Title | Lie Groups for 2D and 3D Transformations (Ethan Eade) |
---|---|
Author | Mingyang Wang |
Course | Computer Vision II: Multiple view geometry |
Institution | Technische Universität München |
Pages | 25 |
File Size | 2.3 MB |
File Type | |
Total Downloads | 25 |
Total Views | 153 |
detailed information about Lie Group...
SO(3) SE(3) SO(2) SE(2) Sim(3)
SO(3)
R R
−1
∈ SO(3) = RT
so(3)
0 G1 = 0 0
so(3)
3×3 0 0 −1 , G 2 = 0 −1 0
0 0 1
so(3)
0 1 0 0 0 , G3 = 1 0 0 0
ω ω 1 G1 + ω 2 G2 + ω 3 G3
∈
∈
−1 0 0
R3 so(3)
ω ∈ so(3)
ω×
0 −ω 3 ω 2 exp (ω × ) ≡ exp ω 3 0 −ω 1 −ω 2 ω 1 0 1 2 1 = I + ω × + ω× + ω 3× + · · · 2! 3!
exp (ω × ) = I +
∞ X i=0
"
ω 2i+2 ω 2i+1 × × + (2i + 2)! (2i + 1)!
ω 3× = − ω T ω · ω × θ2 ω 2i+1 ×
≡ ωT ω = (−1)i θ 2i ω ×
ω 2i+2 ×
=
(−1)i θ 2i ω 2×
#
0 0 0
exp (ω × ) = = =
∞ X (−1)i θ 2i
!
∞ X (−1)i θ 2i
!
ω 2× (2i + 2)! i=0 i=0 1 θ2 θ4 θ2 θ4 2 + + − + · · · ω× + + · · · ω× I+ 1− 3! 4! 2! 5! 6! 1 − cos θ sin θ 2 ω× ω× + I+ θ θ2 I+
(2i + 1)!
ω× +
θ ω θ SO(3)
R
∈
so(3)
SO(3)
tr(R) − 1 θ = arccos 2 θ · R − RT ln (R) = 2 sin θ
ln (R)
ω θ 2 sin θ
θ
X AdjX
ω
∈
so(3), R ∈SO(3)
R · exp (ω ) =
exp (AdjR · ω) · R
exp (AdjR · ω) = ω =t·v
R · exp (ω) · R−1
t∈R
t
t=0
d d R · exp (t · v) · R−1 exp (AdjR · t · v) = t=0 t=0 dt dt 2 d d = R · t=0 I + (t · v)× + O t2 · R−1 I + (AdjR · t · v)× + O t dt t=0 dt (AdjR · v)× = R · v × · R−1 = (Rv)× =⇒ AdjR
=
R
SO(3)
R3
SO(3) R ∈SO(3)
x ∈ R3
x
R
y = f (R, x) = R · x f ∂y =R ∂x
∂y ∂R
= = = = =
∂ |ω=0 (exp (ω) · R) · x ∂ω ∂ |ω=0 exp (ω) · (R · x) ∂ω ∂ |ω=0 exp (ω) · y ∂ω G1 y G2 y G3 y −y×
x
f :G → G
G
exp (ǫ) · f (g) = f (exp (δ) · g ) ∂f ∂ǫ |δ=0 ≡ ∂δ ∂g ǫ ǫ
δ
ǫ = ∂f ∂g
≡
−1 log f (exp (δ) · g) · f (g ) −1 ∂ log f (exp (δ) · g ) · f (g ) ∂δ
|δ=0
f (g) = g G = SO(3) R0 R2 = f (R0 ) ≡ R1 · R0 so(3) exp (ǫ) · R2 = R1 · exp (ω) · R0 ǫ
∂R2 ∂R0
ω
−1 ∂ log (R1 · exp (ω) · R0 ) · (R1 · R0 )
ω=0
=
|ω=0 ∂ω h i ∂ −1 |ω=0 log exp AdjR1 · ω · R1 · R0 · (R1 · R0 ) ∂ω ∂ |ω=0 log exp AdjR1 · ω ∂ω ∂ |ω=0 AdjR1 · ω ∂ω AdjR1
=
R1
≡ = = =
SO(3)
so(3) Σ ∈ R3×3
R ∈SO(3)
S
ǫ S
∈
=
N (0, Σ)
exp (ǫ) · R
(R0 , Σ0 )
(R1 , Σ1 )
R0
R1
