Me6505 dm mech vst au unit iii PDF

Title Me6505 dm mech vst au unit iii
Author Ben Smith
Course Introduction to Engineering Design
Institution San Diego State University
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lecture notes for vibration...


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ME 6505 – DYNAMICS OF MACHINES Fifth Semester Mechanical Engineering (Regulations 2013) Unit – III PART – A 1.

Write the mathematical expression for a free vibration system with viscous damping. (N/D – 15)

Viscous damped free vibration:

Where, c = Damping coefficient fd = frequency of damped vibration m = mass of vibrating system 2.

Write the expression for estimation of the natural frequency of free torsional vibration of a shaft. (N/D – 15)

Where, q = Torsional stiffness of shaft I = Mass moment of inertia of disc 3.

Define the term logarithmic decrement.

(M/J – 16, N/D – 16)

It is defined as the natural logarithm of the amplitude reduction factor. The amplitude reduction factor is the ratio of any two successive amplitudes on the same side of the mean position.

4.

What are the different types of vibratory motions?

(M/J – 16)

The following types of vibratory motion are important from the subject point of view : 1. Free or natural vibrations. When no external force acts on the body, after giving it an initial displacement, then the body is said to be under free or natural vibrations. The frequency of the free vibrations is called free or natural frequency. 2. Forced vibrations. When the body vibrates under the influence of external force, then the body is said to be under forced vibrations. The external force applied to the body is a periodic disturbing force created by unbalance. The vibrations have the same frequency as the applied force. Note: When the frequency of the external force is same as that of the natural vibrations, resonance takes place. 3. Damped vibrations. When there is a reduction in amplitude over every cycle of vibration, the motion is said to be damped vibration. This is due to the fact that a certain amount of energy possessed by the vibrating system is always dissipated in overcoming frictional resistances to the motion. 5.

What are the different types of damped vibrations?

(N/D – 16)

Overdamping, underdamping, critical damping. 6.

Define – Vibration

Any motion that exactly repeats itself after an interval, of time is a periodic motion and is called vibration. 7.

Vibration can have desirable effects – Justify.

(M/J – 14)

Though vibration is mainly known for its undesirable effects like, unwanted noise and wear, sometimes it is

used to design a machine with a specific application. Vibratory conveyor and cell phones are example in support of the statement. 8.

What are the classifications of vibration?

(N/D – 14)

i. According to the actuating force: a) Free vibration b) Forced vibration ii. According to energy dissipation: a) Undamped vibration b) Damped vibration iii. According to behavior of vibrating system: a) Linear vibration b) Non – linear vibration iv. According to motion of system with respect to axis: a) Longitudinal vibration b) Transverse vibration c) Torsional vibration 9.

Define transverse vibration and mention the type of stress developed due to this.

When the particles of the shaft or disc move approximately perpendicular to the axis of the shaft, then the vibrations are known as transverse vibrations. In this case, the shaft is straight and bent alternately and bending stresses are induced in the shaft. 10. Define the following terms: (a) time period (b) cycle (c) frequency

a) Period of vibration or time period. It is the time interval after which the motion is repeated itself. The period of vibration is usually expressed in seconds. b) Cycle. It is the motion completed during one time period. c) Frequency. It is the number of cycles described in one second. In S.I. units, the frequency is expressed in hertz (briefly written as Hz) which is equal to one cycle per second. 11. Define critical speed / whirling speed of shaft.

(N/D – 1 2)

The speed, at which the shaft runs so that the additional deflection of the shaft from the axis of rotation becomes infinite, is known as critical or whirling speed. 12. Define – Torsionaly equivalent shaft.

The shaft have variable diameter for different length. Such a shaft may, theoretically be replaced by an equivalent shaft of uniform diameter. 13. What is the limit beyond which damping is deterimental and why?

When damping factor ζ > 1, the aperiodic motion is resulted. That is, aperiodic motion means the system cannot vibrate due to over damping. Once the system is disturbed, it will take infinite time to come back to equilibrium position. 14. Define node in torsional vibration.

