Inverse Laplace Transform General Properties Questions and Answers - Sanfoundry PDF

Title Inverse Laplace Transform General Properties Questions and Answers - Sanfoundry
Author code with joey
Course multivariable calculus MCQS
Institution Government College University Faisalabad
Pages 7
File Size 188.4 KB
File Type PDF
Total Downloads 14
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3/31/2021

Inverse Laplace Transform General Properties Questions and Answers - Sanfoundry



Ordinary Dierential Equations Questions and Answers – General Properties of Inverse Laplace Transform « Prev

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This set of Ordinary Dierential Equations Multiple Choice Questions & Answers (MCQs) focuses on “General Properties of Inverse Laplace Transform”. 1. Find the \(L^{-1} (\frac{s+3}{4s^2+9})\). a) \(\frac{1}{4} cos(\frac{3t}{2})+\frac{1}{2} cos(\frac{3t}{2})\) b) \(\frac{1}{4} cos(\frac{3t}{4})+\frac{1}{2} sin(\frac{3t}{2})\) c) \(\frac{1}{2} cos(\frac{3t}{2})+\frac{1}{2} sin(\frac{3t}{2})\) d) \(\frac{1}{4} cos(\frac{3t}{2})+\frac{1}{2} sin(\frac{3t}{2})\) View Answer

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Inverse Laplace Transform General Properties Questions and Answers - Sanfoundry

2. Find the \(L^{-1} (\frac{1}{(s+2)^4})\). a) \(e^{-2t}×3\) b) \(e^{-2t}×\frac{t^3}{3}\) c) \(e^{-2t}×\frac{t^3}{6}\) d) \(e^{-2t}×\frac{t^2}{6}\) View Answer 3. Find the \(L^{-1} (\frac{s}{(s-1)^7})\). a) \(e^{-t} \left (\frac{t^6}{5!}+\frac{t^5}{6!}\right )\) b) \(e^t \left (\frac{t^6}{5!}+\frac{t^5}{6!}\right )\) c) \(e^t \left (\frac{t^6}{6!}+\frac{t^5}{5!}\right )\) d) \(e^{-t} \left (\frac{t^6}{6!}+\frac{t^5}{5!}\right )\) View Answer 4. Find the \(L^{-1} (\frac{s}{2s+9+s^2})\). a) \(e^{-t} \{cos(2\sqrt{2t})-sin(\sqrt{2t})\}\) b) \(e^{-t} \{cos(2\sqrt{2t})-sin(2\sqrt{2t})\}\) c) \(e^{-t} \{cos(2\sqrt{2t})-cos(\sqrt{2t})\}\) d) \(e^{-2t} \{cos(2\sqrt{2t})-sin(2\sqrt{2t})\}\) View Answer 1} \left (\frac{(s+1)}{(s+2)(s+3)}\r

)\).

2e-3t-e-2t b) 3e-3t -e-2t c) 2e -3t-3e -2t d) 2e-2t -e-t

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Inverse Laplace Transform General Properties Questions and Answers - Sanfoundry

Answer: a Explanation: In the given question, \(L^{-1} \left (\frac{(s+1)}{(s+2)(s+3)}\right )=L^{-1} \left (\frac{2(s+2)-(s+3)}{(s+2)(s+3)}\right )\) =\(L^{-1} \left (\frac{2}{(s+3)}\right )+L^{-1} \left (\frac{1}{(s+2)}\right )\) =2e -3t-e -2t. advertisement

6. Find the \(L^{-1} \left (\frac{(3s+9)}{(s+1)(s-1)(s-2)}\right )\). a) e-t+6et+5e2t b) e-t -et+5e2t c) e -3t-6e t+5e 2t d) e-t -6et+5e2t View Answer Answer: d Explanation: In the given question, \(L^{-1} \left (\frac{(3s+9)}{(s+1)(s-1)(s-2)}\right )\) =\(L^{-1} \left (\frac{1}{(s+1)}\right )-6L^{-1} \left (\frac{-6}{(s-1)}\right )+5L^{-1} \left (\frac{-6}{(s2)}\right ) \)————-Using properties of Partial Fractions -t

t

2t

=e -6e +5e . 7. Find the \(L^{-1} (\frac{1}{(s^2+4)(s^2+9)})\). a) \(\frac{1}{5} \left (\frac{sin(2t)}{2}-\frac{sin(t)}{3}\right )\) b) \(\frac{1}{5} \left (\frac{sin(2t)}{2}+\frac{sin(3t)}{3}\right )\)

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Inverse Laplace Transform General Properties Questions and Answers - Sanfoundry

d) \(\frac{1}{5} \left (\frac{sin(2t)}{2}-\frac{sin(3t)}{3}\right )\) View Answer 8. Find the \(L^{-1} \left (\frac{s}{(s^2+1)(s^2+2)(s^2+3)}\right )\). a) \(\frac{1}{2} cos(t)-cos(\sqrt3t)-\frac{1}{2} cos(\sqrt3t)\) b) \(\frac{1}{2} cos(t)+cos(\sqrt2t)-\frac{1}{2} cos(\sqrt3t)\) c) \(\frac{1}{2} cos(t)-cos(\sqrt2t)-\frac{1}{2} cos(\sqrt3t)\) d) \(\frac{1}{2} cos(t)+cos(\sqrt2t)+\frac{1}{2} cos(\sqrt3t)\) View Answer 9. Find the \(L^{-1} \left (\frac{s+1}{(s-1)(s+2)^2}\right )\). a) \(\frac{2}{7} e^t-\frac{2}{9} e^{-2t}+\frac{1}{3} e^{-2t}×t\) b) \(\frac{2}{9} e^t-\frac{2}{9} e^{-2t}+\frac{1}{3} e^{-2t}×t\) c) \(\frac{2}{9} e^t-\frac{2}{9} e^{-3t}+\frac{1}{3} e^{-2t}×t\) d) \(\frac{2}{9} e^t-\frac{2}{9} e^{-2t}+\frac{1}{3} e^{-2t}\) View Answer

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10.

The

\(L^{-1}

\left

(\frac{3s+8}{s^2+4s+25}\right

)\)

is

\(e^{-st}

(3cos(\sqrt{21}t+\frac{2sin(\sqrt{21}t)}{\sqrt{21}})\). What is the value of s? a) 0 b) 1 c) 2

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Inverse Laplace Transform General Properties Questions and Answers - Sanfoundry

Answer: c Explanation: In the given question, \(L^{-1} \left (\frac{3s+8}{s^2+4s+25}\right )=L^{-1} \left (\frac{3(s+2)+2}{(s+2)^2+21}\right )\) By the rst shifting property =\(e^{-2t} L^{-1} \left (\frac{3s+2}{s^2+21}\right )\) =\(e^{-2t} L^{-1} \left (\frac{3s}{s^2+21}\right )+e^{-2t} L^{-1} \left (\frac{2}{s^2+21}\right )\) =\(e^{-2t} (3cos(\sqrt{21}t+\frac{2sin(\sqrt{21}t)}{\sqrt{21}})\). Sanfoundry Global Education & Learning Series – Ordinary Dierential Equations. To practice all areas of Ordinary Dierential Equations, here is complete set of 1000+ Multiple Choice Questions and Answers. Participate in the Sanfoundry Certication contest to get free Certicate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs! Telegram | Youtube | LinkedIn | Instagram | Facebook | Twitter | Pinterest « Prev - Ordinary Dierential Equations Questions and Answers – Laplace Transform of Periodic Function » Next - Laplace Transform Questions and Answers – Convolution

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