Solution manual of Numerical and Analytical Methods with MATLAB 1st edition pdf PDF

Title Solution manual of Numerical and Analytical Methods with MATLAB 1st edition pdf
Author farsh sardar
Course Analytical Methods
Institution University of Auckland
Pages 12
File Size 256.2 KB
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Summary

Authors: William Bober ; Chi Tay Tsai ; Oren Masory
Published: CRC Press 2009
Edition: 1st
Pages: 396
Type: pdf
Size: 10MB...


Description

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FOLFNKHUHWRGRZQORDG

SOLUTIONS MANUAL FOR Numerical and Analytical Methods with MATLAB

by Willam Bober

@solutionmanual1

https://gioumeh.com/product/numerical-and-analytical-methods-with-matlab-solutions

FOLFNKHUHWRGRZQORDG

@solutionmanual1

https://gioumeh.com/product/numerical-and-analytical-methods-with-matlab-solutions

FOLFNKHUHWRGRZQORDG

SOLUTIONS MANUAL FOR Numerical and Analytical Methods with MATLAB

by Willam Bober

Boca Raton London New York @solutionmanual1

CRC Press is an imprint of the Taylor & Francis Group, an informa business

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FOLFNKHUHWRGRZQORDG

CRC Press Taylor & Francis Group 6000 Broken Sound Parkway NW, Suite 300 Boca Raton, FL 33487-2742 © 2009 by Taylor and Francis Group, LLC CRC Press is an imprint of Taylor & Francis Group, an Informa business No claim to original U.S. Government works Printed in the United States of America on acid-free paper 10 9 8 7 6 5 4 3 2 1 International Standard Book Number: 978-1-4398-1901-2 (Paperback) This book contains information obtained from authentic and highly regarded sources. Reasonable efforts have been made to publish reliable data and information, but the author and publisher cannot assume responsibility for the validity of all materials or the consequences of their use. The authors and publishers have attempted to trace the copyright holders of all material reproduced in this publication and apologize to copyright holders if permission to publish in this form has not been obtained. If any copyright material has not been acknowledged please write and let us know so we may rectify in any future reprint. Except as permitted under U.S. Copyright Law, no part of this book may be reprinted, reproduced, transmitted, or utilized in any form by any electronic, mechanical, or other means, now known or hereafter invented, including photocopying, microfilming, and recording, or in any information storage or retrieval system, without written permission from the publishers. For permission to photocopy or use material electronically from this work, please access www.copyright.com (http://www.copyright.com/) or contact the Copyright Clearance Center, Inc. (CCC), 222 Rosewood Drive, Danvers, MA 01923, 978-750-8400. CCC is a not-for-profit organization that provides licenses and registration for a variety of users. For organizations that have been granted a photocopy license by the CCC, a separate system of payment has been arranged. Trademark Notice: Product or corporate names may be trademarks or registered trademarks, and are used only for identification and explanation without intent to infringe. Visit the Taylor & Francis Web site at http://www.taylorandfrancis.com

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FOLFNKHUHWRGRZQORDG SOLUTION MANUAL

NUMERICAL AND ANALYTICAL METHODS WITH MATLAB Table of Contents Page Chapter 2

1

Chapter 3

46

Chapter 4

58

Chapter 5

98

Chapter 6

107

Chapter 7

176

Chapter 8

180

Chapter 9

188

Chapter 10

214

Chapter 11

271

Chapter 12

303

Chapter 13

309

Chapter 14

339

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CHAPTER 2 FOLFNKHUHWRGRZQORDG P2.1. Taylor series expansion of f (x ) about x = 0 is: f ( x ) = f (0) + f ' (0) x +

f ' ' (0) 2 f ' ' ' (0) 3 f 1V 4 x + ... x + x + 2! 3! 4!

For f ( x) = cos ( x ) , f (0) = 1,

f ′ (x ) = − sin(x ), f ' (0) = 0, f ' ' (x ) = − cos(x ), f ' ' (0) = − 1, f ' ' ' (x ) = + sin(x ), f ' ' ' (0) = 0, f 1V ( x ) = + cos( x ), f

1V

(0) = 1

We can see that cos( x ) = 1−

x2 x 4 x 6 x 8 + − + − + − + ... 2 ! 4 ! 6 ! 8!

and that

term (k ) = − term (k − 1) ×

x2 2 k (2 k − 1)

The following program evaluates cos( x ) by both an arithmetic statement and by the above series for -  x   in step of 0.1 π . % cosf.m % This program evaluates cos(x) by both arithmetic statement and by % series for

-  x   in steps of 0.1 

clear; clc; xi=-pi; dx=0.1*pi; for j=1:21 x(j)=xi+(j-1)*dx;

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cos_arith(j)= cos(x(j));

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sum=1.0; term=1.0;

FOLFNKHUHWRGRZQORDG

for k=1:50 den=2*k*(2*k-1); term=-term*x(j)^2/den; sum=sum+term; test=abs(sum*1.0e-6); if abs(term)...


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