Title | Math304 Practice Exams |
---|---|
Course | Linear Algebra |
Institution | Binghamton University |
Pages | 5 |
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Practice exams for Linear Algebra course....
Math 304-6
Linear Algebra
Spring 2020
Practice Exam 3
Feingold
SHOW ALL NECESSARY WORK. Note: AT means the transpose of A. (1) (20 Pts) Let L : R22 → R2 be given by
a L c
b a + 2b + 3c + 4d . = −a + b + 2c − 3d d
Let S = {v1 , v2 , v3 , v4 } be the standard basis of R22 and let T = {w1 , w2 } be the standard basis of R2 . Let other ordered bases be 3 2 1 0 0 0 0 1 1 1 ′ ′ ′ ′ . , w2 = S = , , , and T = w1 = 0 1 1 1 1 0 2 1 0 ′1 ′ ′ ′ v1
v2
v3
v4
(a) (4 pts) Find the matrix T [L]S representing L from S to T . (b) (4 pts) Find the matrix T ′ [L]S ′ representing L from S ′ to T ′ without using transition matrices. (Do it directly.) (c) (12 pts) Find the transition matrices S PS ′ and T QT ′ and verify that your answers satisfy T ′ [L]S ′ = (T QT ′ )−1 T [L]S (S PS ′ ) .
(2) (15 Points, 3 points each) Answer each question separately. (a) If A ∈ Rnn and the homogeneous linear system AX = 0 has only the trivial solution, then what is the most you can say about det(A)? (b) Let L : V → V and suppose v ∈ V is an eigenvector for L with eigenvalue λ. Show that v is an eigenvector for L2 with eigenvalue λ2 . Do not assume L is diagonalizable. (c) Suppose A ∈ Rnn has characteristic polynomial det(λIn − A) = (λ − λ1 )k1 (λ − λ2 )k2 · · · (λ − λr )kr with r distinct real eigenvalues λ1 , λ2 , · · · , λr . For each 1 ≤ i ≤ r, what is the most you can say about the relationship between the algebraic multiplicity ki and the geometric multiplicity gi = dim(Aλi )? (d) In part (c), if you also know that A is diagonalizable, what else can you say about the relationship between ki and gi for each i? (e) Let E ∈ Rnn be an elementary matrix corresponding to an elementary row operation R, let A ∈ Rnn and let B be the matrix obtained by doing the row operation R to A. What is the relationship between det(A), det(B) and det(E)?
(3) (20 Points, 3 points each, (a) worth 8 pts) Answer each question separately. 2 3 4 1 1 1 −1 −1 (a) Find det . 3 2 1 1 4 4 −2 −3 (b) If det(A) = 10, det(B) = 4 and det(C) = 3, find det(A−1 B 2 C T ). (c) Suppose S is a basis of V , T is a basis of W , dim(V ) = n, dim(W ) = m. Then for any linear L : V → W we defined a map T MS : Lin(V, W ) → Rnm by T MS (L) = m T [L]S . What property of the map T MS implies dim(Lin(V, W )) = dim(Rn )? n are similar, that is, B = P −1 AP for some invertible P ∈ Rn . (d) Suppose A, B ∈ Rn n What is the relationship between the characteristic polynomials CharA (λ) = det(λIn − A) and CharB (λ) = det(λIn − B)? (e) For A ∈ Rnn we know that CharA (λ) is a polynomial in the variable λ of degree n. What is the constant term of that polynomial? 7 −4 2 (4) (20 Points) Let A = 4 −1 2 . 4 −4 5 (a) (8 Pts) Find the characteristic polynomial of A, det(λI3 − A), find all eigenvalues, λi , of A and the corresponding algebraic multiplicities, ki . (b) (8 Pts) For each eigenvalue, λi , of A, find a basis for the eigenspace, Aλi , and the geometric multiplicity gi = dim(Aλi ). (c) (4 Pts)Determine whether or not A is diagonalizable. If it is, find D and P such that D = P −1 AP is diagonal. If not, explain why.
