Experiment 8 AC power analysys & design PDF

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Warning: TT: undefined function: 32 Warning: TT: undefined function: 3Experiment 8AC Power Analysis and DesignOBJECTIVE:Practice AC circuit power analysis and maximum power transfer design.Equipment Required: 1 - Digital Multimeter 1 - Waveform Generator 1 – Digital Oscilloscope 1 - Protoboard 1 - R...

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Experiment 8 AC Power Analysis and Design OBJECTIVE: Practice AC circuit power analysis and maximum power transfer design. Equipment Required: • 1 - Digital Multimeter • 1 - Waveform Generator • 1 – Digital Oscilloscope • 1 - Protoboard • 1 - RCL Meter (shared) • 1 - 820-Ω Resistor • 1 - 10-Ω Resistor • 1 - 1-mH Inductor • 1 - 100-mH Inductor

Prelab: •

We connect the following circuit

Calculations: ω = 2πf = 6283 rad/s In phase domain: 𝑍𝐿 = 2π j = 6.283j 𝑍𝐿 = 200π j = 628.3j

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Using phasor analysis methods to find 𝑉𝐿 and 𝐼𝐿 ∶

⇒ 3.495 < 0.06𝑉

⇒ 3.38 ∗ 10−3 < −37.4𝑚𝐴

𝑆𝑡𝑟 = 𝑃𝑡𝑟 + j 𝑄𝑡𝑟 𝑆𝐿 = 𝑃𝐿 + j 𝑄𝐿

Ptr = Rtr × 𝐼 2 = 10 × (3.38 × 10−3 )2 = 1.14 × 10−4 ; 𝑄𝑡𝑟 = 𝐿𝑊𝐼 2 = 0.001 × 2000𝜋 × (3.38 × 10−3 )2 = 7.17 × 10−5 Str = 1.14 ×10−4 + j 7.17 × 10−5 = 1.34 × 104 ∠32.16 𝑃𝐿 = 𝑅𝐼 2 = 820 × (3.38 × 10−3 )2 = 0.0094 𝑄𝐿 = 𝐿𝑊𝐼 2 = 100×10−3 × 2000𝜋 × (3.38 × 10−3 )2 = 7.17 × 10−3 SL = 0.0094 + j 7.17 × 10−3 = 0.0118∠37.33 St = SL + Str = 0.0094 + j 7.17 × 10−3 + 1.14 × 10−4 + j 7.17 × 10−5 = 0.0119∠37.27

procedure:

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1. Calculation of 𝑽𝑳 and the complex powers using the real value of the elements: For the same ω = 2πf = 6283 rad/s In phase domain: ZL1 = jwL1 = 6.2377624j ZL = jwl2 = 644.6358j 𝑉𝐿 =

⇒ 3.37200 × 10−3 − 38.3727 A

Ptr = Rtr × 𝐼 2 = 10 × (3.37 × 10−3 )2 = 1.137 × 10−4 ; 𝑄𝑡𝑟 = 𝐿𝑊𝐼 2 = 0.9928 × 10−3 × 2000𝜋 × (3.27 × 10−3 )2 = 6.67 × 10−5 Str = Ptr + 𝑄𝑡𝑟 =1.137 ×10−4 + j 6.67 × 10−5 𝑃𝐿 = 𝑅𝐼 2 = 812 × (3.37 × 10−3 )2 = 9.2218 × 10−3 𝑄𝐿 = 𝐿𝑊𝐼 2 = 102.6×10−3 × 2000𝜋 × (3.37 × 10−3 )2 = 7.32128 × 10−3 SL =𝑃𝑙 + 𝑄𝑙 = 9.2218× 10−3 + j 7.32128 × 10−3 St = SL + Str = 1.137 × 10−4 + 9.2219 × 10−3 + (6.67 × 10−5 + 7.32128 × 10−3 ) j

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⇒ 9.3356 × 10−3 + 𝒋 7.387 × 10−3

2. AC Power Analysis:

3. Power factor correction:

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4. Maximum power transfer: We choose the following design

Conclusion

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• Complex power at the Load:

⇒ The power factor is equal to cos (52.1˚) = 0.677

Power Factor correction

Power Savings

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As a conclusion from this experiment, the concept of power and how power can be delivered to the loads was proofed. As for the errors, the difference between the calculated and measured cause some kind of error which it is acceptable.

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