CAD 3 Report for Weldments PDF

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Report for the weldments practice of CAD...

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GRIDFLEX FORMWORK REPORT Mechanical Design 1

Introduction GRIDFLEX FORMWORK is a specially designed construction platform that is simple and sequential in its assembly and components. It is used to easily assemble floors and to hold as cement is poured onto a flat level of plywood. It is made of only 2 to 4 components, making assembly and installation easy and efficient. Its material is Aluminum Alloy 6061, an extremely lightweight material and the design of the product allows for easy expansion or reduction in the size and scope of the project; its components being able to shift to any direction. It has a high safety factor due to the product being fixed to wall using cuffs and has minimal work hazards. The following report contains information regarding the products, their components and other critical details that contribute to the safety, efficiency, and ease of use of the GRIDFLEX FORM WORK.

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Product Specifications Name: Standard Element Material: Aluminum 6061 alloy Material thickness: 3mm Color: White Surface finished: white powder-coated Item no: 110038 Mass properties Density = 2.7 g/mm3 Mass = 28131.45 g Volume = 357603960 mm3 Surface area = 1954120 mm2 Center of mass: (mm) X = 0.00 Y = 80.35 Z = -490.00

Name: Filler Element Cross Material: Aluminum 6061 alloy Material thickness: 3 mm Color: red Surface finished: red powder-coated Item no: 110040 Mass properties Density = 2.7 g/mm3 Mass = 29471.45 g Volume = 376159647.6 mm3 Surface area = 2055517.2 mm2 Center of mass: (mm) X = -684.50 Y = -11.07 Z = 78.77 Name: Filler Element Longitudinal Material: Aluminum 6061 alloy Material thickness: 3 mm Color: yellow Surface finished: yellow powder-coated Item no: 110486 Mass properties Density = 2.7 g/mm3

Mass = 21704.22 g Volume = 269727360 mm3 Surface area = 1473920 mm2 Center of mass: (mm) X = -684.99 Y = 81.01 Z = 0.00

Name: Filler Element Longitudinal Material: Aluminum 6061 alloy Material thickness: 3mm Color: yellow Surface finished: yellow powder-coated Item no: 110646 Mass properties Density = 2.7 g/mm3 Mass = 8233.66 g Volume = 70768954 mm3 Surface area = 386715 mm2 Center of mass: (mm) X = -860.92 Y = 84.51 Z = -103.50

Engineering Analysis Standard Element Beam Area = 762.49 mm2 Centroid relative to output coordinate system origin: (mm) X = 0.00 Y = 54.83 3

Z = 0.00 Moments of inertia of the area, at the centroid: (mm4) Lxx = 887176.53

Lxy = 0.00

Lxz = 0.00

Lyx = 0.00

Lyy = 168766.92

Lyz = 0.00

Lzx = 0.00

Lzy = 0.00

Lzz = 1055943.45

Polar moment of inertia of the area, at the centroid = 1055943.45 mm4 Angle between principal axes and part axes = -90.00 degrees Principal moments of inertia of the area, at the centroid: (mm4) Mx = 168766.92 My = 887176.53 Calculations Use My = 887176.53 mm4 to calculate deflection on a cross section of the standard beam -

The surface area to pour the concrete on one standard element is 1994 x 980 mm 2 The concrete thickness is 100 – 150 mm* Volume of concrete is 1.954 x 0.15 = 0.2931 m3 Concrete density: 2400 kg/m3 Mass of concrete: 2400 x 0.2931 = 703.44 kg Concrete weight over one standard beam element: 703.44 x 9.81 = 6900.75 N Since a Standard Element has 6 standard beams: 6900.75 / 6 = 1150.13 N Length of standard element beam = 1994 mm Uniform Distributed Load: 1150.12 / 1994 = 0.5768 N/mm

Free Body Diagram

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Vertical Forces

+↑ ∑ Fy=0 Ay + By – 1150.139 = 0 Ay + By = +1150.139 N Sum of Moments about left support

+↻ ∑ M =0 By (1994 – 0) + (-1150.139)(997) = 0 By = 575.07N Shear Force Diagram

Bending Moment Diagram

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Modulus of Elasticity of Aluminum 6061 Alloy: 6.9 x 103 MPa Max Allowable Deflection of cross-section: 1994 / 400 = 4.985 mm Given:

