2019 MM1-ANS - VCAA past exam answer PDF

Title 2019 MM1-ANS - VCAA past exam answer
Author Yunlin YU
Course Mathematical Methods
Institution Victorian Certificate of Education
Pages 17
File Size 1.1 MB
File Type PDF
Total Downloads 108
Total Views 171

Summary

VCAA past exam answer...


Description

SUPERVISOR TO ATTACH PROCESSING LABEL HERE

Victorian Certificate of Education 2019

Letter STUDENT NUMBER

MATHEMATICAL METHODS Written examination 1 Wednesday 6 November 2019 Reading time: 9.00 am to 9.15 am (15 minutes) Writing time: 9.15 am to 10.15 am (1 hour)

QUESTION AND ANSWER BOOK Structure of book Number of questions

Number of questions to be answered

Number of marks

9

9

40

• Studentsaretowriteinblueorblackpen. • Studentsarepermittedtobringintotheexaminationroom:pens,pencils,highlighters,erasers, sharpenersandrulers. • StudentsareNOTpermittedtobringintotheexaminationroom:anytechnology(calculatorsor software),notesofanykind,blanksheetsofpaperand/orcorrectionfluid/tape. Materials supplied • Questionandanswerbookof13pages • Formulasheet • Workingspaceisprovidedthroughoutthebook. Instructions • Writeyourstudent numberinthespaceprovidedaboveonthispage. • Unlessotherwiseindicated,thediagramsinthisbookarenotdrawntoscale. • AllwrittenresponsesmustbeinEnglish. At the end of the examination • Youmaykeeptheformulasheet. Students are NOT permitted to bring mobile phones and/or any other unauthorised electronic devices into the examination room. ©VICTORIANCURRICULUMANDASSESSMENTAUTHORITY2019

2

THIS pAgE IS BLANK

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2019MATHMETHEXAM1



3

2019MATHMETHEXAM1

Instructions Answerallquestionsinthespacesprovided. Inallquestionswhereanumericalanswerisrequired,anexactvaluemustbegiven,unlessotherwisespecified. Inquestionswheremorethanonemarkisavailable,appropriateworkingmustbeshown. Unlessotherwiseindicated,thediagramsinthisbookarenotdrawntoscale.

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Question 1 (4marks) 1 1 . Let f :  , ∞  → R, f ( x) = x 3 3 −1   a.

i. Findf′(x).

1mark



ii. Findanantiderivativeoff (x).

1mark

b.

Letg : R \ {− 1} → R , g ( x ) =



Evaluateg′(1).

sin(π x ) . x+1 2marks

TURN OVER

2019MATHMETHEXAM1

4

Question 2 (4marks) 1 1 → R , f (x) = . a. Let f : R \ 3 3x − 1

{}

Findtheruleoff –1.

b.

Statethedomainoff –1.

c.

LetgbethefunctionobtainedbyapplyingthetransformationTtothefunction f,where

2marks

1mark

 x   x  c  T     =   +     y   y  d  

andc,d∈R.



Findthevaluesofcanddgiventhatg=f–1.

1mark

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5

2019MATHMETHEXAM1

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Question 3 (3marks) Theonlypossibleoutcomeswhenacoinistossedareaheadoratail.Whenanunbiasedcoinistossed,the probabilityoftossingaheadisthesameastheprobabilityoftossingatail. Johasthreecoinsinherpocket;twoareunbiasedandoneisbiased.Whenthebiasedcoinistossed,the 1 probabilityoftossingaheadis . 3 Jorandomlyselectsacoinfromherpocketandtossesit. a.

Findtheprobabilitythatshetossesahead.

b.

Findtheprobabilitythatsheselectedanunbiasedcoin,giventhatshetossedahead.

2marks

1mark

TURN OVER

6

Question 4 (4marks) x x a. Solve1− cos  = cos  for x ∈ [−2 π , π ]. 2  2  

b.

2marks

x Thefunction f : [ −2π, π ] → R, f ( x) = cos  isshownontheaxesbelow. 2 y 2

1 2�

−�

O

x �

1 2



Let g : [ −2π ,π ] → R , g (x ) = 1 − f ( x ).



Sketchthegraphofgontheaxesabove.Labelallpointsofintersectionofthegraphsof fandg,and theendpointsofg,withtheircoordinates.

2marks

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2019MATHMETHEXAM1



7

2019MATHMETHEXAM1

Question 5 (5marks)

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Let f : R \ {1} → R, f ( x) =

2 + 1. ( x − 1) 2

a.

i. Evaluatef (–1).

1mark



ii. Sketchthegraphoffontheaxesbelow,labellingallasymptoteswiththeirequations.

2marks

y 6 5 4 3 2 1 5

4

3

2

1

O 1

x 1

2

3

4

5

2 3 4

b.

Findtheareaboundedbythegraphoff,thex-axis,thelinex=–1andthelinex=0.

2marks

TURN OVER

2019MATHMETHEXAM1

8

Question 6 (3marks) Fredownsacompanythatproducesthousandsofpegseachday.Herandomlyselects41pegsthatare producedononedayandfindseightfaultypegs. Whatistheproportionoffaultypegsinthissample?

b.

