T3 Current resistance - Question and solution PDF

Title T3 Current resistance - Question and solution
Course Thermodynamics & Heat Transfer
Institution University of Queensland
Pages 12
File Size 938.9 KB
File Type PDF
Total Downloads 161
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Summary

T3 (MECH3400) Heat Transfer 1) A 12-cm × 18-cm circuit board houses on its surface 100 closely spaced logic chips, each dissipating 0 W in an environment at 40 °C. The heat transfer from the back surface of the board is negligible. If the heat transfer coefficient on the surface of the board is 10 W...


Description

T3 (MECH3400) Heat Transfer 1) A 12-cm × 18-cm circuit board houses on its surface 100 closely spaced logic chips, each dissipating 0.06 W in an environment at 40 °C. The heat transfer from the back surface of the board is negligible. If the heat transfer coefficient on the surface of the board is 10 W/(m2 K), determine ( ) the heat flux on the surface of the circuit board, in W/m2 ; ( ) the surface temperature of the chips; and ( ) the thermal resistance between the surface of the circuit board and the cooling medium, in °C/W. (Ans: ( ) 278 W/ m2 , ( ) 67.8 °C, ( ) 4.63 °C/W)

2) Water is boiling in a 25-cm-diameter aluminium pan ( = 237 w/m.K) at 95 °C. Heat is transferred steadily to the boiling water in the pan through its 0.5-cm-thick flat bottom at a rate of 800 W. If the inner surface temperature of the bottom of the pan is 108 °C, determine ( ) the boiling heat transfer coefficient on the inner surface of the pan and ( ) the outer surface temperature of the bottom of the pan. (Ans: ( ) 1254 W/m2 . °C, ( ) 108.3 °C)

3) Clothing made of several thin layers of fabric with trapped air in between, often called ski clothing, is commonly used in cold climates because it is light, fashionable, and a very effective thermal insulator. So, it is no surprise that such clothing has largely replaced thick and heavy old-fashioned coats.

T3 (MECH3400) Consider a jacket made of five layers of 0.1-mm-thick synthetic fabric ( = 0.13 W/m.K) with 1.5-mm-thick air space ( = 0.026 W/m.K) between the layers. Assuming the inner surface temperature of the jacket to be 28 °C and the surface area to be 1.25 m2, determine the rate of heat loss through the jacket when the temperature of the outdoors is 0 °C and the heat transfer coefficient at the outer surface is 25 W/ m2.K. (Ans: 127 W) What would your response be if the jacket is made of a single layer of 0.5-mm-thick synthetic fabric? What should be the thickness of a wool fabric ( = 0.035 W/m.K) if the person is to achieve the same level of thermal comfort wearing a thick wool coat instead of a five-layer ski jacket? (Ans: 798 W, 8.22 mm)

4) A 2.2-mm-diameter and 10-m-long electric wire is tightly wrapped with a 1-mm-thick plastic cover whose thermal conductivity is = 0.15 W/m.K. Electrical measurements indicates that a current of 13 A passes through the wire and there is a voltage drop of 8 V along the wire. If the insulated wire is exposed to a medium at ∞ = 30 ºC with a heat transfer coefficient of h = 24 W/m2.K, determine the temperature at the interface of the wire and the plastic cover in steady operation. Also determine if doubling the thickness of the plastic cover will increase or decrease this interface temperature. (Ans: 70 ºC, decrease)

T3 (MECH3400)

T3 (MECH3400)

T3 (MECH3400)

5) A 4-mm-diameter and 10-cm-long aluminium fin ( = 237 W/m.K) is attached to a surface. If the heat transfer coefficient is 12 W/m2.K, determine the precent error in the rate of heat transfer from the fin when the infinitely long fin assumption is used instead of the adiabatic fin tip assumption. (Ans: 63.5%)

T3 (MECH3400) Sketch Assumptions: Steady heat transfer Thermal symmetry about centreline One dimensional heat transfer Constant thermal properties and coefficients Coefficients account for any radiation effects

Strategy Rate of heat transfer assuming an infinitely long fin: Rate of heat transfer assuming adiabatic fin tip:

        

        tanh  !"#"   $&'

%

(

Assume the adiabatic fin tip assumption provides the accepted value for heat transfer rate, so the percent error calculation becomes: %*##+#  Solution





   



Substituting and simplifying: %*##+# 

               tanh        tanh 

For m:









1 1  tanh   1 tanh  tanh 

1200.004  :; .  7  7.116 00.004   237 6 4 8 Substituting: %*##+# 

1 1  1  63.5% 1  tanh...


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