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Waltrip 1 Sophie Waltrip 26 April 2018 Post Lab Report for Oxidation of Alcohol The product of cyclohexanone is pure because there were no extra peaks and all of the peaks that we were supposed to have showed up for both the C NMR and the IR. There is no peak on the cyclohexanone IR for the alcohol group, which was present in the reactants. There is a C=O group present which indicates that the correct product was formed. Also, on the CNMR for the product, there were 4 significant peaks for the 4 constitutionally inequivalent carbons which confirms the correct product. The reaction was efficient due to the purity of the product and the greener experiment methods. Sodium chloride and sodium sulfite are byproducts that can be washed down the sink after the experiment concludes which also makes it a more green experiment. The IR graphs were crucial in understanding how the peaks played a role in the purity of the product in relation to its reactants. Due to the presence of an OH functional group in the cyclohexanol and not in the cyclohexanone, there is a peak at 3321.05 on the cyclohexanol IR that disappears on the cyclohexanone IR. Cyclohexanone has an additional C=O bond that is not present in the cyclohexanol, which explains the presence of the peak at 1704.49 on the cyclohexanone IR. Also, there is a C-O group in the cyclohexanol IR shown by the peak at 1064.31 that is not present in the cyclohexanone. The C-H and C-H2 groups were conserved through the reactants and the products. This is shown through the almost equivalent peaks on both reactant and products. The peak for the C-H groups of cyclohexanol IR is longer than the peak of the C-H groups of the cyclohexanone IR because of the quantity of C-H groups in

Waltrip 2 cyclohexanol compared to cyclohexanone. Due to the relations of these peaks and the presence of some and not others, we can tell that the product is pure. The CNMR belongs to my products because of the 4 constitutionally inequivalent carbons. The peak on the far left signifies the carbon closest to the C=O group. The peak that is much farther from the first peak but still the most left of the bunch of peaks represents the carbons connected to the carbon previously mentioned. The peak next to this represents the third constitutionally inequivalent carbons. The rightmost peak that is close to the third peak represents the fourth constitutionally inequivalent carbon. It has similar characteristics to the third constitutionally inequivalent carbon, which explains its close proximity to the third peak, but they are still distinct carbons. Upon comparing this C NMR sheet to that of the reactants, we can tell that the product of cyclohexanone is pure....