Title | B Tree Diagram Challenge |
---|---|
Course | Introduction to Quantitative Methods |
Institution | University of Tasmania |
Pages | 10 |
File Size | 261.1 KB |
File Type | |
Total Downloads | 7 |
Total Views | 161 |
week 6 lecture notes...
Name:
Class/Set:
Tree Diagrams - Independent Events
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1: A21 spinner has 1 orange section and 4 pink sections (all equal). It is spun twice. Use this tree diagram to answer the following: 1 5
4 5
1 5
orange
4 5
pink
1 5
orange
4 5
pink
orange
pink
a) What is the probability of getting orange twice?
____________________ b) What is the probability of not getting orange twice?
____________________ c) What is the probability of getting the same colour twice?
____________________ d) What is the probability of getting different colours?
____________________
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1 2: The probability of a biased coin landing Heads up is 0.9. 2 It is tossed twice. Complete this tree diagram and hence answer the following:
Heads Heads Tails Heads Tails Tails a) What is the probability of getting Tails twice?
____________________ b) What is the probability of not getting Tails twice?
____________________ c) What is the probability of getting the same result twice?
____________________ d) What is the probability of getting Heads exactly once?
____________________
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Answers: Tree Diagrams - Independent Events
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1:
1 2
1 5
orange
4 5
pink
1 5
orange
4 5
pink
0.9
Heads
0.1
Tails
0.9
Heads
0.1
Tails
orange
4 5
pink
1
a) p(getting orange twice) = 5
1 5
=
b) p(not getting orange twice) = 1
1 25 1 5
1 5
d) p(getting different colours) = 51
4 5
24 = 25
4 5
4 5
4 5
1 5
1
c) p(getting the same colour twice) = 5
2:
1 5
1 5
17 = 25
= 258
1 2
0.9
0.1
Heads
Tails
a) p(getting Tails twice) = 0.1 b) p(not getting Tails twice) = 1
0.1 = 0.01 0.1
c)p(getting the same result twice) = 0.9 d) p(getting Heads exactly once) = 0.9
0.1 = 0.99 0.9 0.1
0.1 0.1
0.1 = 0.82 0.9 = 0.18
Free worksheet created by MATHSprint. Tree Diagrams - Independent Events:1
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Name:
Class/Set:
Tree Diagrams - Conditional Events
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1: A21 bag contains 10 counters with the letters of the word STATISTICS written on them. A counter is chosen at random and not replaced before choosing another one. Use this tree diagram to answer the following: 3 10
7 10
2 9
vowel
7 9
consonant
3 9
vowel
6 9
consonant
vowel
consonant
a) What is the probability of getting two consonants?
____________________ b) What is the probability of getting vowel at least once?
____________________ c) What is the probability of getting exactly one vowel?
____________________ d) What is the probability of not getting exactly one vowel?
____________________
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2: A21 drawer contains 8 green socks and 2 orange socks. A sock is chosen at random and not replaced before choosing another one. Use this tree diagram to answer the following: 8 10
2 10
7 9
green
2 9
orange
8 9
green
1 9
orange
green
orange
a) What is the probability of getting two orange socks?
____________________ b) What is the probability of getting green at least once?
____________________ c) What is the probability of getting two socks of different colours?
____________________ d) What is the probability of getting two socks of the same colour?
____________________
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Answers: Tree Diagrams - Conditional Events
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1:
1 2
3 10
7 10
vowel
7 9
consonant
3 9
vowel
6 9
consonant
vowel
consonant
6 9
7
a) p(getting two consonants) = 10
42 = 157 = 90 6 9
7 10
b) p(getting vowel at least once) = 1
7 9
3
c) p(getting exactly one vowel) = 10
d) p(not getting exactly one vowel) = 103 2:
2 9
8 = 48 90 = 15
7 10
3 9
2 9
7 10
42 = 90 = 157 6 9
48 = 158 = 90
1 2
8 10
2 10
7 9
green
2 9
orange
8 9
green
1 9
orange
green
orange
2
a) p(getting two orange socks) = 10 b) p(getting green at least once) = 1
1 9
= 902 = 451
2 10
1 9
88 = 90 = 44 45 8
c) p(getting two socks of different colours) = 10 8
d) p(getting two socks of the same colour) = 10
2 9 7 9
2 10 2 10
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8 9 1 9
16 32 = 45 = 90
58 = 29 = 90 45
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Name:
Class/Set:
Tree Diagrams - Algebra Problems
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1 1: Work out the following: 2
A box contains a total of 4 balls; some are purple and the rest are pink. A ball is chosen at random, then replaced before choosing again. If p(two purple balls) = 161 then find how many purple balls there are. purple purple pink purple pink pink
____________________ 1 out the following: 2: Work 2
A pencil case contains a total of 8 pencils; some are red and the rest are green. A pencil is chosen at random, then replaced before choosing again. 49 then find p(one pencil of each colour). If p(two red pencils) = 64 red red green red green green
____________________
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1 3: Work out the following: 2
A drawer contains a total of 8 socks; some are white and the rest are black. A sock is chosen at random and not replaced before choosing another one. If p(two white socks) = 281 then find how many black socks there are. white white black white black black
____________________ 1 out the following: 4: Work 2
A bag contains a total of 10 sweets; some are brown and the rest are grey. A sweet is chosen at random and not replaced before choosing another one. 28 then find p(two grey sweets). If p(two brown sweets) = 45 brown brown grey brown grey grey
____________________
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Answers: Tree Diagrams - Algebra Problems 1:
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1 2 n 4 n 4
purple
purple 4
n 4 n 4
4
n
pink purple
pink
4
4
n 4
pink
n
p(two purple balls) = 4n 4 = 161 so n2 = 1 or n = 1 The box contains 1 purple ball. 2:
1 2 n 8 n 8
red
red 8
n 8 n 8
8
n
green red
green
8
8
n 8
green
n 8
49 = 64 so n2 = 49 or n = 7 8 n 7 p(one pencil of each colour) = 2 n 8 8 = 32.
p(two red pencils) = 8n
3:
1 2 1
n 7 n 8
white 8
n 7 n 7
8
n 8
white black white
black 7
n 7
n 1 1 so n2 p(two white socks) = 8n 7 = 28 The drawer contains 6 black socks.
black
n = 2 or n = 2
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4:
1 2 1
n n 10
9
brown
10 n 9
grey
n 9
brown
brown
10 n 10
grey 9
n 9
p(two brown sweets) = 10n p(two grey sweets) = 10 10n
1
n 9
2 = 28 45 so n 9 n 1 9 = 45.
grey
n = 56 or n = 8
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