QB5 - Question Bank 5 PDF

Title QB5 - Question Bank 5
Course Affärsutvecklingslabb
Institution Kungliga Tekniska Högskolan
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Summary

Question Bank 5...


Description

Fig 1 provides the variation of   with I for various electrolytes. It is of interest to note that for non 1:1 electrolyte there exists a minimum value of   and is indicative of ion association and reflects the failure of the Debye – Hückel limiting law

Fig 1: Schematic variation of the mean ionic activity coefficient on molarity of the electrolyte at 298K

Physical Significance of the Debye length The Debye length sometimes denoted as LD is

1

D

in the above notation and it

plays a central role in condensed matter physics. The Debye length represents the characteristic length within which the influence of the electric field is felt ie. beyond LD, the electric field does not have any effect on the ionic distributions.

Flow Chart for the Debye – Hückel theory of electrolyte solutions

Distribution of ions in a solvent

Computation of the mean electrostatic potential(r ) Electrostatics + Statistical mechanics Formulation of the Poisson equation Potential vs charge density Boltzmann distribution of ions Net number density Linearised Poisson – Boltzmann equation Solution of the differential equations Debye potential  (r ) =

ze −D r e r

Excess thermodynamic properties Activity coefficient, Osmotic pressure Chemical potentials, Gibbs free energies

The Debye – Hückel theory pertains to the primitive model of the electrolyte since the solvent is treated as a continuum while ions are considered as point charges. The next improvement is provided by Restricted primitive model wherein the ions are treated as hard sphere, with the solvent being a dielectric continuum. There are other hierarchical improvements in this context such as Hypernetted Chain (HNC), Generalized Mean Spherical Approximation etc. The net result is that the Debye

1

length

D

is an involved function of the bulk concentration of the electrolyte as

well as ion sizes.

WORKED OUT EXAMPLES 1. Calculate the radius of the ionic atmosphere in aqueous NaCl solution of concentration 10-3 mol L-1 I= 1

D

1 ci zi2 = 10-3  2

=

3.035×10 -8 cm = 9.59 10-7 cm I

2. Use the Debye-Hückel limiting law to evaluate  in 10-4 mol lit-1 of 2:2 electrolytes at 25 °C

1 I = ci zi2 = 1 10−4  4 10−4  4 = 4  10 -4 mol cm-3 2 2 log10  = −0.51 z+ z−

I

log   = −0.51 4  4  10−4

and  = 0.91

3. Calculate the Debye length for 8.25  10-5 mol kg-1 solution of Al2(SO4)3. I=

1 c i z i2  2





=

1 2 2 2  8.25 10−5 ( 3) + 3 8.25 10−5 ( 2) 2

=

8.25  10 − 5 18 + 12 = 15 8.25 10−5 mol kg m−1 2

= 1.2375  10-3 mol kg m-1 = 1.2375 mol m-3 D2 =

e 2  2I  0 kT

=

1.602  10-38  2 (1.2375 10-3 )  6.023 1023 78 8.85 10−12  4.14 10−21

=

1.602  2  1.2375 6.023 78  8.85  4.14

κD2= 1.335  1019 met-2 1/κD = 2.736  10-10 met

4.

( )

A 50% v v

aqueous ethanol (dielectric constant =68) contains 0.001 mol kg-1

each in HBr and CaBr2. Find the mean activity coefficient (  ) of CaBr2 in this solution at 300K using the Debye - Hückel limiting law. Debye - Hückel limiting law is log10   = − A z+ z−

I

where A = 1.823 x 106 (  T)3/2 when  = 68, A= 1.823 x 106

at T = 300K

(68 x 300)3/2 or A= 1.823 x 106

= 0.6256

2.914x 106 I=

1 1 mi zi2 = 0.001.12 + 0.001.12 + 0.001.22 + 0.002.12   2 2 1 2

or I = 0.001 + 0.001 + 0.004 + 0.002 = 0.004  log10   = −0.6256  2  1 (0.004)1/ 2 = − 0.6256 2 0.06324

or log10   = -0.07913   = 0.8334 5.

