Title | Probability island submit |
---|---|
Author | Anonymous User |
Course | Business information technology |
Institution | Jomo Kenyatta University of Agriculture and Technology |
Pages | 3 |
File Size | 112.3 KB |
File Type | |
Total Downloads | 77 |
Total Views | 138 |
population growth of an island...
Name:
weeks 4-6
Statistics Island Mean, Median, Mode, Range, Standard Deviation Mean 4.5 Median 3.5 Mode 2 Range 9 Standard 2.97 Deviatio n Mean = (10+3+2+6+2+1+9+6+2+4)/10 = 4.5 Median 1,2,2,2,3,4,6,6,9,10 = n/2 + (n/2) +1 (3+4)/2 = 3.5 Mode 1,2,2,2,3,4,6,6,9,10 =2 Range 1,2,2,2,3,4,6,6,9,10 10 – 1 = 9 Standard deviation 1,2,2,2,3,4,6,6,9,10 √((1 – 4.5) ^2 + (2 – 4.5) ^2 + (2 – 4.5) ^2 + (2 – 4.5) ^2 + (3 – 4.5) ^2+ (4 – 4.5) ^2+ (6 – 4.5) ^2+ (6 – 4.5) ^2+ (9 – 4.5) ^2 + (10 – 4.5) ^2)/10 = 2.97
2.97 is the population standard deviation Create a box and whisker plot of your data. Identify the five-number summary and the interquartile range. Box and whisker plot 1,2,2,2,3,4,6,6,9,10
Name:
weeks 4-6
five-number summary Minimum = 1; Q1 = 2; Median = 3.5; Q3 = 6.75; Maximum = 10 Interquartile range 6.75 – 2 = 4.75 Standard normal curve
Probability that the number of births is less than two Probability below mean = 0.5; probability above mean = 0.5; therefore, probability that the number of births is less than two = 2 * 0.5 / 4.5 = 0.22 Probability that the number of births is more than one
Name:
weeks 4-6
Probability below mean = 0.5; probability above mean = 0.5; therefore, probability that the number of births is more than one is = 1 – (1 * 0.5 / 4.5) = 0.89...