(R1 , Σ1 ) ◦ (R0 , Σ0 ) = R1 · R0 , Σ1 + R1 · Σ0 · R1T
(Rc , Σc )
Σc
= =
v Rc
−1 −1 Σ0 + Σ1−1
−1
Σ0 − Σ0 (Σ0 + Σ1 )
Σ0
≡ R1 ⊖ R0 = ln R1 · R−1 0 = exp Σc · Σ1−1 · v · R0
(R0 , Σ0 ) (R1 , Σ1 )
v
K −1
K ≡ Σ0 (Σ0 + Σ1 )
R0 ⊕ (K · v)
Rc
=
Σc
= exp (K · v) · R0 = (I − K) · Σ0 Σ0
Σ1
SE(3)
R
∈
C
= R
SO(3), t ∈ R3 R t ∈ SE(3) 0 1 t
SO(3)
C1 , C2 C1 · C2
C −1 1
∈
SE(3) R 2 t2 R 1 t1 = · 0 1 0 1 R 1 R 2 R 1 t2 + t1 = 0 1 T Tt R1 −R 1 = 0 1
T z w ∈ RP3 (λx ≃ x ∀λ ∈ R) R t C ·x = ·x 0 1 T R x y z + wt = w
x =
w=1
x
y
x w = 0,
x se(3)
4×4
so(3)
0 0 G1 = 0 0
0 0 G4 = 0 0
0 0 0 0 0 0 1 0
0 0 0 0 0 −1 0 0
se(3)
1 0 , 0 0
0 0 G2 = 0 0
0 0 0 0 , G5 = −1 0 0 0
0 0 0 0
0 0 0 0
0 1 , 0 0
0 0 G3 = 0 0
0 1 0 0 1 0 0 0 , G6 = 0 0 0 0 0 0 0 0
u ω
T
u1 G1 + u2 G2 + u3 G3 + ω 1 G4 + ω 2 G5 + ω 3 G6
u ω
se(3)
δ=
T
∈
−1 0 0 0
0 0 0 0
0 0 , 1 0
0 0 0 0 0 0 0 0
R6 se(3)
∈ se(3)
SE(3)
∈
se(3) ω× u exp (δ) = exp 0 0 2 1 ω× ω× u = I+ + 0 0 0 2!
u ω
∈
0 0 0 0
ω×u 0
1 + 3!
ω 3× 0
2 ω× u 0
+ ···
SO(3)
exp
V
ω× 0
u 0
=
V
=
exp (ω × ) Vu 0 1 1 1 2 I + ω × + ω× + · · · 3! 2!
"
# 2i+1 ω 2i+2 ω× × = I+ + (2i + 2)! (2i + 3)! i=0 ! ! ∞ ∞ X X (−1)i θ 2i (−1)i θ 2i = I+ ω 2× ω× + (2i + 3)! (2i + 2)! i=0 i=0 ∞ X
V
V
= =
1 θ2 θ2 θ4 θ4 1 − + + − + · · · ω× + + · · · ω 2× 2! 4! 5! 3! 6! 7! 1 − cos θ θ − sin θ 2 I+ ω× ω× + θ3 θ2
I+
u, ω
∈
θ
=
A = B
=
C
=
R
=
R3 √ ωT ω sin θ θ 1 − cos θ θ2 1−A θ2 2 I + Aω × + Bω×
V = I + Bω × + Cω×2 u R Vu exp = 0 1 ω A B V
C
θ2
1 1 V−1 = I − ω × + 2 2 θ ln()
A 2 ω× 1− 2B
SE(3) u = V−1 · t
ln(R)
SE(3)
SO(3)
R t δ= u ω ∈ se(3), C = 0 1 C · exp (δ ) = exp (AdjC · δ) · C T
∈SE(3)
exp (AdjC · δ) = AdjC · δ
C · exp (δ) · C −1 ! 6 X = C· δ i Gi · C −1
i=1 Ru + t × Rω = Rω R t× R = ∈ R6×6 0 R
=⇒ AdjC
C =
R 0
t 1
x ∈ R3
∈SE(3)
y
=
f (C, x) =
=
R·x+t
x
R
t
f ∂y =R ∂x SO(3)
·
x 1
x
∂y ∂C
=
=
C ∂C ∂C0
SO(3)
G1 y
· · · G6 y
−y×
I
≡
C1 · C0 ∂ = [C1 · exp (δ) · C0 ] ∂δ = AdjC1
SO(3)
SO(2)
∈ SO(2) = RT
R R so(2)
−1
so(2)
2×2
G=
0 1
−1 0
so(2)
θ θG θ ∈ so(2)
θ×
∈
∈
R so(2) θG
exp (θ× ) ≡ = =
−θ 0 1 1 2 I + θ× + θ × + θ×3 + · · · 2! 3! 1 −θ 2 0 −θ + I+ θ 0 0 2! exp
0 θ
0 −θ 2
1 + 3!
