Title | Purdue digital signal processing labs ece 438 4 |
---|---|
Author | 芷菱 劉 |
Course | Digital Signal Processing I |
Institution | Purdue University |
Pages | 173 |
File Size | 21.2 MB |
File Type | |
Total Downloads | 48 |
Total Views | 118 |
Questions or comments concerning this laboratory should be directed to Prof. Charles A. Bouman, School of Electrical and Computer Engineering, Purdue University, West Lafayette IN 47907; (765) 494-0340; [email protected]...
Purdue Digital Signal Processing Labs (ECE 438)
By: Charles A. Bouman
Purdue Digital Signal Processing Labs (ECE 438)
By: Charles A. Bouman
Online: < http://cnx.org/content/col10593/1.4/ >
CONNEXIONS Rice University, Houston, Texas
∼ ∼ ∼ ∼
a=
h
1
2
3
i
a
a
1×3
b = a. a c =a∗b
b
a
b
b
3×1 c
14 = 1 ∗1 + 2 ∗ 2 + 3 ∗ 3
a c = a. ∗ a a
a. a
a
a
Z
2π
sin2 (5t) dt
0
Z
1
et dt
0
sin t/6 sin t/6 sin n/6
sin t/6
∆t
sin2 5t N
I
I (N ) N exp (t)
1 ≤ N ≤ 100
[0, 1] I (N )
J (N )
I 5 = I 10 = 0
N
0, 2π
=
Z
∞
−∞
• •
(t) (t)
t t
[−10π, 10π ] [−2, 2]
y = rect t <
|
2
(t)| dt .
a = 0.8 a = 1.0
• an (u (n) − u (n − 10)) • cos (ωn) an u (n)
n
a = 1.5
[−20, 20]
ω = π/4
n
[−1, 10]
y = u (n) >
f (t) = sin 2πt
xn
Ts x (n) = f (Ts n) = sin (2πTs n) . f (Ts n)
Ts Ts Ts Ts
Ts
= 1/10 0 ≤ n ≤ 100 = 1/3 0 ≤ n ≤ 30 = 1/2 0 ≤ n ≤ 20 = 10/9 0 ≤ n ≤ 9
Ts = 1/10 Ts = 1/2
Ts = 10/9
Ts = 1/3
n
n
f (m, n) = 255| −50 ≤ m ≤ 50
−50 ≤ n ≤ 50
(0.2m) sin (0.2n) |
y (n) = y (n − 1) + x (n) + x (n − 1) + x (n − 2) y (n)
x (n)
y = S [x]
S
y (n) x (n)
d x (t) y (t) = dt Rt y (t) = −∞ x (τ ) dτ
x (n)
1 ( 3
=
)
= 0.8 ∗
+ 0.2 ∗ +
=
1 3
• •
−10 ≤ n ≤ 20 • δ (n) − δ (n − 5) • u (n) − u (n − (N + 1))
N = 10 u (n)
>
−10 ≤ n ≤ 20
y = S1 [x]
y (n) = x (n) − x (n − 1) y = S2 [x] y (n) =
1 y (n − 1) + x (n) 2
xn
y n
S1
S2
S2 (S1 )
S2
S1 S2 S1 (S2 ) S1
S1 + S2
S1
S2
y = S2 [x] δ (n)
y = S3 [x] S2 x = S3 [S2 [x]]
δ = S3 [S2 [δ]] x
S2 y = S3 [x] y (n) = ax (n) + bx (n − 1) a
b S3
S3
S3 S2 [δ] S3 S3
S3 S2
δ
S3 S3
x M
x
M
M
x x
M
T0 T0 = 2
t ∈ [0, 2] s (t) =
1 t− 2
T0 = 1
t ∈ − 21 , 12
s (t) = rect (2t) −
s (t) = a0 +
∞ X
1 2
Ak sin (2πkf0 t + θk )
k=1
f0 = 1/T0
sin (2πkf0 t + θk )
[0, T0 ]
y (n) = 0.9y (n − 1) + 0.3x (n) + 0.24x (n − 1)
H (z) ≡
−π < ω < π
Y (z ) X (z) |H ejω |
∠H ejω
x (t) = 0 +
13 X 4 sin (2πkt) . kπ k=1 k
X ejω
x (n) ∞ X x (n) e−jωn . X ejω = n=−∞
ω
f s > 2f c
S (f ) =
1 X (f ) . Ts
1 2Ts
.
|f | ≤
1 2Ts
.
