Title | PHYS 234 Quiz 3 Forces - quiz 3 |
---|---|
Course | Classical Physics I |
Institution | St. Cloud State University |
Pages | 1 |
File Size | 75.3 KB |
File Type | |
Total Downloads | 15 |
Total Views | 142 |
quiz 3...
PHYS 234 Quiz 3 Feb. 16 2016
Name:
Forces cm
𝐹𝑐𝑒𝑛 = 𝑚
50
You are swinging a pendulum, making the pendulum bob move uniformly in a circular path. The length of your string is 50cm. The mass of the pendulum is 60 grams. If the pendulum travels on a circular path with 30cm radius, find the speed of the pendulum and the tension on the string. Make sure you draw a free body diagram.
30cm
𝑣2 𝑅
𝜃 = acos
3 = 53.1° 5
FT,y
Here is the free body diagram. The angle between tension and horizontal is given by geometry of the 3-4-5 triangle:
FT
Solution:
FT,x
From the y direction we have tension's component balancing gravity:
𝐹𝑇 =
Fg
𝐹𝑇,𝑦 − 𝐹𝑔 = 𝐹𝑇 sin 53.1° − 𝑚𝑔 = 𝐹𝑇 ∗ 0.8 − 0.06 ∗ 9.8 = 0 0.06 ∗ 9.8 = 0.735(𝑁) 0.8
From the x direction (towards the center of the circle), we have tension's x component providing centripetal force: 𝐹𝑇,𝑥 =
𝑚𝑣 2 𝑅
𝐹𝑇 cos 53.1° = 0.735 ∗ 0.6 = 0.441(𝑁) = 𝑣2 =
0.441 ∗ 0.3 = 2.21 0.06 𝑣 = 1.48 𝑚/𝑠
0.06 ∗ 𝑣 2 0.3...