NYU Classes Principles of Biology Lab, Section 001 Tests & Quizzes 2 PDF

Title NYU Classes Principles of Biology Lab, Section 001 Tests & Quizzes 2
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Course Principles of Biology I, II
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Download NYU Classes Principles of Biology Lab, Section 001 Tests & Quizzes 2 PDF


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8/13/2020

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NYU Classes : Principles of Biology Lab, Section 001 : Tests & Quizzes

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Principles of Biology Lab, Section 001



  Tests & Quizzes

Tests & Quizzes

Quiz 2 Return to Assessment List

Part 1 of 1 -

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Question 1 of 40 Which is NOT an advantage of using C. elegans in genetic screens, compared to the

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other model organisms (compared to Horse, Pig, Mouse)?



A. Short generation time



B. Large number of offspring



C. Easy to breed and maintain in a laboratory setup



D. They are multicellular organisms

Answer Key: D Question 2 of 40 Which is NOT a method of introducing RNAi to an organism?



A. Soak worms in dsRNA



B. dsRNA are injected directly into the body



C. Microinject RNAi into the organs



D. Feed worms with bacteria carrying gene for dsRNA

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Answer Key: C Question 3 of 40 During the genetic screen in c. elegans, if EMS creates a recessive mutation that is

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viable and homozygous. What would you expect to see if we let a mutant F2 hermaphrodite self-fertilize?



A. 50% of F3 worms carry the mutation



B. 25% of F3 worms carry the mutation



C. None of the F3 worms carry the mutation



D. All F3 worms carry the mutation

Answer Key: D Question 4 of 40 How do germ-line mutations differ from somatic mutations?



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A. Germ-line mutations result in mutant gametes, while somatic mutations

do not.



B. Germ-line mutations are reversible, while somatic mutations are not.



C. Germ-line mutations involve small changes to DNA such as base-pair

substitutions, while somatic mutations usually involve large deletions.



D. Germ-line mutations occur during DNA replication, while somatic

mutations do not.

Answer Key: A Question 5 of 40 Why do you need to know the sequence of a gene before you can target it with RNAi?



A. The sequence of the gene will determine the size of the siRNA



B. This sequence of the gene will allow you to mutate it within the

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chromosome

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C. This will allow us to design a dsRNA that is complementary to the target mRNA



D. The sequence of the gene will provide information on the Dicer protein

Answer Key: C Question 6 of 40 Scientists wanted to determine the levels of pollution that a fish could withstand. They placed fish in tanks with differing pollution levels and timed how long they could live

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under those conditions. What is a controlled variable?



A. Amount of time survived



B. Levels of pollution



C. Type of pollution



D. Number of fish dead

Answer Key: C Question 7 of 40 You randomly created mutations in the genome of drosophila flies to identify genes involved in

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the development of a variation of wing shape. This is an example of forward genetics A. True



B. False

Answer Key: True Question 8 of 40 A scientist testing the effects of a chemical on apple yield sprays an orchard with the

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chemical. A second orchard does not receive the chemical. In the fall, the number of apples harvested from each forest is counted. Which of the following is the independent variable in the experiment?



A. the number of apples



B. the chemical



C. the first orchard

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D. the second orchard

Answer Key: B Question 9 of 40 RNA interference is a mechanism for silencing gene expression at the



A. level of replication.



B. Post- transcriptional level



C. level of translation.



D. post-translational level.

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Answer Key: B Question 10 of 40 How does the RNA induced silencing complex (RISC) bind to mRNA?



A. Based on base pairing of target mRNA and siRNA



B. Translation inhibited and mRNA degraded.



C. One strand remains bound to the protein.



D. By using the enzymatic function of Dicer to degrade siRNA

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Answer Key: A Question 11 of 40 1.0 Points The image below represents a cell death assay done on a human cell line. The fluorescent red dye stains

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A. Cells that have receptors for the dye molecule



B. Cells that are dead because their cell membrane is degraded and lets the dye in



C. Cells not fixed by paraformaldehyde



D. All cells that are alive

Answer Key: B Question 12 of 40 In C. elegans RNAi , L4 hermaphrodites are usually required for effective gene silencing in the

