Vapor Pressure and Heat of Vaporization Lab PDF

Title Vapor Pressure and Heat of Vaporization Lab
Author Mariah Kador
Course Gen Chemistry Lab
Institution Northwestern State University of Louisiana
Pages 3
File Size 59 KB
File Type PDF
Total Downloads 96
Total Views 155

Summary

Chemistry Lab Report...


Description

Vapor Pressure and the Heat of Vaporization Experiment #2

OBJECTIVES This experiment aims to research the relation between a liquid-vapor pressure and its temperature by utilizing the Clausius Clapeyron equation to calculate the heat vaporization of the unknown substance and the information obtained in this experiment.

INTRODUCTION Liquids are made up of different molecules of film energies. There is film energy to escape to the gas phase of some faster liquid molecules. Some of the slowest steam molecules condense in the fluid at the same time. The vaporization rate of a bottle is greater than that of the condensation, which eventually evaporates the solvent. The relation between the vapor pressure and the temperature of the solution is discussed in this experiment. The gas pressure sensor and the temperature sensor gather pressure and temperature data. The atmospheric pressure is extracted from the total pressure by vapor pressures.

PROCEDURE Start by filling a 600 mL tap water beaker and start to heat on a hot plate. Then, get a temperature and gas tension sensor and insert a 125 mL flask with the rubber stopper. Next, in the 1000 ml water beaker, position the temperature sample. , Then keep the flask in the water, the temperature should be room temperature. Finally, open the two-way valve by pressing the syringe plunger and inject the liquid into the pitcher and repeat at 40-45°C and 50-55°C.

EXPERIMENTAL RESULTS

TRIAL

1

2

3

4

TEMPERATURE (C)

17.6 C

32.6 C

41.6 C

50 C

TEMPERATURE (K)

290.65 K

305.75 K

314.75 K

323.15 K

104.30 kPa

101.10 kPa

101.17 kPa

MEASURED TOTAL 101.35 kPa PRESSURE (kPa)

For propanol, the equation of the equation was y = -25040x + 84.64. The function ∆HVapR is equal to -25040 and R = 8.31 J/mol•K. Therefore, ∆HVapR=-25040 ∆HVap=-25040*8.31J/mol. K ∆HVap=-208.08KJ/mol

CONCLUSION The heat of propanol vaporization was detected in the experiment. The increase in temperature allows for an increase in air pressure and steady maintenance in volume. The vapor pressure above the solvent is raised by a higher solvent temperature. Unfortunately, the vapor pressure has not improved due to an experimental error with a hole in the center of the stopper. This was clearly seen in the diagrams of the vapor pressure. The accepted values and compounds of the, as well as the calculated values, were substantially different. These failures during the experiment can be attributed.

POST LAB QUESTIONS 1. What is the purpose of the lab? This experiment aims to research the relation between a liquid-vapor pressure and its temperature by utilizing the Clausius Clapeyron equation to calculate the heat vaporization 2. What are the Science concepts of this lab? Briefly Explain the science/chemistry concepts(s) involved in this lab. This experiment involves

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3. What is your hypothesis about the outcome of this lab? If the temperature increases, then the pressure will increase. 4. What results were obtained? (values) Temperature and measured total pressure were measured. 5. How do these results address the purpose of the lab? This requires looking at the experimental titles, the purpose, the data, and calculation sections of the lab notebook and bringing them all together. What do the results mean? The results revealed that the increase in temperature allows for an increase in air pressure and steady maintenance in volume. 6. What errors could have happened or how could this lab activity be improved to address the purpose? The hole in the stopper prevented the pressure from increasing as the temperature increased.

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