Bibble Boi - Test answer sheet PDF

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1. In which of the following does the nitrogen atom have a formal charge of –1? A.

B.

C.

D.

E.

Answer: C C have formal charge 1 because nitrogen have 3 electron for bond formation but hare only 2 electron participate in bond formation with carbon atom so nitron have 1 electron remain so charge is -1.

2. Select the best Lewis structure for CNCl. A.

B.

C.

D.

E.

Answer:

3. Hydrazine, N2H4, is a good reducing agent that has been used as a component in rocket fuels. Which of the following is the best Lewis structure for Hydrazine? A.

C.

B.

D.

Answer: C H2NNH2 2N  2 x 5 = 10 4H  4 x 1 = 4 14

4. Select the correct electron configuration for Cu. A. [Ar]4s13d10 B. [Ar]4s24d9 C. [Ar]4s24p63d3 D. [Ar]4s23d9 E. [Ar]5s24d9 Answer: [Ar]4s13d10

5. "Electrons added to atomic orbitals of the same energy will remain unpaired with parallel spins until the subshell is more than half-filled" most accurately describes: A. the periodic law. B. the singularity rule. C. the Aufbau principle. D. the Pauli exclusion principle. E. Hund's rule.

6. Select the compound with the highest (i.e., most negative) lattice energy. A. LiBr(s) B. BaO(s) C. MgO(s) D. NaI(s) E. CaS(s) Answer: MgO(s) Lattice energy is directly proportional to the product of the charges of the ions, higher the charge of cation and anion, higher will be lattice energy of the solid. Also, lattice energy is inversely proportional to the internuclear distance or size of the ions. The charges on cation and anion of ionic solid CaS, BaO, and MgO is +2 and -2., and on Nal and LiBr is +1 and -1. So, the lattice energy of CaS, Ba0, and MgO is greater than Nal and LiBr. The internuclear distance between MgO will be minimum among the given solids. Therefore, the compound with highest Lattice energy is MgO.

7. Arrange the following bonds in order of increasing (lowest to highest) bond strength. A. C–I < C–Br < C–F< C–Cl B. C–Br < C–I < C–Cl < C–F C. C–I < C–Br < C–Cl < C–F D. C–F < C–Cl < C–Br < C–I E. None of these choices are correct. Answer: C. C–I < C–Br < C–Cl < C–F F,Cl.Br.I are VIIA group elements. In a group top to bottom bond strength decreases. C-F has strong bond C-I weak bond C-I...