Calculate the Debye length of the ionic atmosphere for 0.012 N LaCl3 in nitrobenzene (dielectric constant = 34.8) at 300 K. Debye length,

1

D

1/2

− 10

= 2.81 10

 T   2     ci z i 

where ‘  ’ is the dielectric constant and ci is the concentration of the electrolyte in mL-1. For LaCl3, c=0.012N = 0.004 M  = 34.8 and T = 300K

 c z = (c 2

+

La 3

i i

2 2 .zLa 3+ + c − z − Cl Cl

)

= 4 x 10-3. 32 + 3 x 4 x 10-3.12 =36 x 10-3 + 12 x 10-3 = 48 x 10-3 = 0.048 

 34.8 300  = 2.81 x 10− 10 x  −2  D  4.8 10  1

 34.8 3  = 2.81 10− 10 10 2    4.8  or

6.

1

D

1/2

1/2

= 13.1 Å

The solubility product of CdSO4 is 9.2 x 10-11 M2. Calculate the mean activity coefficient of the Cd and SO 2-4 ions in a solution containing 0.05 M each of KNO3 in KCl, compare the solubility of CdSO4 in water.

The ionic strength of the solution containing KNO 3 and KCl is I=

1  c iz 2i = 0.1M 2 i

log10γ = − A z+ z−

I = − 2 2 0.51 0.1 = − 0.645

Hence γ  = 0.226 K sp is water = 9.2 x 10-11 M2. Hence the solubility is

s = K sp = 9.6 x 10-6 M If the solubility in the solution is s, K sp =s 2γ 2 9.2 10−11 = s 2 ( 0.226 )

2

solubility = 4.25 10−5 M Thus the solubility increases in the salt solution. EXERCISES 1. The ionic strength of 0.1 M lanthanum phosphate solution is -------------------

-------2. The time taken for the formation of ionic atmosphere in the case of 1.0 M

NaCl solution is nearly -------------------seconds. 3. Which of the following has the largest thickness of the ionic atmosphere?

(A)1.0 M KCl;(B) 0.1 M KCl;(C)0.01M KCl and (D)1.5 M KCl 4. Calculate (i) the activity of the electrolyte and (ii) the mean ionic activity, a

of ions in 0.01 molal solutions of (a) Lanthanum nitrate and (b) Indium

sulphate, using the Debye-Huckel limiting law for the mean ionic activity coefficients. 5. Write the equation for the osmotic pressure of 1:1 electrolytes of 0.0001 M

concentration under the Debye – Hückel approximation. 6. Use the Debye – Hückel limiting law to estimate   in 10-6 M solution of

ZnSO4. 7. Write the expression for the mean electrostatic potential ( ψ ) at a central ion

on the basis of Debye–Hückel’s theory. 8. Calculate the Debye length for 0.001 M solution of 2: 2 electrolytes in

nitrobenzene at 25ºC. 9. Consider the ions of charges Zi and zj immersed in a solvent of dielectric

constant . The diameters are  i and 

j

respectively. Write the expression

for the pairwise interaction u ij for this system. 10. What is the mean distance between ions when their number density is 1 x

1024 ions / cm3? SUMMARY The subtle features underlying the Debye–Hückel theory of electrolytes have been outlined. The limitations and merits of the Debye –Hückel theory they have been pointed out. Recent improvements of the Debye – Hückel theory have been indicated. Appendix A An important aspect wherein the SI and Gaussian units differ is the placement of the 4π’s in the governing equation. Units wherein the 4π’s have been eliminated

from Maxwell’s equations are rationalized units; SI units are an example of rationalized units, since the 4π’s do not appear. Gaussian units are not rationalized and hence ‘4 π’ appears. 1. 1 statvolt is (approximately) 300 Volts 2. The conversion from SI to Gaussian units can be accomplished by replacing 1/4πε o by

Thus Poisson’s equation in SI and Gaussion units are as follows. 2 = -

ρ (SI) εr

 2 =-

4 εr

(Gaussian)

where ε r is the relative permittivity (or dielectric constant) given by ε/ε In SI units, 2 =

-ρ ε

In Gaussian units, we replace 4  by 1. Hence, 2  =-

4  ε

3.  is the permittivity of vacuum. SUMMARY The assumptions underlying Debye Hückel theory are pointed out. Recent improvements pertaining to the theory of electrolyte solutions have been indicated.