1 Ts
Ts
p (t) =
1 t − Ts 2
p (t)
.
P (f ) |P (f ) | = Ts |
(f /fs ) | . N
|Hb (f ) | =
|H (f ) | = = | Ts = 1 • • •
1+
1 N . f fc
|Hb (f ) P (f ) T1 Hb (f ) | s 2 1 | (f /fs ) | . 1+(ff )N c
(f /fs ) | fc = 0.45
N = 20
0.1
0.3 0.1 0.1 0.3
0.8
0.8 0.5
0.45
L x (n)
z (n) 2π Z ejω [−π/L, π/L]
L −1
Z ejω = X ejωL . X ejω 2π/L Z ejω
z (n)
x (n)
X ejω [−π, π]
x (n)
L−1
x (n) x (n)
Dth y (n) x (n)
y (n)
D−1 1 X X Y ejω = D k=0
X ejω
2π
[−π, π]
ω − 2πk D
x (Dn)
.
Y ejω
1/D [−π, π] X ejω
1 ω Y ejω = X ej D D π/2
D y (n)
[−π/D, π/D] ω ∈ [−π, π] .
π/2
M
x (n)
y (n) =
N−1 X i=0
bi
ak
bi x (n − i) −
M X k=1
y (n)
ak y (n − k) N
M
y (n) h (n)
δ (n)
h (n) =
N−1 X i=0
bi δ (n − i) −
ak = 0
M X k=1
ak h (n − k) .
k
h (n) =
N−1 X bi δ (n − i) . i=0
N
ak 6= 0 ak 6= 0
n→∞
bi x (n) X (z) =
∞ X
x (n) z −n .
n=−∞
z
X ejω = =
z
X (z)|z=ej ω P∞
n=−∞
x (n) e−jωn
x (n − K )
Z
↔
=
=
K
m = n−K
z −K P∞
n=−∞
P∞
x (n − K ) z −n
−(m+K ) m=−∞ x (m) z P∞ −K −m z m=−∞ x (m) z
z −K X (z )
=
PM PN−1 Y (z) = i=0 bi z −i X (z) − k=1 ak z −k Y (z ) PN−1 PM Y (z) 1 + k=1 ak z −k = X (z) i=0 bi z −i △ Y (z) X (z)
H (z) =
=
PN−1
1+
i=0 P M
k=1
bi z −i ak z −k
H (z) H ejω =
PN−1 i=0
1+
PM
bi e−jωi
k=1
ak e−jωk
.
z −1
z1 = ejθ z2 = e−jθ θ
z1
θ ∈ [0, π]
1 − z1 z −1 1 − z2 z −1 = 1 − ejθ z −1 1 − e−jθ z −1
Hf (z ) =
1 − 2cosθz−1 + z −2 .
=
h (n) h (n) ±∞ Hf (z)
ω
Hf e±jθ = 0
e±jθ ω=θ
θ
−π < ω < π θ = π/6
|Hf ejω |
θ = π/3
θ = π/2
Hf (z) θ
θ Hf (z)
n = 0
M
|ω| < π θ
Hf (z)
θ Hf (z)
• •
θ
Hi (z) = =
1−r (1−rej θ z −1 )(1−re−j θ z −1 ) 1−r 1−2rcos(θ)z −1 +r 2 z −2
p1 = rejθ r
θ
p2 = re−jθ p1 |r| < 1
±∞ r
|Hi ejw |
θ
|ω| < π
θ = π/3
•
r = 0.99
•
r = 0.9
•
r = 0.7
Hi (z) r
r Hi (z)
|ω| < π
θ
Hi (z)
2π Hi (z) θ
r = 0.995
n
ω=θ
ω θ
[θ − 0.02, θ + 0.02]
• • •
ω
[θ − 0.02, θ + 0.02] r
r = 0.9999999
r ω=θ
ωp ≤ ω ≤ ωs
H ejω
δp
δs
|ω| < ωp ωp < ωs
ωs < |ω| ≤ π
δp |H ejω − 1| ≤ jω |H e | ≤ δs
|ω| < ωp
ωs < |ω| ≤ π ωp ωs δ p
δs
|ω| < 1.8
|ω| > 2.2
ωc 1 |ω| ≤ ωc Hideal ejw = { 0 ωc < |ω| ≤ π hideal (n) =
ω n c
ωc π
π
−∞
>
π N
N
N
N = 20
x (n) = { N = 200 N = 50
sin (0.1πn) 0 ≤ n ≤ 49 0 x (n) x (n)
N = 50
N = 200 x (n) = 0 n ≥ 50
N = 200 X (k)
x (0) , · · · , x (N − 1)
N = 50
N = 200
N2
N
N
N/2
N−1
X
X (k) =
x (n) e−j2πkn/N .