δ max=

5 w L4 384 E I y

I y=

5 w L4 384 E δmax

I y=

5 (0.5768 )1994 384 ( 6.9 x 10 3) 4.985

4

I y =344418 mm

4

Max Bending: 286672.95 N.mm

Bending Stress=

Bending Stress=

My I

286672.954 ×50 =¿ 41 MPa 344418

Aluminum 6061’s UTS = 310 MPa Factor of Safety =

UTS 310 =7. 5 = Bending stress 41

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Bracket Support Beam Area = 605.37 mm2 Centroid relative to part origin: (mm) X = -17.20 Y = 43.98 Z = 0.00 Moments of inertia of the area, at the centroid: (mm4) Lxx = 524649.33 Lyx = 70671.67 Lzx = 0.00

Lxy = 70671.67 Lyy = 144461.50

Lxz = 0.00 Lyz = 0.00

Lzy = 0.00

Lzz = 669110.83

Polar moment of inertia of the area, at the centroid = 669110.83 mm4 Angle between principal axes and part axes = -79.80 degrees Principal moments of inertia of the area, at the centroid: (mm4) Mx = 131749.64 My = 537361.19 Calculations -

Using My = 537361.19 mm4 to calculate deflection on a cross section of the standard beam Each standard element has two supporting brackets, thus each cross member is to support 6900.75 ÷ 2 = 3450.375 N The beam is 980 mm in length Uniformly distributed load is 3450 ÷ 980 = 3.5 N/mm

Free Body Diagram

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Vertical Forces

+↑ ∑ Fy=0 Ay + By – 3430 = 0 Ay + By = 3430 N Sum of Moments about left support

+↻ ∑ M =0 By (980 – 0) + (-3430)(490) = 0 By = 1715 N Shear Force Diagram

Bending Moment Diagram

Modulus of Elasticity of Aluminum 6061 Alloy: 6.9 x 103 MPa 8

Max Allowable Deflection of cross-section: 980 / 400 = 2.46 mm Given:

δ max=

5 w L4 384 E I y

I y=

5 w L4 384 E δmax

I y=

5(3.5 ) 9804 384 ( 6.9 x 103) 2.46

I y =247643 mm4 Max Bending: 420175 N.mm

Bending Stress=

Bending Stress=

My I

420175 × 44 =¿ 74.65 MPa 247643

Aluminum 6061’s UTS = 310 MPa Factor of Safety =

310 UTS = =4.15 Bending stress 74.65

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Rectangular Bar Area = 564 mm2 Centroid relative to part origin: (mm) X = 0.00 Y = -37.50 Z = 0.00 Moments of inertia of the area, at the centroid: (mm4) Lxx = 414867.49

Lxy = 0.00

Lyx = 0.00

Lyy = 57738.17

Lzx = 0.00

Lzy = 0.00

Lxz = 0.00 Lyz = 0.00 Lzz = 357129.32

Polar moment of inertia of the area, at the centroid = 414867.49 mm4 Angle between principal axes and part axes = -0.00 degrees Principal moments of inertia of the area, at the centroid: (mm4) Ix = 57738.17 Iy = 357129.32 Calculations -

Using My = 357129.32 mm4 to calculate deflection on a cross section of the standard beam The surface area to pour the concrete on one standard element is 1980 x 1041 mm 2 The concrete thickness is 100 – 150 mm* Volume of concrete is 2.061 x 0.15 = 0.30915 m3 Concrete density: 2400 kg/m3 Mass of concrete: 2400 x 0.2931 = 703.44 kg Concrete weight over one standard beam element: 2.061 x 9.81 = 7269.21 N Since a Standard Element has 7 standard beams: 6900.75 / 7 = 985.82 N Length of Rectangular Bar = 1980 mm Uniform Distributed Load: 985.82 / 1980 = 0.4979 N/mm

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Free Body Diagram

Vertical Forces

+↑ ∑ Fy=0 Ay + By – 985.842 = 0 Ay + By = 985.842 N Sum of Moments about left support

+↻ ∑ M =0 By (1980 – 0) + (-985.842)(990) = 0 By = 492.921 N Shear Force Diagram

Bending Moment Diagram

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Modulus of Elasticity of Aluminum 6061 Alloy: 6.9 x 103 MPa Max Allowable Deflection of cross-section: 1980 / 400 = 4.95 mm Given:

δ max=

5 w L4 384 E I y

I y=

5 w L4 384 E δmax

I y=

5(0.4979) 1980 384 ( 6.9 x 103) 4.95

4

I y =291734 mm

4

Max Bending: 243995.865 N.mm

Bending Stress=

Bending Stress=

My I

243995.865 ×37.5 =¿ 31.36 MPa 291734

Aluminum 6061’s UTS = 310 MPa Factor of Safety =

310 UTS = =9.88 Bending stress 31.36

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