Sheer Force & Bending Moments Tutorial 2 solutions PDF

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EG2206 : SHEAR FORCE & BENDING MOMENTS 2 1.

A support beam is 1m long, constructed from steel and projects horizontally. The beam is built in at one end and free at the other. A 2kg mass is suspended from the free end. The beam has a circular cross section of diameter 38mm. Derive formulae for the shear force and bending moment with respect to “z” the position along the beam. Use these to draw fully labelled SF & BM diagrams. STEEL = 7800 kg/m3.

2.

Derive formulae for the shear force and bending moment with respect to “z” the position, for the beams shown below. Use these to draw fully labelled SF & BM diagrams. (a)

20kN

30kN

1m

(b)

3.

2m

10kN

1m

10kN/m

2m

1m

10kN

50kN

2m

2m

5kN/m

1m

Derive formulae for the shear force and bending moment with respect to “z” the position along the wing for the right hand wing (as we look at it) of the aircraft shown below. Do this both for when the aircraft is on the ground and in level cruise. The undercarriage is fuselage mounted. Use these to draw fully labelled SF & BM diagrams for both cases. The weight of the wings and the lift are assumed to be uniformly distributed over the wing span. All lift is provided by the main wings. the varying mass and location of fuel carried in the wings may be neglected.

5m

Mass of aircraft : 20 tonnes Length : 33.6m Height : 12.5m Wing span : 34.3m Tail span : 14.3m Capacity : 126 passengers Range : 5000km

10 m

Cruise : Mach 0.75 Altitude : 35 000 ft Mass of each wing : 2 tonnes (excl. engines) Engine type : CFM 56/7 Mass of each engine : 1 tonne Pilot’s name : Nigel...