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progeny



A. True B. False

Answer Key: True Question 13 of 40 https://newclasses.nyu.edu/portal/site/cd378193-70f6-4c7f-909e-157524012eef/tool/8c67dc67-77ff-496c-9e23-8f2d28ca5f99/jsf/select/selectIndex

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For the RNAi treatment in C.elegans, the long dsRNA molecules are produced by the worm cell 1.0 Points True



False

Answer Key: False Question 14 of 40 Male c. elegans have



A. Two X chromosomes (XX)



B. one X chromosome (XO)



C. one X and one Y chromosome (XY)



D. no sex chromosome

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Answer Key: B Question 15 of 40 Why are two T7 promoters needed in the plasmid to create working RNAi?



A. One promoter is needed for the transcription of T7 polymerase



B. This allows transcription of the two complementary strands of the

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dsRNA



C. Because the promoters are not very effective



D. Because at least two molecules of dsRNA are needed to produce RNAi

Answer Key: B Question 16 of 40 You transferred an L4 male worm onto a plate with Roller RNAi. What do you expect to

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see on the plate after one week at 12C?



A. The plate should contain some worms that have the mutation as a

result of incubation with the gene



B. After one week, the offspring of the L4 will express the roller phenotype

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C. I would expect to see the L4 male worm growing into an adult male

worm



D. The progeny should move in corkscrew fashion staying in the same regions.

Answer Key: C Question 17 of 40 In a controlled cell death assay, what would be your conclusion if the negative control

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turned out positive?



A. All cells survived as expected



B. Our experimental setup is flawed



C. The negative control confirms the validity of the experiment



D. No conclusion can be made

Answer Key: B Question 18 of 40 In an RNAi experiment in c.elegans, someone accidentally forgot to add IPTG to a plate

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with dumpy RNAi plasmids. What phenotype should we expect after one week of treatment?



A. The worms will not feed on the bacteria as there is no IPTG, so we will

have normal worms



B. The IPTG does not influence the expression of the dumpy dsRNA, so

we will expect short and fat worms



C. The lacZ promoter will be inactive and T7 polymerase will not express, so we expect normal worms



D. The dumpy dsRNA gene will not be expressed, only normal worms will be on the plate

Answer Key: D Question 19 of 40 https://newclasses.nyu.edu/portal/site/cd378193-70f6-4c7f-909e-157524012eef/tool/8c67dc67-77ff-496c-9e23-8f2d28ca5f99/jsf/select/selectIndex

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How could you increase the ratio of males to hermaphrodites in a wild type stock of C.

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elegans?



A. By decreasing the loss of O chromosomes during reproduction



B. By decreasing the loss of X chromosomes during reproduction



C. By increasing nondisjunction of X chromosomes during reproduction



D. By decreasing cross fertilization in the culture

Answer Key: C Question 20 of 40 EMS is a mutagenic compound, that introduces point mutations into the DNA

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A. True



B. False

Answer Key: True Question 21 of 40 TWIST is a transcription factor that is found to be mutated in some SCS (Saethre-

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Chotzen syndrome) patients. Mutations in which other genes could potentially be a cause for SCS?



A. Genes that are expressed in adults



B. Genes that are not expressed in the same cells as TWIST



C. TWIST target genes upstream expressed in other cells



D. Genes that are controlled by the TWIST gene

Answer Key: D Question 22 of 40 A student set up an experiment to test if plants give off water vapor. Fifty pea plants, growing in pots, were covered with individual glass containers and left overnight. The

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next morning, the inside of each lid was covered in droplets of water. The lab student concluded that plants generally give off water vapor. What critique would you make of the experimental design? https://newclasses.nyu.edu/portal/site/cd378193-70f6-4c7f-909e-157524012eef/tool/8c67dc67-77ff-496c-9e23-8f2d28ca5f99/jsf/select/selectIndex

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A. The experiment was not precise, meaning it was not reproducible.



B. The student did not have a clearly stated hypothesis before beginning

the experiment.



C. There was not a large enough sample of pea plants used to get

adequate data. D. There was no control so the water could have come from other sources  such as air in the jar or the soil.

