04 - Normal Lines - Practical Exam PDF

Title 04 - Normal Lines - Practical Exam
Author Cfisd Center
Course  Differential Equations
Institution University of Houston
Pages 2
File Size 78.5 KB
File Type PDF
Total Downloads 77
Total Views 150

Summary

Practical Exam...


Description

Kuta Software - Infinite Calculus

Name___________________________________

Normal Lines

Date________________ Period____

For each problem, find the equation of the line normal to the function at the given point. If the normal line is a vertical line, indicate so. Otherwise, your answer should be in slope-intecept form. 1) y = x 3 − x 2 − 2 at (1, −2)

2) y =

y 8

1 at (5, 1) x−4 y

6 8 4 6 2 4 −6

−4

−2

2

4

6

8

x

2

−2 −2

2

4

6

8

10

−4 −2 −6 −4 −8 −6

3) y = − x3 + 15x2 − 72x + 110 at (4, −2)

5) y =

( )

3 1 at 4, x+2 2

7) y = ln (x + 4 ) at (−3, 0)

4) y =

2 at (5, 1) x−3

6) y = (2x − 8)

1 3

at (0, −2)

( )

8) y = −sin (2x) at −

π

2

,0

12

x

Kuta Software - Infinite Calculus

Name___________________________________

Normal Lines

Date________________ Period____

For each problem, find the equation of the line normal to the function at the given point. If the normal line is a vertical line, indicate so. Otherwise, your answer should be in slope-intecept form. 1) y = x 3 − x 2 − 2 at (1, −2)

2) y =

y 8

1 at (5, 1) x−4 y

6 8 4 6 2 4 −6

−4

−2

2

4

6

8

x

2

−2 −2

2

4

6

8

10

−4

12

x

−2 −6 −4 −8 −6

y = −x − 1 y=x−4

3) y = − x3 + 15x2 − 72x + 110 at (4, −2) Normal line is vertical line atx = 4

4) y =

2 at (5, 1) x−3

y = 2x − 9

5) y =

( )

3 1 at 4, x+2 2

y = 12x −

95 2

7) y = ln (x + 4 ) at (−3, 0)

6) y = (2x − 8)

1 3

at (0, −2)

y = −6x − 2

( )

8) y = −sin (2x) at −

y = −x − 3

π

2

,0

π 1 y=− x− 2 4

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