sin θ exp (θ× ) =
cos θ sin θ
− sin θ cos θ
SO(2)
R ∈ ln (R) = θ =
so(2)
SO(2) arctan (R21 , R11 )
SO(2)
SE(2)
SE(3)
SE(2)
R
∈
C
=
cos θ
∈ SO(2)
θ
SO(2), t ∈ R2 R t ∈ SE(2) 0 1
0 −θ 3
θ3 0
R
∈
SE(2) R 2 t2 R 1 t1 = · 0 1 0 1 R 1 R 2 R 1 t2 + t1 = 0 1 T Tt −R R1 1 = 0 1
C1 , C2 C1 · C2
C −1 1
x = C ·x = = w=1
t
x
R
y
R 0
t 1
x
w
T
∈ RP2
(λx ≃ x ∀λ ∈ R)
·x
y w
T
+ wt
x w = 0,
x se(2)
3×3
0 G1 = 0 0
0 0 0
1 0 0 , G2 = 0 0 0
0 0 0
0 0 1 , G3 = 1 0 0
se(2)
u1
u2
θ
T
u1 G1 + u2 G2 + θG3
u θ
T
∈ se(2)
∈
∈
R3 se(2)
−1 0 0
0 0 0
se(2)
δ=
∈
se(2) θ× u exp (δ) = exp 0 0 2 1 θ× θ× u = I+ + 0 0 0 2!
u θ
SE(2)
θ× u 0
+
1 3!
3 θ× 0
θ 2× u 0
SO(2)
exp
θ× 0
=
V
u 0
=
V
=
∞ X
i=0
2i θ× = 2i+1 θ× =
"
exp (θ× ) Vu 0 1 1 2 1 I + θ× + θ × + · · · 3! 2!
θ 2i+1 θ×2i × + (2i + 1)! (2i + 2)!
#
1 0 0 1 0 −1 (−1)i θ 2i+1 · 1 0 i 2i
(−1) θ ·
V
V
∞ X (−1)i θ 2i
θ 1 1 0 0 + · · 0 1 1 (2i + 1)! (2i + 2)! i=0 ! ! ∞ ∞ X X (−1)i θ 2i (−1)i θ 2i+1 1 0 = + · · 0 1 (2i + 1)! (2i + 2)! i=0 i=0
=
−1 0
0 −1 1 0
+ ···
θ θ2 θ4 1 0 − + + + ··· · V = 1− 0 1 2! 3! 5! 1 − cos θ sin θ 0 1 0 + · · = 1 0 1 θ θ 1 sin θ −(1 − cos θ ) = · 1 − cos θ sin θ θ
θ5 θ3 + + ··· 4! 6! −1 0
0 −1 · 1 0
V ln() Vu = t
SE(2) u
θ = ln(R)
sin θ θ 1 − cos θ B ≡ θ 1 A B −1 V = −B A A2 + B 2 −1 R t V ·t ln ∈ se(2) = θ 0 1 A ≡
SE(2)
δ=
θ
T
∈
se(2), C =
AdjC · δ
=
C·
u θ
3 X
δ i Gi
i=1
Ru + θ = =⇒ AdjC
R = 0
θ
t2 −t1 1
R 0 !
