. x=5+

2x − 7

x=8

10.

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 2.5.035.

MY NOTES

Solve the equation. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.) x4 − 41x2 + 400 = 0 5, −5,4,−4 x =

11.

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 2.6.055.

MY NOTES

Solve the inequality, and express the solutions in terms of intervals whenever possible. |5x + 9| < 8 −

17 1 ,− 5 5

−

17 ,∞ 5

no solution −∞, −

1 5

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Navdeep's Final Exam Part #1 - MATH 136-31D TR 9:30am, section 31D, Fall 2020 | WebAssign

5 −

12.

17 1 ,− 5 5

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 2.7.005.

MY NOTES

Solve the inequality, and express the solution in terms of intervals whenever possible. (x + 5)(x − 1)(8 − x) ≤ 0 [−5, 1]

[8, ∞)

[1, 8] [−5, 1)

[8, ∞)

[−5, 8) (−8, 5]

13.

[1/1 Points]

(1, ∞)

DETAILS

PREVIOUS ANSWERS

SWOKATG13 3.2.047.

MY NOTES

Find an equation of the circle that satisfies the stated conditions. Endpoints of a diameter A(6, −9) and B(−4, 5) (x−1)2+(y+2)2=74 https://www.webassign.net/web/Student/Assignment-Responses/submit?dep=25528391&tags=autosave#question1655743_17

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14.

Navdeep's Final Exam Part #1 - MATH 136-31D TR 9:30am, section 31D, Fall 2020 | WebAssign

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 3.3.036.

MY NOTES

Find the slope-intercept form of the line that satisfies the given conditions. Through A(−8, 6) and B(7, 12) $$y=25x +465

15.

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 3.4.028.

MY NOTES

Find the domain of f. f(x) = 9 ,9 7

7x − 9 x2 − 81 (9, ∞)

− {−9, 9} (−∞, −9) ∞) 9

(9,

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Navdeep's Final Exam Part #1 - MATH 136-31D TR 9:30am, section 31D, Fall 2020 | WebAssign

9, 9 7

(9, ∞)

9 ,∞ 7

16.

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 3.5.033.

MY NOTES

Explain how the graph of the function compares to the graph of y = f(x). For example, for the equation y = 2f(x + 3), the graph of f is shifted 3 units to the left and stretched vertically by a factor of 2. y = f(x − 4) + 5 The graph of f is shifted 4 units to the right and 5 units down. The graph of f is shifted 4 units to the right and 5 units up. The graph of f is shifted 4 units up and 5 units to the left. The graph of f is shifted 4 units up and 5 units to the right. The graph of f is shifted 4 units down and 5 units to the right.

17.

[1/1 Points]

DETAILS

PREVIOUS ANSWERS

SWOKATG13 3.6.007.

MY NOTES

Express f(x) in the form a(x − h)2 + k. f(x) = 2x2 − 20x + 59 2(

5)2+9

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12/15/2020

Navdeep's Final Exam Part #1 - MATH 136-31D TR 9:30am, section 31D, Fall 2020 | WebAssign

2(x−5)2+9 f(x) =

18.

[2/2 Points]

DETAILS

SWOKATG13 3.6.041.

PREVIOUS ANSWERS

MY NOTES

An object is projected vertically upward from the top of a building with an initial velocity of 128 ft/sec. Its distance s(t) in feet above the ground after t seconds is given by the equation s(t) = −16t2 + 128t + 120. (a) Find its maximum distance above the ground. s(t) = 376

ft

(b) Find the height of the building. ft

120

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