Title | Spectrophotometry Lab Report |
---|---|
Author | Hamza Huq |
Course | Introductory Biology Laboratory |
Institution | The University of Texas at Dallas |
Pages | 6 |
File Size | 344.2 KB |
File Type | |
Total Downloads | 81 |
Total Views | 131 |
Lab Report for Spectrophotometry...
Muhammad Hamza Huq MHH180001 10/30/20 Spectrophotometry
1.
2.
Wavelength vs Absorbance 0.9 0.8
Absorbance
0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 400
450
500
550
600
650
Wavelength
3.
Concentration of KMnO4 vs Absorbance at 530nm
Absorbance
1 0.9 0.8 0.7 0.6 0.5
f(x) = 2.12 x R² = 1
0.4 0.3 0.2 0.1 0 0
0.05
0.1
0.15
0.2
0.25
0.3
0.35
0.4
0.45
Concentration of KMnO4
4. The standard curve of the data set from table 3 gives us a linear relationship between the Concentration of KMnO4 and Absorbance. This allows us to create a linear equation to where we can calculate the absorbance or concentration at any point on the line. The R^2 value of 0.9989
gives us confidence that our equation represents a strong relationship between the Concentration and absorbance. 5. Since our equation between our concentration and absorbance is Y=2.1182X, Y representing our absorbance and X representing our concentration. We can use the information of our unknown concentration having an absorbance value of 0.100 and plug that into our Y and find our X value. 0.100 = 2.1182X => Divide both sides by 2.1182 => 0.100/2.1182 = X = 0.0472 mM So our unknown concentration is 0.0472 mM at an absorbance value of 0.100. 6. A=ELC A = absorbance(no unit) L = path length(cm) C = molar concentration(mol/L) E = molar extinction coefficient or molar absorptivity C= 0.00005M A= 0.081 L = 1 cm So, our molar absorptivity should be E = 1620/cm*M
7a.
b.
Protein Conc. Vs Absorbance at 280 nm of HASSA 0.5 0.45 0.4 0.35
f(x) = 0 x R² = 0.99
0.3 0.25 0.2 0.15 0.1 0.05 0 0
50
100
150
200
250
300
c. The R^2 value is very close to 1. d. The equation we will use is Y = 0.0017X, Y represents the absorbance values and X represents the Concentration values(ug/ml). The unknown concentration of HASSA has an absorbance at 0.317. So plugging that into the equation you get 0.317=0.0017X, solving for X you get 186.47 ug/ml. 186.47 ug/ml...