1 - Beverage Density Experiment Pre-Lab (1) Lopez, Meghan PDF

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Gen Chem 1 (CHEM 1411) Beverage Density Pre-Lab...

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Lopez, Meghan 1 CHEM 1411 Sec: 6303 EXPERIMENT #1 Pre-Lab (Beverage Density) 1. Summarize what we will be doing in this lab and it’s purpose in a few sentences During this experiment, we will be determining the percent of sugar found in each of the five unknown samples provided. This information will then be plotted on a graph to create a calibration curve of densities versus percent sugar concentrations. In the second portion of the experiment, a straight-line relationship will produce reference points created by the curve, which will be compared against the “reference,” or known solutions, to determine which beverage is in each of the samples.

2. Define the following terms a. Mass - is a measure of the amount of material in an object. SI uses the (kg) as the base unit. The metric system uses the (g) as the base unit. b. Volume - is a derived unit from length. The most commonly used metric units for volume are (L), which is equal to 1dm3 and (mL), which is also equal to 1cm3 . c. Density - is the ratio of mass per unit volume, or (mass/volume). It is a characteristic physical property that can be used to identify a substance. It is an intensive property, meaning the amount of substance provided does not change the density of the sample, but is an important factor in helping to identify the substance, if unknown. i. D = m/V

3. Complete the following calculations a. Determine the density of a liquid that has a mass of 7.5E3 mg and a volume of 22.01 mL  ● mass = 7.5E3 mg ● volume = 22.01mL ● density = mass/volume ○ 7.5E3 mg/ 22.01 mL = 340.75 mg/mL → 3.4E2 mg/mL

Lopez, Meghan 2 CHEM 1411 Sec: 6303

b. Determine the volume of a solid that has a mass of 5.93E-6 kg and a density of 3.3E-9 g/mL ● mass = 5.93E-6 kg or  5.93 x 10-6  kg = 0.00000593 kg → 0.00593 g → 5.93E-3 g  ● density = 3.3E-9 g/mL = 3.3E-9 g/mL ● volume = mass/density ○ (5.93 x 10-3  g)/3.3 x 10-9  g/mL = 17.97E5 mL → 1.8E6 mL

c. Determine the mass of a solution of 8.88 nL if its density is 4.47E2 mg/L ● volume = 8.88nL → 8.88E-9 L ● density = 4.47E2 mg/L ● mass = density x volume ○ (8.88 x 10-9  L) x (4.47 x 102 mg/L) = 3.97E-6 mg...