Answer Key: D Question 23 of 40 During the process of RNA -interference, DICER is _______?



A. An enzyme that forms a complex with the mRNA



B. An enzyme that breaks long strands of single-stranded DNA into

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siRNA.



C. An enzyme that breaks long strands of double-stranded RNA into

siRNA.



D. An enzyme that inactivates mRNA after siRNA binds to it.



E. An enzyme that takes siRNA and makes it into mRNA.

Answer Key: C Question 24 of 40 How many independent variables can you have in one experiment?



A. 2



B. 1



C. 3



D. As many as you want

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Answer Key: B

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Question 25 of 40 You mutate a male worm with EMS and cross it to a hermaphrodite expressing GFP in

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the M lineage and find that all the F1 worms are wild type. What do you conclude?



A. The mutation is recessive



B. There are no recessive mutations in the M lineage



C. The mutation is dominant



D. There are neither recessive nor dominant mutations in the M lineage

Answer Key: A Question 26 of 40 You want to find out if temperature has an effect on the growth of bread mold. You decide

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to grow the mold in nine Petri dishes containing the same amount and type of nutrients. Three were kept at 0C, three were kept at 90C, and three were kept at room temperature, 27C. The containers were examined, and the growth of the bread mold was recorded each Friday for five weeks. Which of the following is your hypothesis?



A. If the number of containers change, then the amount of bread mold will change.



B. If the amount of nutrients is changed, then the amount of bread mold will change.



C. If the temperature changes then the amount of bread mold will change.

D. If there are different types of nutrient used, then that will cause  differences in the amount of bread mold.

Answer Key: C Question 27 of 40 You are doing a small pilot study to determine the phenotypic effects of knocking out a 1.0 Points regulatory gene expressed early in development by using dsRNA. This an example of forward genetics



A. True B. False

Answer Key: False https://newclasses.nyu.edu/portal/site/cd378193-70f6-4c7f-909e-157524012eef/tool/8c67dc67-77ff-496c-9e23-8f2d28ca5f99/jsf/select/selectIndex

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Question 28 of 40 During a cross between a male worm and a hermaphrodite worm, you screened a total of

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2050 F1 progeny under the microscope and found only two males. What can you conclude?



A. Cross-fertilization occurred because we have ~0.1% males in F1



B. Self-fertilization occurred because we have ~0.1% males in F1



C. Self-fertilization occurred because we have ~50% males in F1



D. Cross-fertilization occurred because we have ~50% males in F1

Answer Key: B Question 29 of 40 With regards to siRNA, the most efficient siRNA duplexes will contain which of the

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following features?



A. Will be 21-23 nucleotides in length



B. Comprise a sense strand and an antisense strand of RNA



C. The antisense strand harbors 100% complementarity to the mRNA

target sequence



D. a and b only



E. a, b, and c

Answer Key: E Question 30 of 40 Why do you think wild type hermaphrodites do NOT produce genetically identical

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progeny when crossed to males?



A. Because hermaphrodite sperm outcompetes the sperm from males



B. Because male sperm does not reach the hermaphrodites' eggs



C. Because male sperm outcompetes the sperm from hermaphrodites



D. Because male sperm is not functional

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Answer Key: C Question 31 of 40 You created a gene knockout of a fibroblast protein in the genome of c elegans to identify genes 1.0 Points involved in the development of cuticle shape. This is an example of forward genetics A. True



B. False

Answer Key: False Question 32 of 40 Which protein, associated with the RNA-inducing silencing complex (RISC), activates

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and cleaves mRNA in RNAi?



A. None of these



B. RNase III Dicer



C. Endonuclease



D. Argonaute



E. RNA helicase

Answer Key: D Question 33 of 40 1.0 Points The following c. elegans is a



A. Cannot tell



B. Hermaphrodite



C. Female

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D. Male

Answer Key: B Question 34 of 40 What is the structure of the RNAi moiety that targets and binds to specific mRNAs?



A. DNA-protein complex



B. Single stranded RNA



C. Single sheet polypeptide



D. Double stranded RNA



E. Double stranded DNA

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