Title | Chapter 5 Homework Solutions 2 |
---|---|
Course | Organic Chemistry I Honors |
Institution | University of Alabama at Birmingham |
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Mission College CHEM-012A Dr. Baker Answers for Chapter 6 – Alkenes: Structure and Reactivity Calculate the degree of unsaturation in each formula below. Show your calculations. Q1. Pinene, ! C10 H18 Answer: The saturated ten carbon compound would have 22 hydrogens so the number of degrees of ( ) un...
Mission College CHEM-012A Dr. Baker Answers for Chapter 6 – Alkenes: Structure and Reactivity Calculate the degree of unsaturation in each formula below. Show your calculations. Q1. Pinene, ! C10 H18 Answer: The saturated ten carbon compound would have 22 hydrogens so the number of degrees of ( )÷ = ÷ = unsaturation is: ! 22 − 18 2 4 2 2 Q2.
3.
Eicosapentaenoic acid, C20H30O2, a constituent of fish oil Answer: Oxygen does not affect the base formula which in this case is C20H30. The saturated 20 carbon compound would have 42 hydrogens so the number of degrees of unsaturation for eiscosapentaenoic acid is: (42 – 30) ÷ 2 = 12 ÷ 2 = 6. C H N OCl Diazepam (Valium), ! 16 13 2 Answer: Oxygen does not affect the base formula. A hydrogen is added to the base formula for each halogen and subtracted for each nitrogen so the base formula for diazepam is . The saturated 16 carbon compound would have 34 hydrogens so the number of degrees of unsaturation for diazepam is: (34 -- 12) / 2 = 22 / 2 = 11.
Dieldrin, C12H8Cl6O, is a pentacyclic compound formerly used as an insecticide. Q4. Calculate the degree of unsaturation for Dieldrin. Show calculations for credit. Answer: Oxygen does not affect the base formula. A hydrogen is added to the base formula for each halogen so the base formula for dieldrin is C12H14. The saturated 12 carbon compound would have 26 hydrogens so the number of degrees of unsaturation for dieldrin is (26 -- 14) / 2 = 12 / 2 = 6. 5.
How many double bonds does dieldrin have? Answer: Dieldrin has 6 degrees of unsaturation and it is pentacyclic, meaning it has 5 rings. Therefore, dieldrin must have one double bond.
Draw structures corresponding to each name below. Either condensed or line structures may be used. 6. Answer: (CH3)2C
CH3
CHCH2
or
C
C
H
CH
CH2
7. Answer: CH3
or
8.
cis-2Answer:
hexene
CH3
H3C or
CH2CH2CH3 C
H
Q9.
trans-4,4-dimethyl-2-pentene Answer: H3C
H C
or H
C C(CH3)2CH3
C H
2-Pentene is an example of a disubstituted alkene.
CH3CH
CHCH2CH3
Q10.
Draw the cis and trans isomers of 2-pentene and label them. Answer:
Q11.
Circle the isomer which is most stable. H3C
H3C
CH2CH3 C
H
C
H H3C
C H CH2CH3
cis C
CH H 2CH3
H3C H
trans C C
C
H
C
H
CH2CH3
H
cis
trans
Answer: Provide names for each structure below. Be sure to include the cis, trans or E, Z designations where applicable. Q12.
Answer: trans-2-methyl-3-hexene or (E)-2-methyl-3-hexene Q13.
Answer: 3-methylcyclopentene Q14.
Q15.
CH2CH2CH3 H2C
CH2CH3
CHC(CH3)2CH C
C
H
H
Answer: cis-3,3-dimethyl-4-propyl-1,5-octadiene or (Z)-3,3-dimethyl-4-propyl-1,5-octadiene Rank each set of substituents using the Cahn-Ingold-Prelog sequence rules by numbering the highest priority substituent 1 and numbering the lowest priority substituent 4. Place the number in the blank below the substituent. Q16. CH CH CH 2
H2C
2
CHC(CH3)2CH C
C
H
Answer:
3
CH2CH3 H
O C
H
CH
1
Q17.
CHCH3 4
NCH3 2
O NHCCH3
CH
C
H
CH
C
CH3
3
CH3
CH3 C
C
CH3
CH
OH
Answer: O
CH3
CH3 C
NHCCH3 1
C
H
CH
CH
CH3
4
3
Q18.
OH
2
O CH2
C
I
N
OH
C
OCH3
CH
CHCH3
Answer: O CH2
I
1
Q19.
C
N
OH
3
CH2 OH
C
C
OCH3
CH
2
N
CH2
CHCH3
4
Cl
CH
CH2
Answer: CH2 OH
C
N
3
2
CH2 1
Cl
CH
CH2
4
MATCH each alkene below with the appropriate heat of hydrogenation. Place the letter of the correct answer in the blank to the left of the alkene. a. 125.9 kJ/mol Q20.
H3C
H
b. 118.4 kJ/mol
c. 115.5 kJ/mol
H
CH3
Answer: c Q21.