Node is the point or the section of the shaft at which amplitude of the torsional vibration is zero. At nodes, the shaft remains unaffected by the vibration.

Unit – III PART – B 1.

(a) Determine (i) the critical damping co-efficient, (ii) the damping factor, (iii) the natural(16) frequency of damped vibrations, (iv) the logarithmic decrement and (v) the ratio of two consecutive amplitudes of a vibrating system which consists of a mass of 25 kg, a spring of stiffness 15 kN/m and a damper. The damping provided is only 15% of the critical value. (N/D – 15)

Given: m = 25 kg, k = 15kN/m, c = 0.15 Cc

2.

(b) A shaft of length 1.25 m is 75 mm in diameter for the first 275 mm of its length, 125 mm (16) in diameter for the next 500 mm length, 87.5 mm in diameter for the next 375 mm length and 175 mm in diameter for the remaining 100 mm of its length. The shaft carries two rotors at two ends. The mass moment of inertia of the first rotor is 75 kg-m2 whereas of the second rotor is 50 kg-m2 Find the frequency of natural torsional vibrations of the system. The modulus of rigidity of the shaft material may be taken as 80 GPa. (N/D – 15)

3.

(a) Derive an expression for the natural frequency of the free longitudinal vibrations by (16) (i) Equilibrium method (ii) Energy method.

(M/J – 16)

1. Equilibrium Method: Consider a constraint (i.e. spring) of negligible mass in an unstrained position, as shown in Figure. Let s = Stiffness of the constraint. It is the force required to produce unit displacement in the direction of vibration. It is usually expressed in N/m. m = Mass of the body suspended from the constraint in kg, W = Weight of the body in newtons = m.g, δ= Static deflection of the spring in metres due to weight W newtons, and x = Displacement given to the body by the external force, in metres.

Restoring force = W - s (δ + x) =W - s.δ - s.x = s.δ- s.δ - s. x = -s.x (since W = s.δ) . . . (i) And Accelerating force = Mass × Acceleration

. . .(Taking upward force as negative)

Equating Restoring force and accelerating force

---- (iii)

---- (iv)

2. Energy Method: In the free vibrations, no energy is transferred to the system or from the system. Therefore the summation of kinetic energy and potential energy must be a constant quantity which is same at all the times. In other words,

We know that kinetic energy,

Potential energy, (∵P.E. = Mean force × Displacement )

The time period and the natural frequency may be obtained as discussed in the previous method. 4.

(b) Find the equation of motion for the spring – mass – dashpot system shown in fig. For(16) cases, when (i) ζ = 2, (ii) ζ = 1, and (iii) ζ = 0.3. The mass 'm' is displaced by a distance of 30 mm and released. (M/J – 16)

Given: x = 30 mm = 0.030 m

5.

(a) The barrel of a large gun recoils against a spring on firing. At the end of firing, a (16) dashpot is engaged that allows the barrel to return to its original position in minimum time without oscillation. Gun barrel mass is 400 kg and initial velocity of recoil is 20 m/s. The barrel recoils 1 m. Determine spring stiffness and critical damping coefficient of dashpot. (N/D – 16)

Given: m = 400 kg, v = 20 m/s, x = 1 m

6.

(b) A vertical steel shaft 15 mm diameter is held in long bearings 1 metre apart and carries (16) at its middle a disc of mass 15 kg. The eccentricity of the centre of gravity of the disc from the centre of the rotor is 0.30 mm. The modulus of elasticity for the shaft material is 200 GN/m2 and the permissible stress is 70 MN/m2. Determine: 1. The critical speed of the shaft and 2. The range of speed over which it is unsafe to run the shaft. Neglect the mass of the shaft. (N/D – 16, N/D – 14)

7.