Pegsarepackedeachdayinboxes.Eachboxholds12pegs.LetP betherandomvariablethat representstheproportionoffaultypegsinabox. 1 Theactualproportionoffaultypegsproducedbythecompanyeachdayis . 6 1 Find Pr  Pˆ   .Expressyouranswerintheforma(b)n,whereaandbarepositiverationalnumbers 6  andnisapositiveinteger.

 

1mark

2marks

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a.



9

2019MATHMETHEXAM1

Question 7 (4marks) Thegraphoftherelationy = 1− x 2 isshownontheaxesbelow.Pisapointonthegraphofthisrelation, Aisthepoint(–1,0)andBisthepoint(x,0). y

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y  1  x2

A (–1, 0)

P (x, y)

B (x, 0)

a.

FindanexpressionforthelengthPBintermsofxonly.

b.

FindthemaximumareaofthetriangleABP.

x

1mark

3marks

TURN OVER

2019MATHMETHEXAM1

10

Question 8 (4marks) Thefunction f :R→R, f (x)isapolynomialfunctionofdegree4.Partofthegraphof fisshownbelow. Thegraphof ftouchesthex-axisattheorigin. y  1  , 1   2 

a.

O

x (1, 0)

Findtheruleoff.

1mark

Letgbeafunctionwiththesameruleas f. Let h : D → R, h ( x ) = log e ( g (x )) − log e ( x 3 + x 2 ) ,whereDisthemaximaldomainofh. b.

StateD.

1mark

Question 8 –continued

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(–1, 0)

 1  , 1   2 



11

Statetherangeofh.

2marks

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c.

2019MATHMETHEXAM1

TURN OVER

2019MATHMETHEXAM1

12

Question 9 (9marks)

a.

Statetheruleofg ( f ( x)) .

1mark

b.

Findthevaluesofxforwhichthederivativeof g ( f ( x) ) isnegative.

2marks

c.

Statetheruleof f ( g ( x )) .

d.

Solve f ( g ( x )) = 0.

1mark

2marks

Question 9–continued

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Considerthefunctions f : R → R, f ( x) = 3 + 2 x − x2 and g : R → R, g( x) = e x.

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13

e.

Findthecoordinatesofthestationarypointofthegraphof f ( g( x)) .

f.

Statethenumberofsolutionstog ( f (x )) + f ( g ( x)) =0 .

END OF QUESTION AND ANSWER BOOK

2019MATHMETHEXAM1

2marks

1mark

Victorian Certificate of Education 2019

MATHEMATICAL METHODS Written examination 1

FORMULA SHEET

Instructions This formula sheet is provided for your reference. A question and answer book is provided with this formula sheet.

Students are NOT permitted to bring mobile phones and/or any other unauthorised electronic devices into the examination room.

© VICTORIAN CURRICULUM AND ASSESSMENT AUTHORITY 2019

MATHMETH EXAM

2

ateatica etod forua Mensuration area of a trapezium

1 ( a + b) h 2

volume of a pyramid

1 Ah 3

curved surface area of a cylinder

2  

volume of a sphere

4 3 πr 3

volume of a cylinder

2

area of a triangle

1 bc sin ( A ) 2

volume of a cone

1 2 πr h 3

Calculus d n n− 1 x = nx dx

∫ x dx = n + 1 x

1

n +1

d n−1 (ax + b )n = an ( ax + b ) dx

∫ ( ax + b)

dx =

1 (ax + b )n + 1 + c , n ≠ − 1 a( n + 1)

d ax e = ae ax dx



1 d ( loge (x )) = x dx

∫ x dx = log (x ) + c , x > 0

d (sin (ax) ) = a cos (ax ) dx

∫sin (ax)dx = − a cos(ax) + c

d ( cos (ax )) = − a sin (ax) dx

∫ cos (ax)dx = a sin (ax ) + c

( )

(

n

)

( )

e axdx =

n

+ c, n ≠ −1

1 ax +c ae

1

e

1

1

d a 2 = a sec ( ax ) (tan (ax) ) = 2 dx cos ( ax)

product rule

d (uv )= udv + v du dx dx dx

chain rule

dy dy du  dx du dx

quotient rule

du dv −u v d  u dx dx  = dx  v  v2

3

MATHMETH EXAM

Probability Pr(A  B) = Pr(A) + Pr(B) – Pr(A  B)

Pr(A) = 1 – Pr(A) Pr(A|B) =

Pr ( A∩ B ) Pr(B )

  E(X)

mean

var(X) =  2 = E((X –  )2) = E(X 2) – 2

variance

Probability distribution discrete

Pr(X  x)  p(x)

continuous

Pr(a < X < b ) =

Mean

Variance

   x p(x)



b

f (x )dx

a

µ=



 2   (x –  )2 p(x)



−∞

x f ( x) dx

σ2=





( x − µ ) 2 f ( x) dx

−∞

Sample proportions P 

X n

standard deviation

mean sd( ˆP) 

p(1  p) n

approximate confidence interval

E(P ) = p   ˆp  z  

END OF FORMULA SHEET

pˆ 1  pˆ n

, ˆp  z

pˆ 1  pˆ  n

   ...


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