t 1
t2 −t1
∈SE(2)
· C −1
∈ R3×3
Sim(3)
SE(3
R
∈
T
=
T1 , T2 T1 · T2
T 1−1
SO(3), t ∈ R3 , s ∈ R R t ∈ Sim(3) 0 s−1
∈
Sim(3) R 2 t2 R 1 t1 · = −1 −1 0 s2 0 s1 R1 R2 R1 t2 + s2−1t1 = 0 (s1 · s2 )−1 T R1 −s1 RT1 t = 0 s1 s
x = T ·x = = ≃
x
y
T w ∈ RP3 t ·x −1
R 0 s R x
z
y z s−1 w
s R x
y
T z
w
+ wt T
(λx ≃ x ∀λ ∈ R)
+ wt
!
w=1 sim(3)
se(3)
0 0 G7 = 0 0
0 0 0 0 0 0 0 0 0 0 0 −1
sim(3)
T u ω λ
u1 G1 + u2 G2 + u3 G3 + ω 1 G4 + ω 2 G5 + ω 3 G6 + λG7
u ω λ
∈
R7 sim(3)
T u ω λ ∈ sim(3)
sim(3)
δ=
∈
Sim(3)
∈
sim(3) ω× u exp (δ) = exp 0 −λ 2 1 ω× ω× u = I+ + 0 λ 0 2!
ω × u − λu λ2
exp (ω × ) 0
Vu exp (−λ)
1 3!
+
3 ω× 0
ω 2× u − λω × u + λ2 u −λ3
se(3)
exp
ω× 0
u 0
=
V
=
n k ∞ X X (−λ) ω n−k × (n + 1)! n=0
k=0
k ∞ X ∞ X ω×n−k (−λ) (n + 1)!
=
k=0 n=k
k ∞ X ∞ j X ω × (−λ) (j + k + 1)! j=0
=
k=0
θ2 = ω T ω ω×
V
=
=
!
"
# 2i+1 ω 2i+2 ω× × + (−λ) I+ (2i + k + 2)! (2i + k + 3)! k=0 i=0 ! ! ! ∞ X ∞ X ∞ ∞ ∞ k k k X X X (−1)i θ 2i (−λ) (−1)i θ 2i (−λ) (−λ) ω 2× ω× + I+ (2i + k + 3)! (2i + k + 2)! (k + 1)! i=0 i=0
∞ k X (−λ) (k + 1)! k=0
k=0
∞ X
k=0
k
∞ X
k=0
+ ···
V
=
A = B C
= =
AI + Bω × + Cω 2× 1 − exp (−λ) λ ∞ ∞ X k X (−1)i θ 2i (−λ) (2i + k + 2)! k=0 i=0 ∞ X ∞ X k=0 i=0
k
(−1)i θ 2i (−λ) (2i + k + 3)!
B
B
= =
∞ X ∞ k X (−1)i θ 2i (−λ)
k=0 i=0 " ∞ X i=0
= =
=
=
(2i + k + 2)! ∞ X
k
(−λ) (−1) θ (2i + k + 2)! k=0 i 2i
#
" # ∞ ∞ X (−1)i θ 2i X (−λ)2i+k (2i + k + 2)! λ2i i=0 k=0 # " ∞ ∞ X (−1)i θ 2i X (−λ)m (m + 2)! λ2i m=2i i=0 #! " ∞ ∞ 2i−1 X (−λ)m X (−1)i θ 2i X (−λ)m − (m + 2)! λ2i (m + 2)! i=0 m=0 m=0 #! " ! 2i−1 ∞ ∞ ∞ X X (−1)i θ 2i X (−λ)m (−1)i θ 2i X (−λ)m − (m + 2)! λ2i λ2i m=0 (m + 2)! m=0 i=0 i=0
L ≡ B
∞ X (−1)i θ 2i λ2i i=0
"
∞ m X (−λ) (m + 2)! m=0
#!
! 2i−1 ∞ X (−1)i θ 2i X (−λ)m = L− λ2i m=0 (m + 2)! i=0 " #! ∞ i−1 2p 2p+1 X (−1)i θ 2i X (−λ) (−λ) = L− + (2p + 3)! λ2i p=0 (2p + 2)! i=0 ! i−1 ∞ X λ 1 (−1)i θ 2i X 2p − (−λ) = L− (2p + 2)! (2p + 3)! λ2i p=0 i=0 ∞ X (−1)i θ 2i 1 λ 2p (−λ) − = L− λ2i (2p + 2)! (2p + 3)! p...