n=0
N
X (k) = N
X (k) N
[x (n)]
x (n) n n X (k) =
N−1 X
x (n) e−j2πkn/N +
n=0 n
m
n n 2m N −2 N/2 − 1 n = 2m + 1
X
n m
X
x (2m + 1) e−j2πk(2m+1)/N .
m=0
N/2−1
X
N/2 − 1 n = 2m n 2m + 1 N −1
N/2−1
x (2m) e−j2πk2m/N +
m=0
X (k) =
x (n) e−j2πkn/N .
n=0 n
N/2−1
X (k) =
N−1 X
N/2−1
x (2m) e−j2πkm/(N/2) + e−j2πk/N
m=0
X
x (2m + 1) e−j2πkm/(N/2) .
m=0
N
N/2
N/2
N/2 N
e−j2πk/N
N/2 N/2 x0 (n)
x1 (n)
N x0 (n) =
x (2n)
x1 (n) = x (2n + 1) ,
N
n = 0, ..., N/2 − 1 x (n) X (k ) = X0 (k ) + e−j2πk/N X1 (k ) X0 (k)
X1 (k)
k = 0, ..., N − 1.
N/2
X0 (k) = DFTN/2 [x0 (n)] X1 (k) = DFTN/2 [x1 (n)]
X0 (k)
X1 (k)
N N/2
N/2 N/2
k
N
e−j2πk/N k
−e−j2π N = e−j2π
k+N/2 N
. N
X (k ) = X0 (k ) + WNk X1 (k ) X (k + N/2) = X0 (k) − WNk X1 (k)
}
k = 0, ..., N/2 − 1
WNk = e−j2πk/N
N N/2
(N/2)
X0
(k)
(N/2)
X1
(k)
N/2
N
N/2 k WN = e−j2πk/N X
x (n) = δ (n) N = 10 x (n) = 1 N = 10 x (n) = ej2πn/N N = 10
N N/2
N/2 N/4
N/2 N/2
N N = 2p
p
X (0) = x (0) + x (1) X (1) = x (0) − x (1)
x (n) = δ (n) N =8 x (n) = 1 N =8 x (n) = ej2πn/8 N =8
x (n) = 1
N =8
N = 2p N
p
>
FX (x) = P (X ≤ x) X (−∞, x]
x ∈ (−∞, ∞) .
FX (x) x
X FX (x)
fX (x) R t1 t0
fX (x) dx
FX (t1 ) − FX (t0 )
= P (t0 < X ≤ t1 ) .
X
X
=
(−∞, ∞)
g (X) E [g (X)] E [g (X)]
= =
g (X)
R∞
−∞
g (x) fX (x) dx
P∞
x=−∞
g (x) P (X = x)
µX = E [X] =
µX Z ∞
2 σX
xfX (x) dx
−∞
i Z h 2 2 = E (X − µX ) = σX
∞
−∞
2
(x − µX ) fX (x) dx .
1 2 exp − 2 (x − µX ) . fX (x) = √ 2σX 2πσ X 1
X
X ∼ N µ, σ 2
σ2
µ
X v ǫ
X
X =v+ǫ X
X {X1 , X2 , · · · , XN } N
Xi FX (x)
Xi {X1 , X2 , · · · , XN }
X
{X1 , X2 , · · · , XN } µX =
N 1 X Xi N i=1
2
σX=
N X
1 Xi − µ X N − 1 i=1
2
.
