Title | 141 Mole Worksheet Key |
---|---|
Course | General Chemistry I |
Institution | Grossmont College |
Pages | 2 |
File Size | 84 KB |
File Type | |
Total Downloads | 64 |
Total Views | 156 |
Moles Worksheet Answers...
Mass and Moles Worksheet 1.
How many moles in 34.2 g of sulfur? 34.2 𝑔 𝑆 ×
2.
1 𝑚𝑜𝑙 𝑆 = 1.07 𝑚𝑜𝑙 𝑆 32.07 𝑔 𝑆
How many grams in 1.20 moles of carbon? 12.01 𝑔 𝐶 = 14.4 𝑔 𝐶 1 𝑚𝑜𝑙 𝐶
1.20 𝑚𝑜𝑙 𝐶 × 3.
How many atoms in 3.91 moles of sodium? 3.91 𝑚𝑜𝑙 𝑁𝑎 ×
4.
6.02 × 1023 𝑎𝑡𝑜𝑚𝑠 𝑁𝑎 = 2.35 × 1023 𝑎𝑡𝑜𝑚𝑠 𝑁𝑎 1 𝑚𝑜𝑙 𝑁𝑎
How many atoms in 45.22 moles of strontium? 6.02 × 1023 𝑎𝑡𝑜𝑚𝑠 𝑆𝑟 = 2.72 × 1025 𝑎𝑡𝑜𝑚𝑠 𝑆𝑟 45.22 𝑚𝑜𝑙 𝑆𝑟 × 1 𝑚𝑜𝑙 𝑆𝑟
5.
How many molecules in 31 g of chlorine gas?
31 𝑔 𝐶𝑙2 × 6.
1 𝑚𝑜𝑙 𝐶𝑙2 70.90 𝑔 𝐶𝑙2
6.02 × 1023 𝑚𝑜𝑙𝑒𝑐𝑢𝑙𝑒𝑠 𝐶𝑙2 1 𝑚𝑜𝑙 𝐶𝑙2
6.02 × 1023 𝑎𝑡𝑜𝑚𝑠 𝑁 1 𝑚𝑜𝑙 𝑁 × = 2.05 1024 𝑎𝑡𝑜𝑚𝑠 𝑁 1 𝑚𝑜𝑙 𝑁𝐻3 1 𝑚𝑜𝑙 𝑁
What mass would 4.52 x 1024 molecules of water have?
4.52 × 1024 𝑚𝑜𝑙𝑒𝑐𝑢𝑙𝑒𝑠 𝐻2 𝑂 × 8.
1 𝑚𝑜𝑙 𝐻2 𝑂 6.02 × 1023 𝑚𝑜𝑙𝑒𝑢𝑙𝑒𝑠 𝐻2 𝑂
×
18.02 𝑔 𝐻2 𝑂 1 𝑚𝑜𝑙 𝐻2 𝑂
= 135 𝑔 𝐻2 𝑂
How many oxygen atoms in 2.3 x 10-8 g of oxygen?
2.3 × 10−8 𝑔 𝑂2 × 9.
= 2.63 × 1023 𝑚𝑜𝑙𝑒𝑐𝑢𝑙𝑒𝑠 𝐶𝑙2
How many nitrogen atoms in 3.4 moles of ammonia? 3.4 𝑚𝑜𝑙 𝑁𝐻3 ×
7.
×
1 𝑚𝑜𝑙 𝑂2 32.00 𝑔 𝑂2
×
2 𝑚𝑜𝑙 𝑂 1 𝑚𝑜𝑙 𝑂2
×
6.02 × 1023 𝑎𝑡𝑜𝑚𝑠 𝑂 1 𝑚𝑜𝑙 𝑂
= 8.7 × 1014 𝑎𝑡𝑜𝑚𝑠 𝑂
How may atoms in 1.00 ounce of pure gold?