H
H
H
CH3
Answer: a Q22.
H3C
H Answer: b 23.
CH2CH3
H
Arrange the following bicyclic alkenes in order of increasing stability (least stable to most stable).
II
I
a.
III < II < I
b.
III
I < II < III
c.
I < III < II
d.
II < III < I
Answer: d Assign E or Z configurations to each alkene below. H3C
CH3
Q24. Br
CH2CH3
Answer: Z CN
Q25.
CH2CH2OH
CH3
Answer: E Q26.
O H3COC
O
C
CH3 C
CH2
C
CH
OH
Answer: E MATCH each definition to the term it describes. Place the letter corresponding to the term in the blank to the left of the definition. a. Hammond Postulate
b. Cahn-Ingold-Prelog Rules
c. Markovnikov’s Rule
Q27.
Predicts that the more stable carbocation intermediate is formed in electrophilic additions to alkenes. Answer: c
Q28.
Predicts that the transition state of an exergonic reaction step structurally resembles the reactant. Answer: a
Q29.
Assigns priorities to the substituent groups on a carbon. Answer: b
Q30.
Predicts that the transition state of an endergonic reaction step structurally resembles the product. Answer: a
Q31.
_____ Predicts that in additions of HX to alkenes, the H adds to the less substituted alkene carbon and the X adds to the more substituted alkene carbon. Answer: c
Q32.
Rank the carbocations below in order of increasing stability (least stable = 1; most stable = 3). Place the number corresponding to the carbocation’s relative stability in the blank below the structure. + + +
Answer: + + + 3
1
2
Consider the following reaction: CH3
CH3 +
Q33.
HCl
Cl
Write the complete stepwise mechanism for this reaction. Show all intermediate structures and show all electron flow using the curved arrow convention. Answer: CH3 H
+
Cl
_ Cl
H H
Q34.
CH3
CH3
Cl
H
Draw a qualitative reaction energy diagram for this reaction. Label the positions of all reactants, intermediates and products. Answer:
first TS second TS =/ ΔG1
Energy
=/ ΔG2 intermediate
reactants ΔG0 products
Reaction Progress
Consider the following reaction: Cl (CH3)3CCH
Q35.
CH2
+
(CH3)3CCHCH3
HCl
+
(CH3)2CCHCH3
Cl
CH3
A 50%
B 50%
Below are all the chemical structures and intermediates involved in this reaction. On the structures provided, show all electron flow using the arrow formalism for the complete stepwise mechanism for this reaction. _ Cl
Pathway A
(CH3)3CCH
CH2
H
Cl
(CH3)3CCH +
CH3
(CH3)3CCHCH3 Cl
Pathway B
A
CH3 (CH3)2C
CH3 CH +
CH3
(CH3)2C +
CH
_ CH3
Cl
Cl (CH3)2CCHCH3 CH3 B
Answer: _
Pathway A
(CH3)3CCH
H
CH2
Cl
(CH3)3CCH +
(CH3)3CCHCH3
Cl
CH3
Cl Pathway B
A CH3
CH3 (CH3)2C
CH +
CH3
(CH3)2C +
CH
Cl
_ CH3
(CH3)2CCHCH3
Cl
CH3 B
Q36.
Why does the rearrangement that results in the formation of product B occur? Answer: The 1,2-alkyl shift is the rearrangement of a secondary carbocation to a more stable tertiary carbocation.
Q37.
Write the complete stepwise mechanism for the following reaction. Show all intermediate structures and all electron flow with arrows. H3C
H3C
CH3
Br CH3
HBr
Answer: Predict the major organic product for each reaction below. Q38.
CH3
H3C
HI3 CH
H3C
H
_
+
Br
+ H
Answer: CH3
H3C
I
HI
Q39.
HCl ether
Answer: HCl ether Cl
Q40.
HBr
Answer: Br HBr
CH3
CH3 Br
+
H3C CH3
_ Br
Br CH3
Q41.
KI H3PO4
Answer:
I KI H3PO4
Predict the structure of the alkene you would use to prepare each alkyl halide below. Br
Q42. (only product)
Answer:
Q43. Answer: I
I
CH3CHCH2CHCH3
The reaction of isobutene with HBr in ether gives one of the two products below as the major product. Answer the following questions about this reaction. Br HBr
Br
+
ether Product A
!
Product B
Q44.
Which product would be the major product? Answer: Product B
Q45.
Which product would be formed via a primary carbocation? Answer: Product A
Q46.
Which product would have a higher energy transition state for the formation of the intermediate leading to it? Answer: Product A
Q47.
Which product is the non-Markovnikov product? Answer: Product A
Q48.
According to Hammond’s Postulate, which product would have a transition state structure most closely resembling the carbocation intermediate? Answer: Product A
Q49.
Which product would be formed by a carbocation experiencing the greatest degree of hyperconjugative stabilization? Answer: Product B
Q50.
Increasing the temperature at which the reaction is run would lead to an increase in the percentage of which product relative to the other product? Answer: Product A...