Module II - Electrode potentials and Applications Learning objectives After reading this chapter, you will be able to (i) comprehend the importance of Nernst equation (ii) predict the occurrence of chemical reactions (iii) employ Latimer and Frost diagrams for disproportionation reactions Introduction The analytical and physicochemical applications of the Nernst equation are exhaustive and hence an outline of various applications is provided below. At a preliminary stage, it is essential to acquire expertise in writing the Nernst equations for various types of half cells. It is customary to write both the half-cell reactions as reduction and cancelling the number of electrons when the complete cell reaction is considered. The terminology of anodes and cathodes will be different depending upon whether one considers galvanic or electrolytic cells. The galvanic cells are energy storage devices since they convert chemical energy into electrical energy, e.g (batteries, fuel cells etc). The electrolytic cells on the other hand, involve supplying electrical energy in order to bring about a chemical transformation. The synthesis of organic and inorganic compounds, extraction of metals from their respective ores etc are carried out in electrolytic cells. Thus, it is now customary to consider oxidation as occurring at anodes and reduction as a cathodic process. This nomenclature will be valid irrespective of whether one employs galvanic or voltaic cells.

1

Table 1: Half-cell reactions and corresponding Nernst equations

Half Cell

Ag|AgCl| KCl

Reduction

AgCl + e-

𝐻𝑔|𝐻𝑔2 𝐶𝑙2 |𝐾𝐶𝑙

-

𝐻𝑔|𝐻𝑔2 𝑆𝑂4 |𝐾2 𝑆𝑂4 Hg2SO4 + 2e

Hg/HgO/NaOH 𝐴𝑔|𝐴𝑔2 𝑂|𝑁𝑎𝑂𝐻

Sb|Sb2O3|NaOH

= 𝐸0 − 0.059 𝑙𝑜𝑔 𝑎𝐶𝑙−

-

-

2Hg + 2Cl

𝐸 = 𝐸° −

2Hg +SO4

-

𝐸 = 𝐸0 −

Pb + 2SO4-

PbSO4 + 2e-

HgO + H 2 O + 2e-

Hg + 2OH -

Ag2O + H 2O + 2e-

Ag+ 2OH-

Sb2O3 + 3H2O + 6e-

2Sb+ 6OH-

𝑃𝑡|𝐻2 |𝐻𝐶𝑙

2𝐻+ + 2𝑒 − → 𝐻2

𝑃𝑡|𝐶𝑙2 |𝐻𝐶𝑙

𝐶𝑙2 + 2𝑒 − → 2𝐶𝑙−

𝑃𝑡|𝐹𝑒 3+, 𝐹𝑒 2+

2

𝐸

Ag + Cl-

Hg2Cl2 + 2e

𝑃𝑏|𝑃𝑏𝑆𝑂4 |𝐻2 𝑆𝑂4

Nernst Equation at 298K

Fe3+ + e -

Fe2+

𝐸

= 𝐸0 −

0.059 2

0.059 2

2 − 𝑙𝑜𝑔 𝑎𝐶𝑙

𝑎𝑆𝑂42−

0.059 𝑙𝑜𝑔 𝑎𝑆𝑂42− 2

𝐸= 𝐸 0 −

0.059 𝑎2𝑂𝐻 − 2 𝑎𝐻2𝑂

𝐸= 𝐸° − 0.059

𝐸= 𝐸 0 −

2 − 𝑎𝑂𝐻

𝑎𝐻2𝑂

0.059 𝑎6𝑂𝐻 − 6 𝑎𝐻32𝑂

𝐸 = 𝐸° −

0.059 𝑝𝐻2 2 2 𝑎𝐻 +

0.059 2 𝑎𝐶𝑙− 2 𝑎𝐹2+ 𝑒 𝐸 = 𝐸 0 − .059. 3+ 𝑎𝐹𝑒

𝐸=𝐸° −

𝐸

8

𝐶𝑑 − 𝐻𝑔|CdSO4. 𝐻2 𝑂 3

|CdSO4 (saturated)

