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BODMAS answers...

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BODMAS 1. Brackets 2. Orders (i.e. Powers and Square Roots, etc.; exponents) 3. Division & Multiplication (left-to-right) 4. Addition & Subtraction (left-to-right)

Addition & Subtraction (AS) (left-to-right) •

1–2+3=2

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4 + 8 – 2 + 5 = 15

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10 + 14 – 22 = 2

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32.5 – 1.5 + 16.8 = 47.8

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1.26 + 5.31 – 4.15 = 2.42

Division & Multiplication (DM) (left-to-right) •

4 x 3 ÷3 = 4

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2÷1x3=6

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25 x 4 x 2 ÷5 = 40

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12 ÷ 4 x 6 ÷ 2 = 9

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1.2 x 5 x 6.5 ÷ 3 ÷ 10 = 1.3

Division, Multiplication, Addition & Subtraction (DMAS) •

5 – 6 + 4 x 7 = 27

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10 ÷ 5 – 2 + 4 = 4

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9–2x2–3=2

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12 ÷ 2 x 6 – 5 = 31

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8 ÷ 4 – 8 + 5 x 9 = 39

Orders, Division, Multiplication, Addition & Subtraction (ODMAS) Before you do any parts of the sum involving Divisions, Multiplications, Additions or Subtractions (DMAS), perform the Orders first Orders = anything involving a power or a square root •

42 = 16

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√ 36 = 6

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√9 = 3

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52 = 25

Orders, Division, Multiplication, Addition & Subtraction (ODMAS) If an Order contains a sum within itself, simply it first according to the rules of DMAS •

√ 1+ 3+ 5 = √9 = 3

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√ 70−10 + 4 = √64 = 8

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√ 2 X 8 X 9 = √144 = 12

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√ 64−10÷ 2−10 = √49 = 7

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√ 9 X 10÷2+4 = √49 = 7

Orders, Division, Multiplication, Addition & Subtraction (ODMAS) •

2 × 32 - 8 = 10

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√ 9 – 22 = -1

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√ 1+3 X 5+7 = √16 + 7 = 11

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82 ÷ 4 2 + 10 x 2 = 24

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4x

√ 64−10÷ 2−10 + 3 = 4 x √49 + 3 = 31

Brackets, Orders, Division, Multiplication, Addition & Subtraction (BODMAS) In any given sum, start with anything inside Brackets. •

7 x (4 + 8) = 84

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63 ÷ (17 – 8) = 7

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8 + (7 – 6) x 4 = 12

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(8 – 4) + (24 ÷ 2) = 16

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(8 – 4) + (24 ÷ 2) x (27 – 17) = 124

Brackets, Orders, Division, Multiplication, Addition & Subtraction (BODMAS) “Sub-sums” contained within Brackets are worked out according to rules of ODMAS •

2 x (4 x 3 + 8) = 40

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30 – (20 – 8 ÷ 2) = 14

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8 + (42 ÷ 6 – 3 x 2) x 4 = 12

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(10 – 4 + 2 ÷ 2) - (26 – 24 ÷ 2) = 7

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(8 ÷ 4) x (31 – 3 x 10) x (12 ÷ 2 - 5) = 2

Brackets, Orders, Division, Multiplication, Addition & Subtraction (BODMAS) •

7 + (6 × 52 + 3) = 160

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√ 4+(19−7)

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√ 1+ 3 x 5 – (4+ 2) – 3 = √16 – 6 – 3 = -5

– (3 + 2) = √16 – 5 = -1

√ 36  + 3) = 21

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36 ÷ 3 +

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42 – (64 ÷ 8 - 5) 2 + 2 = 10

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Dealing with positive and negative integers •

-10 + 3 = -7

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4 + +4 = 8

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-20 – -17 = -3

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-6 + -3 = -9

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-25 – (-15) = -10

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5 + (-2) = 3...