Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith for only 59 99 PDF

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Download Solution Manual for Introduction to Chemical Engineering Thermodynamics 8th Edition by Smith for only 59 99 PDF

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SVNAS 8th Edition Annotated Solutions

power =

Chapter 1

energy J Nm kg m 2 = = = time s s s3

charge time charge = current*time = A s

current =

energy = current*electric potential time energy kg m2 electrical potential = = current*time A s3

power =

electrical potential resistance electrical potential kg m2 resistance = = 2 3 current A s

current =

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SVNAS 8th Edition Annotated Solutions

electrical potential =

Chapter 1

charge electrical capacitance 2

electrical capacitance =

P

Sat

  b  a   t /  C c 

/ torr  10

4

charge As A s   2 electrical potential kg m kg m2 3 As

B    7.5  P Sat / kPa=7.5exp  A   T /K C  

 b B   =7.5exp   exp  2.303  a    A T / K C  T c / K 273.15       

  b B 2.303 a   =ln  7.5 + A  T  C T c / K 273.15 / K  

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Chapter 1

The point of this problem is just for you to practice evaluating and plotting a simple function. You will do a number of problems over the course of the semester (and many more over the course of your career) in which the results are best presented in graphical form. The only thing to be careful of in plotting the Antoine equation is to pay attention to the units of T and Psat and to whether the constants are given for use with the base 10 logarithm or the natural logarithm. The parameters in Table B.2 are for use with T in °C, P in kPa, and the natural logarithm. I used MS Excel to prepare the plots for diethyl ether. A portion of the spreadsheet (containing the plots) is shown below: 13.9891 B

2463.93 C

223.24

Vapor pressure of Diethyl Ether

Vapor pressure of Diethyl Ether

200 180

100

160

Vapor Pressure (kPa)

T (deg C) Psat (kPa) -30 3.450361508 -29 3.684455127 -28 3.931786307 -27 4.192943086 -26 4.468531566 -25 4.759176154 -24 5.065519787 -23 5.388224158 -22 5.727969934 -21 6.085456959 -20 6.461404464 -19 6.856551255 -18 7.271655907 -17 7.707496937 -16 8.16487298 -15 8.644602953 -14 9.147526209 -13 9.674502686 -12 10.22641305 -11 10.80415881 -10 11.40866246 -9 12.0408676 -8 12.70173902 -7 13.39226279 -6 14.11344639 -5 14.86631874 -4 15.65193033 -3 16.4713532 -2 17.3256811 -1 18.21602942 0 19.14353533 1 20.10935774

Vapor Pressure (kPa)

A

140

120 100 80 60

10

40 20 0

1

-30

-20

-10

0

10

20

30

40

50

-30

60

-10

Temperature (°C)

10

30

50

Temperature (°C)

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Chapter 1

SVNAS, problem 1.4 300

T (deg C or deg F)

200 100 0

deg C

-100 -200

deg F

-300 -400 -500 0

50

100

150

200

250

300

350

T (K)

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

Chapter 1



 











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Chapter 1







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Chapter 1

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Chapter 1

MP dP  g dz RT

Mg dP  dz P RT

Mg  P ln      z  zo  P RT o    Mg P  Po exp    z  zo  RT  

 0.029*9.8  P  101325exp   1609   83430 Pa  8.314*283  Updated 16/01/2017

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SVNAS 8th Edition Annotated Solutions

Chapter 1

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Chapter 1

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Chapter 1









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SVNAS 8th Edition Annotated Solutions

Chapter 1



 







 

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Chapter 1



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

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Chapter 1



1.25 kg m 3 *55880 m 3 s 1 = 69850 kg s 1

m



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Chapter 1

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Chapter 1

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SVNAS 8th Edition Annotated Solutions

Chapter 1

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Chapter 1

A 12.74

B 2017.87

C -80.87

T (°C) -18.5 -9.5 0.2 11.8 23.1 32.7 44.4 52.1 63.3 75.5

T(K) 254.65 263.65 273.35 284.95 296.25 305.85 317.55 325.25 336.45 348.65

Psat (kPa)

ln (Psat)

ln (Psat)fit

Error2

Psatfit (kPa)

3.18 5.48 9.45 16.9 28.2 41.9 66.6 89.5 129 187

1.157 1.701 2.246 2.827 3.339 3.735 4.199 4.494 4.860 5.231

1.125 1.697 2.253 2.849 3.368 3.767 4.211 4.479 4.841 5.201

1.02E-03 2.03E-05 4.77E-05 4.61E-04 7.96E-04 1.02E-03 1.43E-04 2.24E-04 3.50E-04 9.19E-04

3.08 5.46 9.52 17.27 29.01 43.26 67.40 88.17 126.61 181.42

Error Sum

5.01E-03

6.000

200 180

5.000

160

4.000

Pressure(kPa)

ln(Pressure(kPa))

Relative Error -3.2% -0.4% 0.7% 2.2% 2.9% 3.3% 1.2% -1.5% -1.9% -3.0%

3.000 2.000

140 120 100 80

60 40

1.000

20 0.000

0 200

250

300 Temperature (K)

ln P sat / kPa  A 

350

400

-50

0 50 Temperature (°C)

100

B T / K C

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SVNAS 8th Edition Annotated Solutions

Chapter 1

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