𝑃𝑡|𝑄0𝑥 , 𝑄𝐻2 |𝐻𝐶𝑙

CdSO4 + 2e-

Cd2+ + 2SO 4-

= 𝐸° − 𝐸

Qox + 2H+ + 2e-

QH2

0.059 𝑎

= 𝐸0 −

2

2−

𝐶𝑑 2+ 𝑎𝑆𝑂4 𝑎𝐶𝑑2+

1 . 059 𝑙𝑜𝑔 𝑎𝐻 + 2 2

Sign Convention The IUPAC (or Stockholm) convention employs the reduction potentials of both half cells. The net cell emf is positive and hence the reaction is spontaneous. Consider the half-cell represented as Cd | Cd2+ and during the discharge of Cd 2+ , the Cd electrode acquires positive charge and hence the reduction potential is positive while ΔG is negative. Analogously, in a complete cell when both half cell reactions are written as reduction, the sign of the overall cell potential will correspond to that of the r h s in the cell representation. The potential is calculated as the difference between the rhs and lhs of the cell representation. The important points in the construction of electrochemical cells are as follows: 1.Both half-cell reactions should be written as reductions; E0(rhs)-E0(lhs) should be positive in the cell representation for any galvanic cells. 2. ΔG should be considered while manipulating cell reactions and not the electrode potentials. Thermodynamic considerations underlying Nernst equation Consider a general chemical equilibrium such as aA + bB + ...... = cC +dD+ ......(1) The Gibbs free energy change (ΔG) is given by ΔG = (c ΔG c+ d ΔG D+.....)- (a ΔG A+ b ΔG B+....)

------ (2)

Further, ΔG under standard conditions (ΔG0) becomes ΔG = (c ΔG 0C+ d ΔG 0D+.....)- (a ΔG 0A+ b ΔG 0A+....) ------ (3) where 𝜇𝐴 , µB … denote the respective chemical potentials. However, the chemical potentials are given by following general equations: 3

𝜇𝐴 = 𝜇𝐴0 + 𝑅𝑇 𝑙𝑛 𝑎𝐴 − − − (4)

𝜇𝐵 =𝜇𝐵0 + 𝑅𝑇 𝑙𝑛 𝑎𝐵 − − − (5)

𝜇𝐶 = 𝜇𝐶0 + 𝑅𝑇 𝑙𝑛 𝑎𝐶 − − − (6)

𝜇𝐷 = 0𝜇𝐷+ 𝑅𝑇 𝑙𝑛 𝑎𝐷 − − − −(7)

Hence 𝛥𝐺 − 𝛥𝐺 0 = 𝑅𝑇 𝑙𝑛

𝑎𝐶𝑐 𝑎𝐷𝑑 𝑎𝐴𝑎 𝑎𝐵𝑏

----(8)

At equilibrium ΔG = 0 Hence, one can write 𝛥𝐺 0 = −𝑅𝑇 𝑙𝑛

𝑎 𝐶𝑐1𝑒𝑞 𝑎𝑑𝐷1𝑒𝑞 𝑎𝐴𝑎 𝑒

1

𝑎𝑏 𝑞 𝐵1𝑒𝑞

− − − (9)

where the activities are now the values at equilibrium. Thus 𝛥𝐺 0 = − 𝑅𝑇 ln K 𝑒𝑞 ----- (10) Furthermore, employing 𝛥𝐺= −𝑛𝐹𝐸 and Δ𝐺 0 = −𝑛𝐹𝐸 0 , the familiar Nernst eqn follows as 𝐸 = 𝐸0 −

