48530 Lab 3 - Assignment PDF

Title 48530 Lab 3 - Assignment
Course Circuit Analysis
Institution University of Technology Sydney
Pages 6
File Size 828.4 KB
File Type PDF
Total Downloads 80
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Summary

Download 48530 Lab 3 - Assignment PDF


Description

Faculty of Engineering and Information Technology Subject:

48530 Circuit Analysis

Assessment Task:

Lab 3 Assignment – Power and Phase

Assessment Mark:

6%

Submission deadline:

6 pm, Friday 12 April 2019

Lateness penalty:

10% (i.e. 0.6) per calendar day, zero marks if > 5 days

Your details: Student Number

Family Name

First Name

Family Name

First Name

Your lab partners’ details: Student Number

Though your measurements will be identical to your partners and you may workshop the theory, you must prepare your own solutions to this Assignment and not copy a partner’s work. Complete the following declaration of originality and attach this as cover sheet for your assignment – otherwise you will have to resubmit it and a 0.2 mark penalty will be imposed. Declaration of Originality: The work contained in this assignment, other than that specifically attributed to another source, is that of the author(s). It is recognised that, should this declaration be found to be false, disciplinary action could be taken and the assignments of all students involved will be given zero marks. In the statement below, I have indicated the extent to which I have collaborated with other students, whom I have named. Signature Statement of Collaboration:

Question 1 (1 Mark) Question 2 (1 Mark) Your answer to Prework Question Q1.5 and Q.1.7 of the lab (Page L3.4) (Page L3.5) 1mm=1Vrms for question 1

Question 3 (1 Mark) v.1 25/3/2019

Your answer to Lab Work Q2 of the lab (Pages L3.9)

VR

VC

Ip

VC

(V) 0.2 10 20 30 40 50 60 70 80 90 94.1

(V) 105.6 105.5 104.4 102.8 99.8 96.4 92.1 85.7 77.2 65.8 59.4

(A) 0.67 0.656 0.644 0.628 0.608 0.588 0.568 0.524 0.468 0.4 0.358

2

R=

2

VR

VR +

(V) 105.6 105.97 106.30 107.09 107.52 108.60 109.92 110.65 111.17 111.49 111.28

 =

5*Pp

pf I p tan− 1  1  (by watt   meter) (by wattCR  

pf =

Pp

V p I p nclude correct sign +/−

meter)

(Ω) 0.30 15.24 31.06 47.77 65.79 85.03 105.63 133.59 170.94 225 262.85

(°) 89.90 84.53 78.96 73.29 67.54 61.89 56.43 50.00 42.96 35.27 31.19

(W) -9 -41 -73 -101 -129 -155 -176 -188 -194 -183 -172

Question 4 (1 Mark) Your answer to Lab Work Q3 of the lab (Pages L3.10 - L3.11)

-0.028 -0.124 -0.214 -0.306 -0.399 -0.490 -0.585 -0.670 -0.766 -0.844 -0.865

 = cos− 1( pf ) i

-0.026 -0.119 -0.216 -0.306 -0.404 -0.502 -0.590 -0.683 -0.790 -0.871 -0.915

(°) -88.40 -82.88 -77.53 -72.18 -66.48 -60.66 -53.84 -46.92 -37.81 -29.42 -30.12

Question 5 (1 Mark) v.1 25/3/2019

Your answer to Lab Work Q10 of the lab (Page L3.14 and table on page L3.15)

VR

IR

R = VR I R (Ω)

IP

pf

 = cos − 1 ( pf ) with

(by wattmeter)

(V) 0.8

(A) 0.998

0.802

0.748

-0.677

+/− (°) -47.39

10

0.981

10.19

0.802

-0.677

-47.39

20

0.965

20.73

0.862

-0.676

-47.47

30

0.946

31.71

0.918

-0.677

-47.39

40

0.915

43.72

0.976

-0.677

-47.39

50

0.88

56.82

1.028

-0.679

-47.23

60

0.834

71.94

1.068

-0.68

-47.16

70

0.772

90.67

1.102

-0.679

-47.23

80

0.701

114.12

1.126

-0.679

-47.23

90

0.591

152.28

1.122

-0.679

-47.23

100

0.417

239.81

1.068

-0.68

-47.16

Max =101

0.387

260.98

1.056

-0.679

-47.23

105 (from Q5)

0



(inbuilt meter)

(A)

Question 6 (1 Mark) Your answer to Lab Work Q11 of the lab (Page L3.16 and plot on page L3.15)

v.1 25/3/2019...


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