5- seepage 2D PPT - Lecture notes 5 PDF

Title 5- seepage 2D PPT - Lecture notes 5
Course Soil Behaviour
Institution University of Technology Sydney
Pages 38
File Size 2.5 MB
File Type PDF
Total Downloads 57
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Summary

lecture notes seepage 2D with relevant examples...


Description

Darcy’s Law for Groundwater Flow

Groundwater Flow

Coefficient of permeability in the field

SOIL BEHAVIOUR (Part 5 ) Two Dimensional Seepage (Flow Net) Hadi Khabbaz Email: [email protected] Room 2.520

Continuity Equation - Unit thickness in y direction. - Total rate of inflow = total rate of outflow:

z

- Isotropic permeability: k x = kz = k

dz

dx x

Laplace’s Equation

It represents an infinite number of mutually perpendicular curves.  One group of curves shows paths of water and called flow lines. Total head gradually decreases along a flow line. 

Laplace’s Equation Another group represent lines on which the total head is constant and called equipotential lines. These lines are contours of constant total head.  Flow lines and equipotential lines are orthogonal (intersects at 90˚).  A selected number of flow lines and equipotential lines constructs a flow net. 

Flow Lines

Equipotential Lines

Flow Net

Properties of Flow Net Q

L1

Assuming: h1=h2=h

A1

L2

A2

Q

Properties of Flow Net Assuming: h1=h2=h3=h Q3

Q1

A3

h

L1

L3

A1

L2

h+h

A2

Rate of Flow Q

L1

No. of head drops=Nh A1

L2

A2

No. of flow channels=Nf

Q

Properties of Flow Net 



It is most convenient to draw a flow net so that the head drop between two adjacent equipotential lines, h, is the same.  The flow net is comprised of squares  Each flow tube carries the same flow Q. Rate of flow can be calculated from a flow net as: Total head loss

Flow per unit length in y Coefficient of permeability

Number of flow channels

Number of equipotential drops

Sketching Flow Net 



The flow net must be comprised of a family of orthogonal lines, defining a curvilinear square mesh, that also satisfy the boundary conditions. Some of the more common boundary conditions are:  A submerged

soil boundary is an equipotential.  An impermeable soil boundary is a flow Line.  Any line of constant pore pressure is defined as phreatic line where the head drop is equal to the elevation drop on that line.  Any axis of symmetry can be a part of flow lines.

Procedure for Sketching Flow Nets 1. Mark all boundary conditions. 2. Draw a coarse net which is consistent with the boundary conditions and which has orthogonal equipotential and flow lines. It is usually easier to visualise the pattern of flow so start by drawing the flow lines.

Procedure for Sketching Flow Nets 3.Modify the mesh so that it meets the conditions outlined above and any rectangle between adjacent flow lines and equipotential lines becomes a curvilinear square. 4. Refine the flow net by repeating the previous step and subdividing the coarse net.

Example of Flow Nets Phreatic line: equipotential drop = elevation drop Submerged surface boundary = equipotential line

Vertical drain

Weephole

Impermeable boundary = flow line



Flow rate?

What is H?

Vertical drain h Weephole

h=H/Nh

Example of Flow Nets Submerged boundary = equipotential line

Impermeable boundary = flow line

Example of Flow Nets Submerged boundary = equipotential line Phreatic line: equipotential drop = elevation drop

Impermeable boundary = flow line



Calculation of Seepage Example 1: Trench excavated under water, water pumped out. Q=? k = 610-6 m/s ’vx=? t = 18.2 kN/m3 Quick conditions ? Pore pressure distribution on the sheet pile wall = ? 10.8m 2.1m 1.2m x 4.5m

2.8m

4m



Calculation of Pressure Distribution of pore water pressure on the sheet pile? H

he

hp

10.1 10.1

0.0

10.1

8.0

2.1

9.8

6.8

3.0

2.1m

1.2m

H 10.1 H 6.8

9.8

2.8m

7.1 9.5 7.4 9.2

4m

7.7 8.0

8.9 8.6

8.3

9.5

5.7

3.8

9.2 8.9

4.7 4.0

4.5 4.9

H

he

hp

6.8

6.8

0

7.1

5.8

1.3

7.4

5.2

2.2

7.7 8.0

4.5 4

3.2 4.0



Calculation of Pressure Distribution of pore water pressure on the sheet pile? hp

u

0.0

0.0

2.1

20.6

2.1m

1.2m

H 10.1 H 6.8

9.8

2.8m

7.1 9.5 7.4 9.2

4m

7.7 8.0

8.9 8.6

8.3

3.0

29.4

3.8

37.2

4.5 4.9

44.1 48.0

hp

u

0

0

1.3

12.7

2.2

21.6

3.2 4.0

21.4 39.2

Anisotropic Permeability In many soils the permeability in horizontal direction is not similar to the permeability in vertical direction.

Isotropic

Anisotropic

Anisotropic Permeability 

The Laplace’s equation given before is valid for isotropic soils.



A general form of Laplace’s equation can be obtained for anisotropic soils:



A practical way to solve the general Laplace’s equation is to transform the coordinates.

Anisotropic Permeability Coordinate transformation: or

Assume: x =xt then: If

then:

It means that if all dimensions in x-direction are divided by , the problem can be treated the same as isotropic soils with an equivalent permeability of:

Anisotropic Permeability Example: x = xt xt = x /  = x / 2

kx=410-5 m/s kz=110-5 m/s

12m 28m

z x

Real dimensions

Anisotropic Permeability Example: x = xt xt = x /  = x / 2

kx=410-5 m/s kz=110-5 m/s

keq=210-5 m/s 12m 14m

z xt

Transformed dimensions

Exam 2004 A long concrete walled coffer dam has been installed across a section of river. Excavation has proceeded between the concrete Flow Tube 3

walls on either side of the dam. Steady seepage is occurring into the excavated section of the dam. The coefficient of permeability of the soil around the dam is 10-4 m/s. Note the flow net has only been drawn for half the coffer dam because of symmetry.

1m

Concrete wall

Excavation side

4m

3m

5m

Exam 2004 i) Determine the flow that is occurring through Flow Tube 3 which is marked on the flow net. 1m

Concrete wall

Flow Tube 3

ii) What pump capacity, in m3 /s per metre run, would be required to maintain the water levels at the levels indicated on the flow net?

Excavation side

4m

3m A B

iii) Find the resultant uplift water force on the base AB of the 1m wide concrete wall.

5m

Solution Part i) Flow Tube 3

Part ii) Total Flow

Part iii) Uplift Force

H = 9.33

Assume linear variation

H = 10.33

H = 10

H = 9.66

hp = 5.33

hp = 5

hp = 4.66

u = 52.3

u = 49

u = 45.7

u = 42.4 u = 52.3

F

hp = 4.33 u = 42.4...


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