Practice Questions for using the rules of multiplication and addition in genetic crosses PDF

Title Practice Questions for using the rules of multiplication and addition in genetic crosses
Author Anonymous User
Course Test Bank for Global Health 101 2nd edition by Richard Skolnik
Institution Qafqaz Universiteti
Pages 2
File Size 72.8 KB
File Type PDF
Total Downloads 26
Total Views 192

Summary

Download Practice Questions for using the rules of multiplication and addition in genetic crosses PDF


Description

Practice questions for using the rules of multiplication and addition in genetic crosses Q - When do we us the rule of multiplication? A - When we have independent events in sequence. You multiply the probabilities of the independent sequential events. Example: In heterozygous pea plants (Pp) what is the probability that the offspring (Pp xPp) will be homozygous recessive? Pp x Pp The chance of the first parent (Pp) passing on p (little p) is ½ and the second parent (Pp) is also ½. Therefore ½ x ½ = ¼ OK that is simple. In a trihybridcross between AABbCC X AaBbCc what is the probability that the offspring will be AaBbCC? Just work on each letter combination at a time. You can use a punnett square initially but you will soon learn the probabilities. AABbCC X AaBbCc resulting in AaBbCC so Aa =2/4 or ½

A a

A AA Aa

A AA Aa

Bb X Bb resulting in Bb is ½ CC X Cc resulting in CC is ½ Therefore what is the probability that a cross between AABbCC X AaBbCc will produce offspring that are AaBbCC is ½ x ½ x ½ = 1/8

OK now practice this. 1. Parents = aaBbCC x aabbCc What is the probability that offspring will be aabbcc (recessive for all alleles)? 2. Parents are WwYYZz x wwyyZZ What is the probability that offspring will be WwYyZz? (heterozygous for all alleles)?

Q - When do we us the rule of addition? A - When we have two or more mutually exclusive events. Example: What is the probability that the offspring from a cross between WwYyZz x WwYYZZ will be WWYyZz or WWYYZZ? So first you do the same as above and use the rule of multiplication to work out the probability for each: WwYyZz x WwYYZZ WWYyZz = Ww ¼ x Yy ½ x Zz ½ = 1/16 WWYYZZ = WW ¼ x YY ½ x ZZ ½ = 1/16 Then you add the probabilities of these mutually exclusive events together. 1/16 + 1/16 = 2/16 or 1/8 so there is a 1/8 probability that the offspring from a cross between WwYyZz x WwYYZZ will be WWYyZz or WWYYZZ.

OK, now practice a few of these: 1. What is the probability that the offspring from a cross between SsTtVv x SsTtVV will be SSTTVV or ssttVV? 2. What is the probability that the offspring from a cross between CCDDEe x ccDdEe will be CcDDee or CCDdtEE? Slightly more complicated. 3. What is the probability that the offspring from a cross between CCDdee x CcDdEe will be dominant for at least 2 of the 3 characters? (hint: work out the probabilities for each offspring that has at least 2 dominant character using the multiplication rule then use the rule of addition) I will post the answers on Monday....


Similar Free PDFs