Title | Transverse Standing Waves |
---|---|
Author | Akanksha Chouhan |
Course | Physics I |
Institution | Kean University |
Pages | 4 |
File Size | 131 KB |
File Type | |
Total Downloads | 7 |
Total Views | 157 |
Transverse Standing Waves...
Transverse Standing Waves Akanksha Chouhan Physics Lab Report 05 December 2018
Lab Partners: Amber Dimartini Briana Lenard Palak Patel Njasanie Fernandez
Purpose:
The purpose of this lab wa to verify the v =
√ (Ft)/(μ) for a string under tension.
Theory: Equation one is important to establish resonance. In equation one, N is the number of segments in the standing wave pattern, and each segments relates to a half of a wavelength which is given by λ/2. N (λ/2) = L Equation two is a measure of the velocity of propogation of the waves which travel along the string. The wavelength can be adjusted by fixing v and this is done by altering the tension in the string v=fλ Equation three depicts the relationship between v and FT, which is the tension in the string. μ is the linear mass density of the string. v= √ (FT )/μ The tension in the string is created by a hanging mass, m, which is placed on the end of the string. Therefore, the equation can be manipulated into FT = mg Sketch:
Data Collected ● f=120 Hz ● L= 2.07 cm ● μ=2.67 x 10^-4 kg/m Table One m(kg)
N (Number Of Segments)
6.72 kg
1
1.60 kg
2
0.750 kg
3
0.410 kg
4
0.265 kg
5
0.182 kg
6
0.135 kg
7
Sample Calculations On Separate Sheet
Analysis: Table One λ(m) = 2L/N
v(m/s)=λf
FT(N) = mg
4.14 m
496.8 m/s
65.86 N
2.07 m
248.4 m/s
15.68 N
1.38 m
165.6 m/s
7.35 N
1.035 m
124.2 m/s
4.02 N
0.828 m
99.36 m/s
2.60 N
0.69 m
82.8 m/s
1.78 N
0.591 m
70.92 m/s
1.32 N
Table Two FT(N)
V (m/s) =
√ (Ft)/(μ)
1
61.2 m/s
2
86.55 m/s
3
106 m/s
4
122.40 m/s
5
136.85 m/s
6
149.91 m/s
7
161.91 m/s
8
173.10 m/s
Conclusion: The calculated results were very similar to the theoretical values which were given. Some potential sources of error could be not measuring the string correctly, or not counting the number of loops correctly....