Balancing Redox 2-Key PDF

Title	Balancing Redox 2-Key
Author	Justin Humphrey
Course	General Chemistry II
Institution	University of Nebraska-Lincoln
Pages	1
File Size	61.3 KB
File Type	PDF
Total Downloads	6
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Balancing Redox Reactions Practice Problems 1. MnO4— (aq) + Fe2+ (aq)  Mn2+ (aq) + Fe3+ (aq) (in acid) MnO4— (aq) + 5 Fe2+ (aq) + 8 H+ (aq)  Mn2+ (aq) + 5 Fe3+ (aq) + 4 H2O (l) 2. MnO4— (aq) + I— (aq)  MnO2 (s) + I2 (aq) (in base) 2 MnO4— (aq) + 6 I— (aq) + 4 H2O (l)  2 MnO2 (s) + 3 I2 (aq) + 8 OH— (aq) 3. Sn2+ (aq) + O2 (g)  Sn4+ (aq) + H2O (l) (in acid) 2 Sn2+ (aq) + O2 (g) + 4 H+ (aq)  2 Sn4+ (aq) + 2 H2O (l) 4. H2O2 (aq) + Cr2O72— (aq)  Cr3+ (aq) + O2 (aq) (in acid) 3 H2O2 (aq) + Cr2O72— (aq) + 8 H+ (aq)  2 Cr3+ (aq) + 3 O2 (aq) + 7 H2O (l) 5. NO2— (aq) + Br2 (aq)  NO3— (aq) + Br— (aq) (in base) NO2— (aq) + Br2 (aq) + 2 OH— (aq)  NO3— (aq) + 2 Br— (aq) + H2O (l) 6. MnO4— (aq) + NH3 (aq)  MnO2 (s) + N2 (g) (in base) 2 MnO4— (aq) + 2 NH3 (aq)  2 MnO2 (s) + N2 (g) + 2 H2O (l) + 2 OH— (aq) 7. Al (s) + Cu2+ (aq)  Al3+ (aq) + Cu (s) (in acid) 2 Al (s) + 3 Cu2+ (aq)  2 Al3+ (aq) + 3 Cu (s) 8. Sn (s) + O2 (g)  Sn2+ (aq) + H2O (l) (in acid) 2 Sn (s) + O2 (g) + 4 H+ (aq)  2 Sn2+ (aq) + 2 H2O (l) 9. MnO4— (aq) + Mn2+ (aq)  MnO2 (s) (in acid) 2 MnO4— (aq) + 3 Mn2+ (aq) + 2 H2O (l)  5 MnO2 (s) + 4 H+ (aq) 10. Cl2 (g)  Cl— (aq) + ClO3— (aq) (in acid) 6 Cl2 (g) + 6 H2O (l)  10 Cl— (aq) + 2 ClO3— (aq) + 12 H+ (aq) ---OR--3 Cl2 (g) + 3 H2O (l)  5 Cl— (aq) + ClO3— (aq) + 6 H+ (aq) 11. PtCl42— (aq) + Cu+ (aq)  Pt (s) + Cu2+ (aq) (in acid) PtCl4— (aq) + 2 Cu+ (aq)  Pt (s) + 2 Cu2+ (aq) + 4 Cl— (aq) 12. AgBr (s) + CO2 (g)  H2C2O4 (aq) + Br2 (in acid) 2 AgBr (s) + 2 CO2 (g) + 2 H+ (aq)  2 Ag+ (aq) + H2C2O4 (aq) + Br2 (aq)...