(a) A shaft 50 mm diameter and 3 metres long is simply supported at the ends and carries (8) three loads of 1000 N, 1500 N and 750 N at 1 m, 2 m and 2.5 m from the left support. The Young's modulus for shaft material is 200 GN/m2. Find the frequency of transverse vibration. (N/D – 11)

8.

(a) A vertical shaft of 5 mm diameter is 200 mm long and is supported in long bearings at (16) its ends. A disc of mass 50 kg is attached to the centre of the shaft. Neglecting any increase in stiffness due to the attachment of the disc to the shaft, find the critical speed of rotation and the maximum bending stress when the shaft is rotating at 75% of the critical speed. The centre of the disc is 0.25 mm from the geometric axis of the shaft. E = 200 GN/m2. (N/D – 11, N/D – 14)

9.

(b) An instrument vibrates with a frequency of 1 Hz when there is no damping. When the (8) damping is provided, the frequency of damped vibrations was observed to be 0.9 Hz. Find 1. the damping factor, and 2. logarithmic decrement. (N/D – 11)

1. Damping factor

10. (b) The mass of a single degree damped vibrating system is 7.5 kg and makes 24 free (16) oscillations in 14 seconds when disturbed from its equilibrium position. The amplitude of vibration reduces to 0.25 of its initial value after five oscillations. Determine: 1. stiffness of the spring, 2. logarithmic decrement, and 3. damping factor, i.e. the ratio of the system damping to critical damping. (N/D – 11)

11. (a) A 4 - cylinder engine and flywheel coupled to a propeller are approximated to a 3 rotor (16) system in which the engine is equivalent to a rotor of moment of inertia 800 kg-m2, the flywheel to a second rotor of 320 kg-m2 and the propeller to a third rotor of 20 kg-m2. The first and second rotors are being connected by a 25 mm diameter and 2 m long shaft. Neglecting the inertia of the shaft and taking its modulus of rigidity as 80 GN/m 2, determine; (i) natural frequencies of free torsional vibrations and (ii) the positions of the nodes. (N/D – 11)

12. (a) Derive an expression for the frequency of free torsional vibrations for a shaft fixed at (16) one end and carrying a load on the free end.

Let

Total Angle of Twist of shaft is equivalent to sum of angle of twist of each shaft. From this concept T.l/C.J = [T.l1/C.J1] + [T.l2/C.J2] + [T.l3/C.J3] Substituting value of J, J1, J2 and J3 in all equation and simplifying we get Torsional equivalent shaft is l = l1 + l2 [d1/d2]4 + l3 [d1/d3]4

13. (a) A vibrating system consists of a mass 0f 8 kg, spring of stiffness 5.6 N/mm and a (16) dashpot of damping coefficient of 40 N/m/s. Find (a) damping factor (b) logarithmic decrement (c) ratio of two consecutive amplitudes.

HINT: Step 1: a) Determine the critical damping coefficient cc

Damping factor = c/cc [c is given as damping coefficient] Step 2: b) Determine the Logarithmic Decrement

Step 3: Determine the ratio of two consecutive amplitudes

14. (a) A centrifugal pump is driven through a pair of spur wheels from an oil engine. The pump(16) runs at 4 times the speed of the engine. The shaft from the engine flywheel to the gear is 75 mm diameter and 1.2 m long, while that from the pinion to pump is 50 mm diameter and 400 mm long. The moments of inertia are as follows: flywheel = 1000kg - m2; pinion = 10kg - m2; and pump impeller = 40kg - m2. Find the natural frequencies of torsional oscillations. Take C = 84 GN/m2.

HINT: Step 1: Determine the mass moment of equivalent rotor B IB’ = IB/G2 Additional length of equivalent shaft is l3 = G2.l2 [d1/d2]4 Total length of equivalent shaft l = l1 + l3 Step 2: lAIA = lBIB’ Determine lA from the above expression Polar Moment of Inertia for equivalent shaft is J = [π/32]d14 Step 3: Determine the Natural frequency of torsional vibration fn = [1/2π]sqrt[C.J/lAIA]...


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