Title | Pre-Lab 3 WHAT IS THE Molarity OF Na OH |
---|---|
Author | Ruth Ijiogbe |
Course | General Chemistry I Lab |
Institution | East Carolina University |
Pages | 1 |
File Size | 92 KB |
File Type | |
Total Downloads | 79 |
Total Views | 143 |
Download Pre-Lab 3 WHAT IS THE Molarity OF Na OH PDF
PRE-LAB 3: WHAT IS THE MOLARITY OF NaOH? LAST NAME: IJIOGBE
FIRST NAME: ASHLEY
SECTION/GROUP: 1
You and your teammates will use the data provided by your instructor (final burette reading, initial burette reading, and grams of KHP) to calculate volume of NaOH, moles of KHP, and molarity of NaOH for all 4 trials. Enter the results in Table 1. Also, enter the shade of pink provided in your group’s data set. Each member of your team will upload the completed worksheet on Canvas, INDIVIDUALLY. Table 1 Trial
Final Burette Reading (mL) Initial Burette Reading (mL) Volume of NaOH Used (mL) Grams KHP (g) Moles KHP (mol) Molarity NaOH (M) Shade of Pink
1
2
3
4
12.49
24.87
37.19
49.57
0.12
12.49
24.87
37.19
12.37
12.38
12.32
12.38
1.003
1.011
1.008
1.013
.004911
.004950
.004936
.004960
.3970
.3998
.4006
.4006
dark
Light
Light
Light
Sample Calculation: Show the step-by-step calculations and report answers to the proper number of significant figures and with the corresponding units. A. Grams of KHP to moles of KHP conversion for trial _1_ Molar Mass KHP = 204.23 g/mol 1.003 g KHP (1 mol KHP/204.23) = 0.004911 mol KHP B. Molarity of NaOH for trial _1_ Molarity = mol/L Convert 12.37 mL to L 12.37/1000 = 0.01237 L M = 0.004911/0.01237 = .3970 M C. Average Molarity (Trial 1 M + Trail 2 M + Trial 3 M + Trial 4 M) / 4 = Average Molarity (.3970 + .3998 + .4006 + .4006) / 4 = .3995 D. Range of Molarities Highest Molarity – Lowest Molarity .4006 - .3970 = .0036...