1.00 𝑜𝑧 𝐴𝑢 ×
1 𝑙𝑏 𝐴𝑢 16 𝑜𝑧 𝐴𝑢
×
454 𝑔 𝐴𝑢 1 𝑙𝑏 𝐴𝑢
×
1 𝑚𝑜𝑙 𝐴𝑢 196.97 𝑔 𝐴𝑢
×
6.02 × 1023 𝑎𝑡𝑜𝑚𝑠 𝐴𝑢 1 𝑚𝑜𝑙 𝐴𝑢
= 8.67 × 1022 𝑎𝑡𝑜𝑚𝑠 𝐴𝑢
10.
How many sugar molecules (C12H22O11) could you make from 1.0 pound of carbon?
1.0 𝑙𝑏 𝐶 ×
11.
453.59 𝑔 𝐶 1 𝑚𝑜𝑙 𝐶 1 𝑚𝑜𝑙 𝐶12𝐻22𝑂11 × × 1 𝑙𝑏 𝐶 12.01 𝑔 𝐶 12 𝑚𝑜𝑙 𝐶 6.02 × 1023 𝑚𝑜𝑙𝑒𝑢𝑙𝑒𝑠 𝐶12𝐻22𝑂11 = 1.89 × 1024 𝑚𝑜𝑙𝑒𝑢𝑙𝑒𝑠 𝑠𝑢𝑔𝑎𝑟 × 1 𝑚𝑜𝑙 𝐶12𝐻22𝑂11
What is the mass of 4.00 moles of sugar? 4.00 𝑚𝑜𝑙 𝐶12𝐻22 𝑂11 ×
12.
342.34 𝑔 𝐶12 𝐻22𝑂11 = 1370 𝑔 𝑠𝑢𝑔𝑎𝑟 1 𝑚𝑜𝑙 𝐶12 𝐻22 𝑂11
How many moles of sulfate ions would be released if 2.5 moles of aluminum sulfate were dissolved in water? 3 𝑚𝑜𝑙 𝑆𝑂42− = 7.5 𝑚𝑜𝑙 𝑆𝑂42− 2.5 𝑚𝑜𝑙 𝐴𝑙2 (𝑆𝑂4 )3 × 1 𝑚𝑜𝑙 𝐴𝑙2 (𝑆𝑂4 )3
13.
What is the mass of 1.2 x 10-3 moles of sodium chloride? 1.2 × 10−3 𝑚𝑜𝑙 𝑁𝑎𝐶𝑙 ×
14.
58.44 𝑔 𝑁𝑎𝐶𝑙 = 0.070 𝑔 𝑁𝑎𝐶𝑙 1 𝑚𝑜𝑙 𝑁𝑎𝐶𝑙
How many formula units of NaCl are there in 3.55 x 10-6g of salt? 1 𝑚𝑜𝑙 𝑁𝑎𝐶𝑙 6.02 × 1023 𝑓𝑜𝑟𝑚𝑢𝑙𝑎 𝑢𝑛𝑖𝑡𝑠 𝑁𝑎𝐶𝑙 × 1 𝑚𝑜𝑙 𝑁𝑎𝐶𝑙 58.44 𝑔 𝑁𝑎𝐶𝑙 = 3.66 × 1023 𝑓𝑜𝑟𝑚𝑢𝑙𝑎 𝑢𝑛𝑖𝑡𝑠 𝑁𝑎𝐶𝑙
3.55 × 10−6 𝑔 𝑁𝑎𝐶𝑙 ×
15.
How many Volkswagons are there in 2 moles of Volkswagons?
2 𝑚𝑜𝑙 𝑉𝑜𝑙𝑘𝑠𝑤𝑎𝑔𝑜𝑛𝑠 ×
6.02 × 1023 𝑉𝑜𝑙𝑘𝑠𝑤𝑎𝑔𝑜𝑛𝑠 1.20 × 1024 𝑉𝑜𝑙𝑘𝑠𝑤𝑎𝑔𝑜𝑛𝑠 1 𝑚𝑜𝑙 𝑉𝑜𝑙𝑘𝑠𝑤𝑎𝑔𝑜𝑛𝑠...