𝑅𝑇

𝑛𝐹

𝑙𝑛

𝑎𝐶𝑐 𝑎𝐷𝑑 𝑎𝑎𝐴 𝑎𝐵𝑏

-----(11)

Standard Chemical potentials For a reduction reaction such as Fe 3+ + e-

= Fe 2+, occurring at an inert electrode ( Phase

I) while the Phase II denotes an electrolyte, the equilibrium condition is given by

 Fe , phaseII +  e− , phase I = Fe , phase II 3+

II

2+

 aFe3+  a 0 3+  Fe

0Fe + RT ln  3+

  a 2+ 0 0  + nFII + I e− − FI = II Fe2 + + RT ln  0Fe   a Fe2+

The Galvani Potential (vide infra) is given by

 I − II =  0 + 4

0 RT  aFe3 + aFe ln  . 0 2+  F  a Fe2 + a Fe3+

  

  + 2F II 

where 𝛥𝜑 0 =

0 𝐼𝐼 𝜇 𝐹𝑒3+

− 𝐼𝐼𝜇

0 𝐹𝑒2+

𝐹

+ 𝐼𝐼 𝜇 𝑒−0

Formal potentials In general, the Nernst equation can be written in terms of the activities and hence 𝛾𝑖

𝑅𝑇 𝛱𝑎𝑖,𝑝 𝑙𝑛 𝐸 = 𝐸° − 𝛾𝑖− − − (12) 𝑛𝐹 ∏ 𝑎𝑖,𝑟

where

∏ refers to the multiplication symbol. A subtle distinction can be obtained by

replacing the activities with concentrations so as to obtain 𝐸=𝐸° ′ −

𝑅𝑇

𝑛𝐹

𝑙𝑛

𝐶𝐶𝑐𝐶𝐷𝑑

𝐶𝐴𝑎 𝐶𝐵𝑏

− − − −(13)

𝐸°′ is designated as the formal potential and is related to E0 as 𝐸°′ = 𝐸° −

𝛾 𝑐𝛾 𝑑 𝑅𝑇 𝑙𝑛 𝐶𝑎 𝐷𝑏-----𝑛𝐹 𝛾𝐴 𝛾𝐵

(14)

If all the activity coefficients are unity, the formal potential becomes identical to the standard electrode potential. The following Table provides a few formal potential values. The Nernst equation, taking into account, the activity coefficients, stoichiometric coefficients and the formal potentials can be derived in the following manner: Consider the reduction: 𝑣𝐴 + 𝑛𝑒 − = 𝑣𝐵 𝐵. The electrode potential E is given by 𝐸=𝐸° −

𝑅𝑇

𝑛𝐹

𝑙𝑛

𝜈

𝑎𝐵 𝐵

𝑣 𝑎𝐴 𝐴

= 𝐸° −

(𝐶 𝛾 ) 𝜈𝐵 𝑅𝑇 𝑙𝑛 (𝐶𝐵 𝐵 )𝑣𝐴 𝑛𝐹 𝐴 𝛾𝐴

𝐸°′ is referred to as the formal potential and is related to E0 as 𝐸°′

𝜈

𝑅𝑇 𝛾𝐵 𝐵 = 𝐸° − 𝑙𝑛 𝑛𝐹 𝛾𝐴𝑣𝐴

Hence the Nernst eqn is given by 𝜈

5

𝑅𝑇 𝑐𝐵𝐵 𝐸 = 𝐸°᾿ − 𝑙𝑛 𝑛𝐹 𝑐𝐴𝑣𝐴

The single ionic activity coefficients cannot be experimentally obtained; but can be theoretically estimated using various theories such as Debye-Hückel theory, scaled particle theory, hypernetted chain approximation etc. Table 2 : Formal electrode potentials at 25 ˚ C for a few compounds Compound

E(V vs. SHE)