Math 304-6
Linear Algebra
Spring 2020
Practice Exam 3 Solutions
Feingold
1. (20 Points)
1 2 3 4 (a) (4 Pts) Find L(S): L(v1 ) = , L(v2 ) = , L(v3 ) = , L(v4 ) = . −3 −1 1 2 1 0 1 2 3 4 so [L] = 1 2 3 4 . Then [T | L(S)] = S T 0 1 −1 1 2 −3 −1 1 2 −3 T L(S)
7 5 7 5 ′ ′ ′ , L(v2 ) = , L(v3 ) = , L(v4 ) = . (b) (4 Pts) Find L(S ): = −3 −4 −1 3 5 7 5 22 17 1 1 0 23 2 3 7 Row reduce to 0 1 −13 −13 −9 1 1 2 −3 −4 −1 3 I2 T′ L(S ′ ) T ′ [L]S ′ 1 1 0 0 2 3 1 0 0 1 (c) (12 Pts) S PS ′ = since S and T are the standard and T QT ′ = 0 0 1 1 1 2 1 1 1 0 bases. To get T ′ QT = (T QT ′ )−1 , reduce ′
L(v1′)
2 1
(T QT ′ )−1 T [L]S (S PS ′ ) =
T′
3 1 2 0
0 1 0 2 −3 to 0 1 −1 2 1 I 2 T ′ QT T
2 −3 −1 2
1 −1
2 3 4 1 2 −3
1 1 0 1
5 1 0 −3 0 1
2 −3 −1 2
1 −1
2 −3 −1 2
7 −3
17 −10
1 1 0
0 0 1 1
0 0 1 1
0 1 = 1 0
0 23 22 17 1 1 = T ′ [L]S ′ checks. Also, = 1 −13 −13 −9 1 1 0 1 1 0 0 2 3 4 1 0 0 1 = 1 2 −3 0 0 1 1 1 1 1 0 23 22 17 1 5 7 5 . = −13 −13 −9 1 −4 −1 3
1 0 0 1
1 0 0 1
(2) (15 Points, 3 points each) Answer each question separately. (a) If A ∈ Rnn and the homogeneous linear system AX = 0 has only the trivial solution, then A has rank n and is invertible so det(A) 6= 0. (b) Let L : V → V and suppose v ∈ V is an eigenvector for L with eigenvalue λ. Then L(v) = λv so L2 (v) = L(L(v)) = L(λv ) = λL(v) = λλv = λ2 v so v is an eigenvector for L2 with eigenvalue λ2 . (c) Suppose A ∈ Rnn has characteristic polynomial det(λIn − A) = (λ − λ1 )k1 (λ − λ2 )k2 · · · (λ − λr )kr with r distinct real eigenvalues λ1 , λ2 , · · · , λr . In general, for each 1 ≤ i ≤ r, we know that 1 ≤ gi ≤ ki . (d) In part (c), if you also know that A is diagonalizable, then we know that gi = ki for each i. (e) Let E ∈ Rnn be an elementary matrix corresponding to an elementary row operation R, let A ∈ Rnn and let B be the matrix obtained by doing the row operation R to A. Then B = EA so det(B) = det(E) det(A). (3) (20 Points, 3 points each, (a) worth 8 pts) Answer each question separately. 1 1 −1 −1 1 1 −1 2 3 4 1 6 3 1 1 −1 −1 0 1 0 1 6 (a) det = − det = − det 3 2 1 1 0 −1 4 4 0 0 10 4 4 −2 −3 0 0 2 1 0 0 2 1 1 −1 −1 1 1 −1 −1 3 3 0 1 6 0 1 6 =4 − det = det 0 0 2 1 0 0 0 2 0 0 0 2 0 0 2 1 (42 )(3) (b) If det(A) = 10, det(B) = 4 and det(C ) = 3, then det(A−1 B 2 C T ) = 10 =
−1 3 = 7 1
24 . 5
(c) Suppose S is a basis of V , T is a basis of W , dim(V ) = n, dim(W ) = m. Then for any linear L : V → W we defined a map T MS : Lin(V, W ) → Rm n by T MS (L) = T [L]S . What property of the map T MS implies dim(Lin(V, W )) = dim(Rnm)? Answer: The property that T MS is an isomorphism, that is, a bijective linear map. (d) Suppose A, B ∈ Rnn are similar, that is, B = P −1 AP for some invertible P ∈ Rnn . The relationship between the characteristic polynomials is that they are equal, CharA (λ) = det(λIn − A) = CharB (λ) = det(λIn − B). (e) For A ∈ Rnn we know that CharA (λ) is a polynomial in the variable λ of degree n. What is the constant term of that polynomial? Answer: The constant term is CharA (0) = det(−A) = (−1)n det(A).
7 −4 2 (4) (20 Points) Let A = 4 −1 2 . 4 −4 5 (a) (8 Points) The characteristic polynomial is CharA (t) = det(λI3 − A) = − det(A−λI3 ) 7−λ −4 2 3−λ 0 λ−3 −1 − λ 2 = − det 0 3 − λ λ − 3 − det 4 4 −4 5−λ 4 −4 5−λ 1 0 −1 1 0 −1 = −(3 − λ)2 det 0 1 −1 = −(3 − λ)2 det 0 1 −1 4 −4 5 − λ 0 0 5−λ = (λ − 3)2 (λ − 5)1 = λ3 − 11λ2 + 39λ − 45.
So the eigenvalues are λ1 = 3 and λ2 = 5, the roots of CharA (λ), with algebraic multiplicities k1 = 2 and k2 = 1. (b) (4 Points) For λ1 = 3, the eigenspace, Aλ1 , is found by row reducing [A − 3I3 |0]: 4 −4 2 0 x1 = r − 12 s 1 −1 21 0 4 −4 2 0 to 0 0 0 0 so x2 = r ∈ R x3 = s ∈ R 0 0 0 0 4 −4 2 0 so the λ1 = 3 eigenspace r − 12 s Aλ1 = r ∈ R3 s (4 Points) For λ2 2 4 4
1 −1 r, s ∈ R has basis 1 , 0 and g1 = 2 = k1 . 0 2
= 5, the eigenspace, −4 2 0 1 −6 2 0 to 0 −4 0 0 0
so the λ1 = 5 eigenspace r Aλ2 = r ∈ R3 r
Aλ2 , is found by row reducing [A − 5I3 |0]: 0 −1 0 x1 = r 1 −1 0 so x2 = r 0 0 0 x3 = r ∈ R
1 r ∈ R has basis 1 and g2 = 1 = k2 . 1
3 (c) (4 Points) eigenbasis for A is since g1 + g2 = 3 and we found an R , diagonalizable −1 3 0 0 1 1 −1 1 1 T = 1 , 0 , 1 . D = 0 3 0 and P = S PT = 1 0 1 is the 0 2 0 0 5 1 0 2 1 transition matrix such that D = P −1 AP is diagonal. As a numerical check: 1 −1 1 3 0 0 3 −3 5 7 −4 2 1 −1 1 P D = 1 0 1 0 3 0 = 3 0 5 = 4 −1 2 1 0 1 = AP. 0 2 1 0 0 5 0 6 5 4 −4 5 0 2 1...