Title | 04 - Normal Lines - Practical Exam |
---|---|
Author | Cfisd Center |
Course | Differential Equations |
Institution | University of Houston |
Pages | 2 |
File Size | 78.5 KB |
File Type | |
Total Downloads | 77 |
Total Views | 150 |
Practical Exam...
Kuta Software - Infinite Calculus
Name___________________________________
Normal Lines
Date________________ Period____
For each problem, find the equation of the line normal to the function at the given point. If the normal line is a vertical line, indicate so. Otherwise, your answer should be in slope-intecept form. 1) y = x 3 − x 2 − 2 at (1, −2)
2) y =
y 8
1 at (5, 1) x−4 y
6 8 4 6 2 4 −6
−4
−2
2
4
6
8
x
2
−2 −2
2
4
6
8
10
−4 −2 −6 −4 −8 −6
3) y = − x3 + 15x2 − 72x + 110 at (4, −2)
5) y =
( )
3 1 at 4, x+2 2
7) y = ln (x + 4 ) at (−3, 0)
4) y =
2 at (5, 1) x−3
6) y = (2x − 8)
1 3
at (0, −2)
( )
8) y = −sin (2x) at −
π
2
,0
12
x
Kuta Software - Infinite Calculus
Name___________________________________
Normal Lines
Date________________ Period____
For each problem, find the equation of the line normal to the function at the given point. If the normal line is a vertical line, indicate so. Otherwise, your answer should be in slope-intecept form. 1) y = x 3 − x 2 − 2 at (1, −2)
2) y =
y 8
1 at (5, 1) x−4 y
6 8 4 6 2 4 −6
−4
−2
2
4
6
8
x
2
−2 −2
2
4
6
8
10
−4
12
x
−2 −6 −4 −8 −6
y = −x − 1 y=x−4
3) y = − x3 + 15x2 − 72x + 110 at (4, −2) Normal line is vertical line atx = 4
4) y =
2 at (5, 1) x−3
y = 2x − 9
5) y =
( )
3 1 at 4, x+2 2
y = 12x −
95 2
7) y = ln (x + 4 ) at (−3, 0)
6) y = (2x − 8)
1 3
at (0, −2)
y = −6x − 2
( )
8) y = −sin (2x) at −
y = −x − 3
π
2
,0
π 1 y=− x− 2 4
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