Title | Physics 2 Lab 7 |
---|---|
Course | Physics 2II |
Institution | Kean University |
Pages | 4 |
File Size | 155.5 KB |
File Type | |
Total Downloads | 58 |
Total Views | 152 |
Physics 2 Lab 7...
Refraction of Light 11/10/17 Conor Gugliotta, Kenneth, Ashleigh, & Thomas
Purpose: The purpose of this experiment is to use Snell’s Law to determine the index of refraction of glass and water. Introduction: Refraction is the change in direction of a light ray as it passes from one medium to the second medium. This medium for example can be air to glass. Light will be reflected from pin A. The light as it passes from air to glass changes direction. When the three pins, A, B, & C are viewed through the glass they will appear to be aligned. The change in direction of the light is what will be measured.
n1 sinθ1 = n2 sinθ2
Data Analysis: θ1 15° 20° 25° 30° 35° 40° 45°
θ2 (Glass) 11° 14° 17° 20° 23° 25.5° 29°
θ1 15° 20° 25° 30° 35° 40°
θ2 (Water) 11.7° 15° 19° 23° 27° 30.5°
45°
34°
θ1 sin15 (0.2588) sin20 (0.342) sin25 (0.4226) sin30 (0.5) sin35 (0.5736) sin40 (0.6428) sin45 (0.7071)
θ2 (Glass) 0.1908 0.2419 0.2924 0.342 0.3907 0.4305 0.4848
θ2 (Water) 0.2027 0.2588 0.3256 0.3907 0.4539 0.507 0.559
Sketch:
Snell's Law for Glass 0.8 0.7
f(x) = 1.49 x − 0.01
0.6
Air
0.5 0.4 0.3 0.2 0.1 0
0
0.1
0.2
0.3
Glass
0.4
0.5
0.6
Snell's Law for Water 0.8 0.7
f(x) = 1.26 x + 0.01
0.6
Air
0.5 0.4 0.3 0.2 0.1 0
0
0.1
0.2
0.3
Water
Glass Refraction Index o y = 1.489x + 0.0108 o n2 = 1.489
Water Refraction Index o y = 1.2602x + 0.0059 o n2 = 1.260
Examples o Air
sinθ1 = sin(45°) = 0.7071
o Glass
sinθ2 = sin(23°) = 0.3907
o Water
sinθ2 = sin(34°) = 0.559
0.4
0.5
0.6...