Ru (NH3)5(py)2+

E˚’ = 0.299, 1M CF3 SO3H

Thionine

E˚’ = 0.056, pH =7

Ru(NH 3)63+

E˚’ = 0.051, 0.1M NaBF4

Methylene blue

E˚’ = 0.011, pH = 7

Neutral Red

E˚’ = 0.325, pH = 7

Reference Electrodes In order to measure the electrode potentials of any complete cell, it is essential to have a reference electrode. The standard hydrogen electrode (SHE) was originally chosen as the

reference electrode, whose potential was assigned as Zero at 298K, unit activity of 𝐻 + ions and

1 atm pressure of 𝐻2 (𝑔). It is essential to point out that, by careful consideration of interfacial

potentials and work functions, an absolute scale of electrochemical potentials can be constructed. For an electrode to be employed as a reference electrode, the following requirements should be met: (i)long stability;(ii)non-polarizable;(iii) small temperature coefficient of the potential; (iv)ease of handling and (v) non-interference with the cell reaction. The requirement (i) is

essential since the potential needs to be constant over long periods of time. A non-polarizable electrode ensures that its potential remains constant during the passage of current. For electron transfer process es such as, Ox + ne-

Red

Nernst eqn becomes

6

𝐸= 𝐸° −

𝑅𝑇

𝑎 𝑅𝑒 𝑑 𝑙𝑛 𝑎𝑜𝑥

𝑛𝐹 For the electron transfer process Ox + ne- - Red = 0, the equation for Affinity is given by νA Ox + ne- - νp Red = 0 Recognising that the stoichiometric number of the reactant is positive while that of the product is negative, the above eqn becomes 𝑚

∑ 𝛾𝑖 𝑐𝑖 + 𝑛𝑒 − = 0

𝑖=1

where the summation index runs over all the species present in the system. If a redox couple involves 𝐻 +ions, the above eqn. becomes more generalized as 𝐶𝑟2 𝑂72 + 14𝐻 + − 2𝐶𝑟 3+ − 7𝐻2 𝑂 + 6𝑒 − = 0 −

The electrode potential depends upon concentrations of various species as well as pH of the solution. Affinity of electrochemical reactions We also note that the driving force for any (electro) chemical reaction is the affinity defined as 𝐴𝑓𝑓𝑖𝑛𝑖𝑡𝑦(𝐴𝑟 ) = ∑ 𝜈 𝜇𝑖 where 𝜇𝐴 is +ve for reactants and –ve for products.

𝑖

For the equilibrium 𝑎𝐴 + 𝑏𝐵 = 𝑐𝐶+ 𝑑𝐷, The affinity is, 𝐴 = 𝑎𝜇𝐴 + 𝑏𝜇𝐵 − 𝑐𝜇𝐶 − 𝑑𝜇𝐷 and so on. At this stage it is necessary to define various standard states(Table 3 ) Table 3: Standard states of pure substances

7

Solid in its most stable and pure form at 𝜌𝜃 = 1 𝑏𝑎𝑟 (100𝑘𝑃𝑎) and the

Solid

specified temperature (T) (often at T=298.15K) Liquid

Pure liquid in most stable form at 𝜌𝜃 = 1 bar and T

Gas

Pure gas at unit fugacity

Common Reference electrodes Normal (or standard) hydrogen electrode In view of the reproducibility offered by Pt surface, the earliest known reference electrode was the Standard Hydrogen Electrode(SHE) or Normal Hydrogen Electrode(NHE) consisting of platinised Pt immersed in H 2 SO4. The reduction process in this half cell is 2H+ + 2e-

H2

The Nernst eqn in this case is 𝑬 = 𝑬° +

(𝒂 )𝟐 𝑹𝑻 𝒍𝒏 { 𝑯+ } 𝟐𝑭 𝒑𝑯𝟐

As mentioned earlier, the potential of SHE is assigned zero at one atmosphere pressure of hydrogen, 298 K and unit activity of H+ ions. Saturated calomel electrode (SCE) It is probably the most widely used refe...


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