Spectrophotometry Lab Report PDF

Title Spectrophotometry Lab Report
Author Hamza Huq
Course Introductory Biology Laboratory
Institution The University of Texas at Dallas
Pages 6
File Size 344.2 KB
File Type PDF
Total Downloads 81
Total Views 131

Summary

Lab Report for Spectrophotometry...


Description

Muhammad Hamza Huq MHH180001 10/30/20 Spectrophotometry

1.

2.

Wavelength vs Absorbance 0.9 0.8

Absorbance

0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 400

450

500

550

600

650

Wavelength

3.

Concentration of KMnO4 vs Absorbance at 530nm

Absorbance

1 0.9 0.8 0.7 0.6 0.5

f(x) = 2.12 x R² = 1

0.4 0.3 0.2 0.1 0 0

0.05

0.1

0.15

0.2

0.25

0.3

0.35

0.4

0.45

Concentration of KMnO4

4. The standard curve of the data set from table 3 gives us a linear relationship between the Concentration of KMnO4 and Absorbance. This allows us to create a linear equation to where we can calculate the absorbance or concentration at any point on the line. The R^2 value of 0.9989

gives us confidence that our equation represents a strong relationship between the Concentration and absorbance. 5. Since our equation between our concentration and absorbance is Y=2.1182X, Y representing our absorbance and X representing our concentration. We can use the information of our unknown concentration having an absorbance value of 0.100 and plug that into our Y and find our X value. 0.100 = 2.1182X => Divide both sides by 2.1182 => 0.100/2.1182 = X = 0.0472 mM So our unknown concentration is 0.0472 mM at an absorbance value of 0.100. 6. A=ELC A = absorbance(no unit) L = path length(cm) C = molar concentration(mol/L) E = molar extinction coefficient or molar absorptivity C= 0.00005M A= 0.081 L = 1 cm So, our molar absorptivity should be E = 1620/cm*M

7a.

b.

Protein Conc. Vs Absorbance at 280 nm of HASSA 0.5 0.45 0.4 0.35

f(x) = 0 x R² = 0.99

0.3 0.25 0.2 0.15 0.1 0.05 0 0

50

100

150

200

250

300

c. The R^2 value is very close to 1. d. The equation we will use is Y = 0.0017X, Y represents the absorbance values and X represents the Concentration values(ug/ml). The unknown concentration of HASSA has an absorbance at 0.317. So plugging that into the equation you get 0.317=0.0017X, solving for X you get 186.47 ug/ml. 186.47 ug/ml...


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