µX # " N N 1 X 1X µ Xi = E X =E E [Xi ] = µX N N i=1 i=1 i i h P hP N 1 = X X V ar µX = V ar N1 N V ar i i i=1 i=1 N2 2 PN σX 1 = i=1 V ar [Xi ] = N N2
a
a V ar a → 0
E a = a N →∞
X X
X1 X2
X
X Y = aX + b a
b
a 6= 0
Y
X1000
"
2
#
2 E σ X = σX
X
X
Y σY2
µY
2 σX
Y
a b µX
X a
b Y a
X b
Y Y Y Y Y Y
Y Y
X
FX (x)
FX (x) FX (x)
{X1 , X2 , ..., XN } F X (x) F X (x) = I{Xi ≤x} F X (x)
1 N
= {
PN
i=1 I{X i ≤x}
1,
0,
Xi ≤ x
Xi
x
F X (x) Nx
Xi
x Nx =
N X i=1
I{Xi ≤x} = N F X (x)
P (Xi ≤ x) = FX (x) P I{Xi ≤x} = 1 = FX (x) P I{Xi ≤x} = 0 = 1 − FX (x)
F X (x) = E F X (x)
1 E N
[Nx] 1 = N i=1 E I{X i ≤x} 1 N E I{Xi ≤x} = N = 0 · P I{Xi ≤x} = 0 + 1 · P I{Xi ≤x} = 1 PN
=
F X (x)
FX (x) .
FX (x)
1 V ar F X (x) = FX (x) (1 − FX (x)) . N F X (x)
F X (t)
X
t <
X
s N = 20
FX (x) FX (x)
X Y = FX (X) X
Y
X
N = 200
FX (·)
Y [0, 1]
X
Y
FX (·)
P (Y ≤ y) = { FX (x) y = FX (x)
0,
y1 x
{Y ≤ y }
0≤y≤1 FY (y) = =
{X ≤ x}
P (Y ≤ y)
P (FX (X) ≤ FX (x))
= P (X ≤ x)
=
FX (x)
=
y .
Y FX (·)
FX−1 (U )
U
FX (·)
FX (·)
Z ∼ FZ (z)
FZ (·)
X ∼ FX (x)
FX (·)
FZ (·)
FX (x) = 1 − e−3x u (x) . N = 20 N = 200
• •
Xi
fX (x)
x
L fX (x) L
x0 [x0 , x1 ] (x1 , x2 ]
(xL−1 , xL ]
xL
bin (k)
∆
(xk−1 , xk ] k = 1, 2, · · · , L bin (k) = (xk−1 , xk ]
k = 1, 2, · · · , L
xL −x0 L
∆ = f˜ (k)
X
bin (k)
f˜ (k ) = P (X ∈ bin (k )) R xk f (x) dx = xk−1 X
≈ fX (x) ∆
x ∈ bin (k) ∆ {X1 , X2 , · · · , XN } Xn
bin (k) In (k) = { Xn
bin (k)
Xn ∈ bin (k)
1, 0,
Xn ∈ / bin (k)
H (k)
bin (k) H (k) =
N X
In (k) .
n=1
H (k) /N
X
bin (k) E
h
H(k) N
i
1 N
= = =
1 N
PN
n=1 {1
PN
n=1
E [In (k )]
· P (Xn ∈ bin (k)) + 0 · P (Xn ∈ / bin (k))} f˜ (k) f˜ (k)
Xn H (k)
V ar N
h
H(k) N
i
=
1 N
f˜ (k) 1 − f˜ (k) .
f˜ (k)
H (k) /N H (k) f˜(k) ≈ N fX (x) fX (x) ≈
H (k) N∆ x
bin (k)
x ∈ bin (k) . bin (k)
U FU (u) 0,
u1
1
X = U3 FX (x) =
P(X ≤ x) 1 P U3 ≤ x P U ≤ x3
= = =
FU (u)|u=x3
0,
x1
fX (x)
f˜ (k)
xL = 1
x ∈ [0, 1] bin (k)
X
f˜ (k) = FX (xk ) − FX (xk−1 ) k = 1, · · · , L FX (x) fX (x) fX (x)
f˜ (k)
f˜(k)
f˜ (k) U X
1
X = U3
X [0, 1]
H (k) /N
H (k) /N
f˜(k)
f˜ (k)
X
Y
FX (x) X
FX,Y (x, y ) = P (X ≤ x, Y ≤ y) .
