Title | Qualifying round 2014 answers |
---|---|
Author | Akinrinmade Daniel |
Course | Engineering Analysis |
Institution | Ladoke Akintola University of Technology |
Pages | 2 |
File Size | 45.1 KB |
File Type | |
Total Downloads | 41 |
Total Views | 139 |
Download Qualifying round 2014 answers PDF
MIT Integration Bee Qualifying Exam 1
Z e 1
log( x2 ) dx = 2
√ sin( 3 x ) dx = 0
2
Z 9
3
Z ∞ d h 1+ x − x 2 i e dx = − e
4
5
6
−9
Z 2
r
Z √
Z
10
Z 0
11
Z
−1
x2 1 dx = − log 2 x−1 2
x arctan x dx =
x 1 2 x arctan( x ) − + 2 2
1 arctan( x ) 2
dx
0
0
21 January 2014
x+
xe
√
x
q
x+
√
dx = 2 e
x + · · · dx =
√
x
x − 53 dx 1 log = x + 38 91 x2 − 15x − 2014
13
Z
h i e x log(1 + x2 ) − 2(1 + x ) arctan x dx =
19 6
√ ( x − 2 x + 2)
sin(2x ) cos (3x ) dx =
12
Z
h i e x log(1 + x2 ) − 2x arctan x
cos x cos 5x − 10 2
14
Z
p (arcsin x )2 dx = 2 1 − x2 arcsin x −
2x + x (arcsin x )2 7
Z 2π 0
√ 2π +4 3 |1 + 2 sin x | dx = 3
15
Z √ 2 x −1
x
arctan 8
Z
x (1 − x )2014 dx
=
x )2016
(1 − 2016
−
(1 − x )2015 2015 9
Z
arcsinh( x ) = x arcsinh( x ) −
16
Z
p
dx
=
p
x2 − 1 −
x2 − 1
x sec2 (4x ) dx
=
x tan (4x ) + 4
log(cos (4x )) 16 p
x2 + 1 17
Z
2 dx = 2 log (2 − 6 − 11x + 6x2 − x3
x ) − log( x2 − 4x + 3)
18
Z 1 0
1
⌊1 − log2 (1 − x )⌋
dx = log 2
19
Z 1/ √3
20
Z 5π/2
0
0
q
x+
p
x2 + 1 dx =
√ dx 7 3π = 9 2 + cos x
2 3...