Title | Solutions-derivatives-Exponential sadhas odsakjhd kjsad |
---|---|
Author | Harout Kermezian |
Course | Leadership in Public and Private Sectors |
Institution | Lebanese American University |
Pages | 1 |
File Size | 74.5 KB |
File Type | |
Total Downloads | 25 |
Total Views | 145 |
a targeted goal to reach a certain level of competence...
Section 4.8 The derivative of the exponential and natural logarithm functions Practice Problems
2. (a) 3e3x
(b)
–e–x
(c)
1/x
(d)
3. (a) For the product rule we put u = x4
and
v = ln x
for which du 4x 3 dx
and
dv 1 dx x
By the product rule
dy 1 x 4 ln x 4x 3 x dx x3 4 x3 ln x x3 (1 4 ln x) (b) By the chain rule 2 2 dy e x 2x 2xe x dx
(c) If u ln x
and
du 1 and dx x
dv 1 dx
v x 2
then
By the quotient rule
1 (x 2) ( ln x )1 dy x dx (x 2)2 x 2 x ln x (multiply top and bottom by x ) x( x 2)2
1/x...