fX,Y (x, y) =
FX,Y (x, y) =
Z
∂2 FX,Y (x, y ) . ∂x∂y
y
−∞
Z
x
fX,Y (s, t) ds dt. −∞
Y
FY (y)
X
Y
fX,Y (x, y) = fX (x) fY (y) X
Y
E [XY ] = E [X] E [Y ] X
Y X
•
E [XY ] =
•
E [(X − µX ) (Y − µY )] =
Z Z
∞ −∞ ∞ −∞
Z Z
∞
xyfX,Y (x, y) dx dy
−∞ ∞ −∞
(x − µX ) (y − µY ) fX,Y (x, y) dxdy
• ρX Y =
E [(X − µX ) (Y − µY )] E [XY ] − µX µY = σX σY σX σY X
Y
(Xi , Zi ) X
Y X
Z
Z Z=Y
Z = (X + Y ) /2
Z = (4 ∗ X + Y ) /5 Z = (99 ∗ X + Y ) /100 Z X Y
Y1 Y2
Y1000
X1 X2
Z X1000 Z
Y
ρX Z X X
Y Z
(X2 , Z2 )
X Z E [XY ] = E X E Y
Y X
Y (Xi , Zi )
(X1 , Z1 )
(X1000 , Z1000 ) Z Xi
ρX Z = s
Zi
µ µ X − Z − i i Z X i=1
PN
2 2 PN µ µ i=1 Zi − Z i=1 Xi − X
PN
ρX Z ρX Z ρX Z
ρX Z (Xi , Zi )
ρX Z ρX Z
Xn
n Xn
X rX X (m) = E [Xn Xn+m ]
m = · · · , −1, 0, 1, · · · . n
E [Xn+m Xn ]
m m
X 2 σX
rX X (m) = = { =
E [Xn Xn+m ] E [Xn ] E [Xn+m ] E Xn2
2 σX δ (m) .
m 6= 0
m=0
E [Xn Xn+m ] =
Xn
Xn+m
m 6= 0
Xn Yn
rY Y (m) rX X (m)
h (m) rY Y (m) = h (m) ∗ h (−m) ∗ rX X (m)
Xn y (n) = x (n) − x (n − 1) + x (n − 2) Yn X Yi i = 1, 2, · · · , 1000 (n = 1, 2, 3, 4) (Yi , Yi+1 ) (i = 1, 2, · · · , 900)
(Yi , Yi+2 ) (Yi , Yi+3 ) (Yi , Yi+4 ) (i = 1, 2, · · · , 900) rY Y (m) rY Y (m)
r Y Y (m) = N
1 N − |m|
N−|m|−1 n=0
Y rY Y (m)
X
Y (n) Y (n + |m|) Yn rY Y (m)
− (N − 1) ≤ m ≤ N − 1
m
−20 ≤ m ≤ 20
rY Y (m) rY Y (m) rY Y (m) m
X
rY Y (m)
m m
rY Y (m)
r Y Y (m)
Y c X Y (m) = E [Xn Yn+m ]
Xn
m = · · · , −1, 0, 1, · · · .
Yn c X Y (m) =
cX Y (m) =
1 N −m
N−m−1
X
n=0
X (n) Y (n + m) 0 ≤ m ≤ N − 1
N−1 X 1 X (n) Y (n + m) 1 − N ≤ m < 0 N − |m| n=|m|
N m X (n) D/2 Y (n)
α
Y (n) = αX (n − D) + W (n) W (n) D cX Y c X Y (m) = =
E [X (n) Y (n + m)] E [X (n) (αX (n − D + m) + W (n + m))]
= αE [X (n) X (n − D + m)] + E [X (n)] E [W (n + m)] =
αE [X (n) X (n − D + m)]
X (n)
W (n + m)
c X Y (m) = αrX X (m − D)
rX X (m − D)
m=D
D
c X Y (m)
X (n)
rX X (m)
m=0
X Xn
Zn X
Y
m
Y...